如何获得方法的执行时间? 是否有Timer实用程序类来计时任务所需的时间等?
在谷歌上的大多数搜索都返回调度线程和任务的计时器的结果,这不是我想要的。
如何获得方法的执行时间? 是否有Timer实用程序类来计时任务所需的时间等?
在谷歌上的大多数搜索都返回调度线程和任务的计时器的结果,这不是我想要的。
当前回答
也可以实现定时器接口,并在类的任何方法上执行
import java.util.function.*;
public interface Timer {
default void timeIt(Runnable r) {
timeIt(() -> { r.run(); return 0;});
}
default <S,T> T timeIt(Function<S,T> fun, S arg) {
long start = System.nanoTime();
T result = fun.apply(arg);
long stop = System.nanoTime();
System.out.println("Time: " + (stop-start)/1000000.0 + " msec");
return result;
}
default <T> T timeIt(Supplier<T> s) {
return timeIt(obj -> s.get(), null);
}
}
用法:
class MyClass implements Timer ..
timeIt(this::myFunction);
其他回答
Spring提供了一个实用工具类org.springframework.util。秒表,根据JavaDoc:
简单的秒表,允许计时多项任务,暴露 每个指定任务的总运行时间和运行时间。
用法:
StopWatch stopWatch = new StopWatch("Performance Test Result");
stopWatch.start("Method 1");
doSomething1();//method to test
stopWatch.stop();
stopWatch.start("Method 2");
doSomething2();//method to test
stopWatch.stop();
System.out.println(stopWatch.prettyPrint());
输出:
StopWatch 'Performance Test Result': running time (millis) = 12829
-----------------------------------------
ms % Task name
-----------------------------------------
11907 036% Method 1
00922 064% Method 2
方面:
@Around("execution(* my.package..*.*(..))")
public Object logTime(ProceedingJoinPoint joinPoint) throws Throwable {
StopWatch stopWatch = new StopWatch();
stopWatch.start();
Object retVal = joinPoint.proceed();
stopWatch.stop();
log.info(" execution time: " + stopWatch.getTotalTimeMillis() + " ms");
return retVal;
}
非常好的代码。
http://www.rgagnon.com/javadetails/java-0585.html
import java.util.concurrent.TimeUnit;
long startTime = System.currentTimeMillis();
........
........
........
long finishTime = System.currentTimeMillis();
String diff = millisToShortDHMS(finishTime - startTime);
/**
* converts time (in milliseconds) to human-readable format
* "<dd:>hh:mm:ss"
*/
public static String millisToShortDHMS(long duration) {
String res = "";
long days = TimeUnit.MILLISECONDS.toDays(duration);
long hours = TimeUnit.MILLISECONDS.toHours(duration)
- TimeUnit.DAYS.toHours(TimeUnit.MILLISECONDS.toDays(duration));
long minutes = TimeUnit.MILLISECONDS.toMinutes(duration)
- TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(duration));
long seconds = TimeUnit.MILLISECONDS.toSeconds(duration)
- TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(duration));
if (days == 0) {
res = String.format("%02d:%02d:%02d", hours, minutes, seconds);
}
else {
res = String.format("%dd%02d:%02d:%02d", days, hours, minutes, seconds);
}
return res;
}
我实现了一个简单的定时器,我认为它真的很有用:
public class Timer{
private static long start_time;
public static double tic(){
return start_time = System.nanoTime();
}
public static double toc(){
return (System.nanoTime()-start_time)/1000000000.0;
}
}
这样你就可以计算一个或多个动作的时间:
Timer.tic();
// Code 1
System.out.println("Code 1 runtime: "+Timer.toc()+" seconds.");
// Code 2
System.out.println("(Code 1 + Code 2) runtime: "+Timer.toc()+"seconds");
Timer.tic();
// Code 3
System.out.println("Code 3 runtime: "+Timer.toc()+" seconds.");
总有一些过时的方法:
long startTime = System.nanoTime();
methodToTime();
long endTime = System.nanoTime();
long duration = (endTime - startTime); //divide by 1000000 to get milliseconds.
如果java有更好的功能支持就好了,这样需要测量的动作就可以被包装到一个块中:
measure {
// your operation here
}
在java中,这可以通过匿名函数来完成,看起来太冗长了
public interface Timer {
void wrap();
}
public class Logger {
public static void logTime(Timer timer) {
long start = System.currentTimeMillis();
timer.wrap();
System.out.println("" + (System.currentTimeMillis() - start) + "ms");
}
public static void main(String a[]) {
Logger.logTime(new Timer() {
public void wrap() {
// Your method here
timeConsumingOperation();
}
});
}
public static void timeConsumingOperation() {
for (int i = 0; i<=10000; i++) {
System.out.println("i=" +i);
}
}
}