我一直在努力创建一个UIAlertView在Swift,但由于某种原因,我不能得到正确的声明,因为我得到这个错误:

无法找到一个超载的'init'接受提供的 参数

我是这样写的:

let button2Alert: UIAlertView = UIAlertView(title: "Title", message: "message",
                     delegate: self, cancelButtonTitle: "OK", otherButtonTitles: nil)

然后我使用:

button2Alert.show()

到目前为止,它正在崩溃,我只是不能得到正确的语法。


当前回答

// UIAlertView的自定义类

//MARK:- MODULES
import Foundation
import UIKit

//MARK:- CLASS
class Alert  : NSObject{

static let shared = Alert()

var okAction : AlertSuccess?
typealias AlertSuccess = (()->())?
var alert: UIAlertController?

/** show */
public func show(title : String?, message : String?, viewController : UIViewController?, okAction : AlertSuccess = nil) {

    let version : NSString = UIDevice.current.systemVersion as NSString
    if  version.doubleValue >= 8 {
        alert = UIAlertController(title: title, message: message, preferredStyle:.alert)
        alert?.addAction(UIAlertAction(title: "OK", style: .default, handler: { (action: UIAlertAction) in

            if let okAction = okAction {
                okAction()
            }
        }))
        viewController?.present(alert ?? UIAlertController(), animated:true, completion:nil);
    }
}

/** showWithCancelAndOk */
public func showWithCancelAndOk(title : String, okTitle : String, cancelTitle : String, message : String, viewController : UIViewController?, okAction : AlertSuccess = nil, cancelAction : AlertSuccess = nil) {
    let version:NSString = UIDevice.current.systemVersion as NSString;

    if  version.doubleValue >= 8 {
        alert = UIAlertController(title: title, message: message, preferredStyle:.alert)

        alert?.addAction(UIAlertAction(title: cancelTitle, style: .default, handler: { (action: UIAlertAction) in

            if let cancelAction = cancelAction {
                cancelAction()
            }
        }))
        alert?.addAction(UIAlertAction(title: okTitle, style: .default, handler: { (action: UIAlertAction) in

            if let okAction = okAction {
                okAction()
            }
        }))
        viewController?.present(alert!, animated:true, completion:nil);
    }
}

/** showWithTimer */
public func showWithTimer(message : String?, viewController : UIViewController?) {

    let version : NSString = UIDevice.current.systemVersion as NSString
    if  version.doubleValue >= 8 {
        alert = UIAlertController(title: "", message: message, preferredStyle:.alert)
        viewController?.present(alert ?? UIAlertController(), animated:true, completion:nil)
        let when = DispatchTime.now() + 1
        DispatchQueue.main.asyncAfter(deadline: when){
            self.alert?.dismiss(animated: true, completion: nil)
        }
    }
}
}

使用:

Alert.shared.show(title: "No Internet Connection", message: "The internet connection appers to be offline.", viewController: self) //without ok action

Alert.shared.show(title: "No Internet Connection", message: "The internet connection appers to be offline.", viewController: self, okAction: {
                            //ok action
                        }) // with ok action

Alert.shared.show(title: "No Internet Connection", message: "The internet connection appers to be offline.", viewController: self, okAction: {
                            //ok action 
}, cancelAction: {
 //cancel action
}) //with cancel and ok action

Alert.shared.showWithTimer(message : "This is an alert with timer", viewController : self) //with timer

其他回答

我找到了这个,

var alertView = UIAlertView();
alertView.addButtonWithTitle("Ok");
alertView.title = "title";
alertView.message = "message";
alertView.show();

虽然不是很好,但它有效:)

更新:

但我在头文件上发现为:

extension UIAlertView {
    convenience init(title: String, message: String, delegate: UIAlertViewDelegate?, cancelButtonTitle: String?, otherButtonTitles firstButtonTitle: String, _ moreButtonTitles: String...)
}

也许有人能解释一下。

你可以使用标准的构造函数创建一个UIAlert,但是“遗留的”构造函数似乎不起作用:

let alert = UIAlertView()
alert.title = "Alert"
alert.message = "Here's a message"
alert.addButtonWithTitle("Understood")
alert.show()

通过Swift 2的协议扩展,你可以创建一个为视图控制器提供默认实现的协议:

ShowsAlert.swift

import UIKit

protocol ShowsAlert {}

extension ShowsAlert where Self: UIViewController {
    func showAlert(title: String = "Error", message: String) {
        let alertController = UIAlertController(title: title, message: message, preferredStyle: .Alert)
        alertController.addAction(UIAlertAction(title: "Ok", style: .Default, handler: nil))
        presentViewController(alertController, animated: true, completion: nil)
    }
}

ViewController.swift

class ViewController: UIViewController, ShowsAlert {
    override func viewDidLoad() {
        super.viewDidLoad()
        showAlert(message: "Hey there, I am an error message!")
    }
}

斯威夫特3

下面是一个简单的例子,如何用Swift 3一个按钮创建一个简单的警报。

let alert = UIAlertController(title: "Title",
                              message: "Message",
                              preferredStyle: .alert)
alert.addAction(UIAlertAction(title: "Ok", style: .default))
present(alert, animated: true)

在上面的例子中,动作的句柄回调被省略了,因为带有一个按钮的警报视图的默认行为是在单击按钮时消失。

下面是如何创建另一个动作,可以用"alert. addaction (action)"添加到警报中。不同的样式是.default, .destructive和.cancel。

let action = UIAlertAction(title: "Ok", style: .default) { action in
    // Handle when button is clicked    
}

在xcode 9中

let alert = UIAlertController(title: "Alert", message: "message", preferredStyle: UIAlertControllerStyle.alert)
alert.addAction(UIAlertAction(title: "Ok", style: UIAlertActionStyle.default, handler: nil))
self.present(alert, animated: true, completion: nil)