如何获得方法的执行时间? 是否有Timer实用程序类来计时任务所需的时间等?

在谷歌上的大多数搜索都返回调度线程和任务的计时器的结果,这不是我想要的。


当前回答

您可以使用Metrics库,它提供了各种测量工具。添加依赖关系:

<dependencies>
    <dependency>
        <groupId>io.dropwizard.metrics</groupId>
        <artifactId>metrics-core</artifactId>
        <version>${metrics.version}</version>
    </dependency>
</dependencies>

并为您的环境配置它。

方法可以用@Timed进行注释:

@Timed
public void exampleMethod(){
    // some code
}

或者用Timer包装的一段代码:

final Timer timer = metricsRegistry.timer("some_name");
final Timer.Context context = timer.time();
// timed code
context.stop();

聚合的指标可以导出到控制台、JMX、CSV或其他。

@定时指标输出示例:

com.example.ExampleService.exampleMethod
             count = 2
         mean rate = 3.11 calls/minute
     1-minute rate = 0.96 calls/minute
     5-minute rate = 0.20 calls/minute
    15-minute rate = 0.07 calls/minute
               min = 17.01 milliseconds
               max = 1006.68 milliseconds
              mean = 511.84 milliseconds
            stddev = 699.80 milliseconds
            median = 511.84 milliseconds
              75% <= 1006.68 milliseconds
              95% <= 1006.68 milliseconds
              98% <= 1006.68 milliseconds
              99% <= 1006.68 milliseconds
            99.9% <= 1006.68 milliseconds

其他回答

总有一些过时的方法:

long startTime = System.nanoTime();
methodToTime();
long endTime = System.nanoTime();

long duration = (endTime - startTime);  //divide by 1000000 to get milliseconds.

我的答案很简单。对我有用。

long startTime = System.currentTimeMillis();

doReallyLongThing();

long endTime = System.currentTimeMillis();

System.out.println("That took " + (endTime - startTime) + " milliseconds");

它运行得很好。分辨率显然只有毫秒级,使用System.nanoTime()可以做得更好。这两种方法都有一些限制(操作系统调度切片等),但效果很好。

平均几次运行(越多越好),你就会得到一个不错的想法。

我已经编写了一个方法,以易于阅读的形式打印方法执行时间。 例如,要计算100万的阶乘,大约需要9分钟。因此,执行时间打印为:

Execution Time: 9 Minutes, 36 Seconds, 237 MicroSeconds, 806193 NanoSeconds

代码在这里:

public class series
{
    public static void main(String[] args)
    {
        long startTime = System.nanoTime();

        long n = 10_00_000;
        printFactorial(n);

        long endTime = System.nanoTime();
        printExecutionTime(startTime, endTime);

    }

    public static void printExecutionTime(long startTime, long endTime)
    {
        long time_ns = endTime - startTime;
        long time_ms = TimeUnit.NANOSECONDS.toMillis(time_ns);
        long time_sec = TimeUnit.NANOSECONDS.toSeconds(time_ns);
        long time_min = TimeUnit.NANOSECONDS.toMinutes(time_ns);
        long time_hour = TimeUnit.NANOSECONDS.toHours(time_ns);

        System.out.print("\nExecution Time: ");
        if(time_hour > 0)
            System.out.print(time_hour + " Hours, ");
        if(time_min > 0)
            System.out.print(time_min % 60 + " Minutes, ");
        if(time_sec > 0)
            System.out.print(time_sec % 60 + " Seconds, ");
        if(time_ms > 0)
            System.out.print(time_ms % 1E+3 + " MicroSeconds, ");
        if(time_ns > 0)
            System.out.print(time_ns % 1E+6 + " NanoSeconds");
    }
}

为此,我们使用了AspectJ和Java注释。如果我们需要知道一个方法的执行时间,我们可以简单地注释它。更高级的版本可以使用自己的日志级别,可以在运行时启用和禁用。

public @interface Trace {
  boolean showParameters();
}

@Aspect
public class TraceAspect {
  [...]
  @Around("tracePointcut() && @annotation(trace) && !within(TraceAspect)")
  public Object traceAdvice ( ProceedingJintPoint jP, Trace trace ) {

    Object result;
    // initilize timer

    try { 
      result = jp.procced();
    } finally { 
      // calculate execution time 
    }

    return result;
  }
  [...]
}

在Java 8中引入了一个名为Instant的新类。根据文件:

Instant represents the start of a nanosecond on the time line. This class is useful for generating a time stamp to represent machine time. The range of an instant requires the storage of a number larger than a long. To achieve this, the class stores a long representing epoch-seconds and an int representing nanosecond-of-second, which will always be between 0 and 999,999,999. The epoch-seconds are measured from the standard Java epoch of 1970-01-01T00:00:00Z where instants after the epoch have positive values, and earlier instants have negative values. For both the epoch-second and nanosecond parts, a larger value is always later on the time-line than a smaller value.

这可以用于:

Instant start = Instant.now();
try {
    Thread.sleep(7000);
} catch (InterruptedException e) {
    e.printStackTrace();
}
Instant end = Instant.now();
System.out.println(Duration.between(start, end));

打印pt7.001。