如何获得方法的执行时间? 是否有Timer实用程序类来计时任务所需的时间等?
在谷歌上的大多数搜索都返回调度线程和任务的计时器的结果,这不是我想要的。
如何获得方法的执行时间? 是否有Timer实用程序类来计时任务所需的时间等?
在谷歌上的大多数搜索都返回调度线程和任务的计时器的结果,这不是我想要的。
当前回答
我实现了一个简单的定时器,我认为它真的很有用:
public class Timer{
private static long start_time;
public static double tic(){
return start_time = System.nanoTime();
}
public static double toc(){
return (System.nanoTime()-start_time)/1000000000.0;
}
}
这样你就可以计算一个或多个动作的时间:
Timer.tic();
// Code 1
System.out.println("Code 1 runtime: "+Timer.toc()+" seconds.");
// Code 2
System.out.println("(Code 1 + Code 2) runtime: "+Timer.toc()+"seconds");
Timer.tic();
// Code 3
System.out.println("Code 3 runtime: "+Timer.toc()+" seconds.");
其他回答
如果你想要时间
long start_time = System.currentTimeMillis();
object.method();
long end_time = System.currentTimeMillis();
long execution_time = end_time - start_time;
使用Java 8的新API中的即时和持续时间,
Instant start = Instant.now();
Thread.sleep(5000);
Instant end = Instant.now();
System.out.println(Duration.between(start, end));
输出,
PT5S
也可以实现定时器接口,并在类的任何方法上执行
import java.util.function.*;
public interface Timer {
default void timeIt(Runnable r) {
timeIt(() -> { r.run(); return 0;});
}
default <S,T> T timeIt(Function<S,T> fun, S arg) {
long start = System.nanoTime();
T result = fun.apply(arg);
long stop = System.nanoTime();
System.out.println("Time: " + (stop-start)/1000000.0 + " msec");
return result;
}
default <T> T timeIt(Supplier<T> s) {
return timeIt(obj -> s.get(), null);
}
}
用法:
class MyClass implements Timer ..
timeIt(this::myFunction);
在Java 8中引入了一个名为Instant的新类。根据文件:
Instant represents the start of a nanosecond on the time line. This class is useful for generating a time stamp to represent machine time. The range of an instant requires the storage of a number larger than a long. To achieve this, the class stores a long representing epoch-seconds and an int representing nanosecond-of-second, which will always be between 0 and 999,999,999. The epoch-seconds are measured from the standard Java epoch of 1970-01-01T00:00:00Z where instants after the epoch have positive values, and earlier instants have negative values. For both the epoch-second and nanosecond parts, a larger value is always later on the time-line than a smaller value.
这可以用于:
Instant start = Instant.now();
try {
Thread.sleep(7000);
} catch (InterruptedException e) {
e.printStackTrace();
}
Instant end = Instant.now();
System.out.println(Duration.between(start, end));
打印pt7.001。
这里有很多有效的答案,它们都是在方法中实现的。为了制作一个通用的计时方法,我通常有一个timing类,它由以下内容组成。
public record TimedResult<T>(T result, Duration duration) {}
public static Duration time(Runnable r) {
var s = Instant.now();
r.run();
var dur = Duration.between(s, Instant.now());
return dur;
}
public static <T> TimedResult<T> time(Callable<T> r) throws Exception {
var s = Instant.now();
T res = r.call();
var dur = Duration.between(s, Instant.now());
return new TimedResult<>(res, dur);
}
这足够通用,可以传递Runnable或Callable对象。
Duration result = Timing.time(() -> {
// do some work.
});
TimedResult<String> result = Timing.time(() -> {
// do some work.
return "answer";
});
Duration timeTaken = result.duration();
String answer = result.result();