如何获得方法的执行时间? 是否有Timer实用程序类来计时任务所需的时间等?

在谷歌上的大多数搜索都返回调度线程和任务的计时器的结果,这不是我想要的。


当前回答

也可以实现定时器接口,并在类的任何方法上执行

import java.util.function.*;

public interface Timer {

    default void timeIt(Runnable r) {
        timeIt(() -> { r.run(); return 0;});
    }

    default <S,T> T timeIt(Function<S,T> fun, S arg) {
        long start = System.nanoTime();
        T result = fun.apply(arg);
        long stop = System.nanoTime();
        System.out.println("Time: " + (stop-start)/1000000.0 + " msec");
        return result;
    }

    default <T> T timeIt(Supplier<T> s) {
        return timeIt(obj -> s.get(), null);
    }
}

用法:

class MyClass implements Timer ..

timeIt(this::myFunction); 

其他回答

Spring提供了一个实用工具类org.springframework.util。秒表,根据JavaDoc:

简单的秒表,允许计时多项任务,暴露 每个指定任务的总运行时间和运行时间。

用法:

StopWatch stopWatch = new StopWatch("Performance Test Result");

stopWatch.start("Method 1");
doSomething1();//method to test
stopWatch.stop();

stopWatch.start("Method 2");
doSomething2();//method to test
stopWatch.stop();

System.out.println(stopWatch.prettyPrint());

输出:

StopWatch 'Performance Test Result': running time (millis) = 12829
-----------------------------------------
ms     %     Task name
-----------------------------------------
11907  036%  Method 1
00922  064%  Method 2

方面:

@Around("execution(* my.package..*.*(..))")
public Object logTime(ProceedingJoinPoint joinPoint) throws Throwable {
    StopWatch stopWatch = new StopWatch();
    stopWatch.start();
    Object retVal = joinPoint.proceed();
    stopWatch.stop();
    log.info(" execution time: " + stopWatch.getTotalTimeMillis() + " ms");
    return retVal;
}

非常好的代码。

http://www.rgagnon.com/javadetails/java-0585.html

import java.util.concurrent.TimeUnit;

long startTime = System.currentTimeMillis();
........
........
........
long finishTime = System.currentTimeMillis();

String diff = millisToShortDHMS(finishTime - startTime);


  /**
   * converts time (in milliseconds) to human-readable format
   *  "<dd:>hh:mm:ss"
   */
  public static String millisToShortDHMS(long duration) {
    String res = "";
    long days  = TimeUnit.MILLISECONDS.toDays(duration);
    long hours = TimeUnit.MILLISECONDS.toHours(duration)
                   - TimeUnit.DAYS.toHours(TimeUnit.MILLISECONDS.toDays(duration));
    long minutes = TimeUnit.MILLISECONDS.toMinutes(duration)
                     - TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(duration));
    long seconds = TimeUnit.MILLISECONDS.toSeconds(duration)
                   - TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(duration));
    if (days == 0) {
      res = String.format("%02d:%02d:%02d", hours, minutes, seconds);
    }
    else {
      res = String.format("%dd%02d:%02d:%02d", days, hours, minutes, seconds);
    }
    return res;
  }

我实现了一个简单的定时器,我认为它真的很有用:

public class Timer{
    private static long start_time;

    public static double tic(){
        return start_time = System.nanoTime();
    }

    public static double toc(){
        return (System.nanoTime()-start_time)/1000000000.0;
    }

}

这样你就可以计算一个或多个动作的时间:

Timer.tic();
// Code 1
System.out.println("Code 1 runtime: "+Timer.toc()+" seconds.");
// Code 2
System.out.println("(Code 1 + Code 2) runtime: "+Timer.toc()+"seconds");
Timer.tic();
// Code 3
System.out.println("Code 3 runtime: "+Timer.toc()+" seconds.");

总有一些过时的方法:

long startTime = System.nanoTime();
methodToTime();
long endTime = System.nanoTime();

long duration = (endTime - startTime);  //divide by 1000000 to get milliseconds.

如果java有更好的功能支持就好了,这样需要测量的动作就可以被包装到一个块中:

measure {
   // your operation here
}

在java中,这可以通过匿名函数来完成,看起来太冗长了

public interface Timer {
    void wrap();
}


public class Logger {

    public static void logTime(Timer timer) {
        long start = System.currentTimeMillis();
        timer.wrap();
        System.out.println("" + (System.currentTimeMillis() - start) + "ms");
    }

    public static void main(String a[]) {
        Logger.logTime(new Timer() {
            public void wrap() {
                // Your method here
                timeConsumingOperation();
            }
        });

    }

    public static void timeConsumingOperation() {
        for (int i = 0; i<=10000; i++) {
           System.out.println("i=" +i);
        }
    }
}