我一直在努力创建一个UIAlertView在Swift，但由于某种原因，我不能得到正确的声明，因为我得到这个错误:
无法找到一个超载的'init'接受提供的 参数
我是这样写的:
let button2Alert: UIAlertView = UIAlertView(title: "Title", message: "message",
delegate: self, cancelButtonTitle: "OK", otherButtonTitles: nil)
然后我使用:
button2Alert.show()
到目前为止，它正在崩溃，我只是不能得到正确的语法。
当前回答
斯威夫特有一个有趣的例子:
private func presentRandomJoke() {
if let randomJoke: String = jokesController.randomJoke() {
let alertController: UIAlertController = UIAlertController(title:nil, message:randomJoke, preferredStyle: UIAlertControllerStyle.Alert)
alertController.addAction(UIAlertAction(title:"Done", style:UIAlertActionStyle.Default, handler:nil))
presentViewController(alertController, animated:true, completion:nil)
}
}
其他回答
// UIAlertView is deprecated. Use UIAlertController
// title = title of the alert view.
// message = Alert message you want to show.
// By tap on "OK" , Alert view will dismiss.
UIAlertView(title: "Alert", message: "Enter Message here.", delegate: nil, cancelButtonTitle: "OK").show()
斯威夫特有一个有趣的例子:
private func presentRandomJoke() {
if let randomJoke: String = jokesController.randomJoke() {
let alertController: UIAlertController = UIAlertController(title:nil, message:randomJoke, preferredStyle: UIAlertControllerStyle.Alert)
alertController.addAction(UIAlertAction(title:"Done", style:UIAlertActionStyle.Default, handler:nil))
presentViewController(alertController, animated:true, completion:nil)
}
}
通过Swift 2的协议扩展，你可以创建一个为视图控制器提供默认实现的协议:
ShowsAlert.swift
import UIKit
protocol ShowsAlert {}
extension ShowsAlert where Self: UIViewController {
func showAlert(title: String = "Error", message: String) {
let alertController = UIAlertController(title: title, message: message, preferredStyle: .Alert)
alertController.addAction(UIAlertAction(title: "Ok", style: .Default, handler: nil))
presentViewController(alertController, animated: true, completion: nil)
}
}
ViewController.swift
class ViewController: UIViewController, ShowsAlert {
override func viewDidLoad() {
super.viewDidLoad()
showAlert(message: "Hey there, I am an error message!")
}
}
适用于13.0以上版本 使用SceneDelegate
适用于所有类型的课程
static func showWindowAlert(alertMessage: String, inVC:UIViewController) {
DispatchQueue.main.async(execute: {
guard let windowScene = UIApplication.shared.connectedScenes.first as? UIWindowScene,
let sceneDelegate = windowScene.delegate as? SceneDelegate
else {
return
}
sceneDelegate.window?.rootViewController = inVC
sceneDelegate.window?.windowLevel = UIWindow.Level.alert + 1
let alert2 = UIAlertController(title: App_Name, message: alertMessage, preferredStyle: .alert)
let defaultAction2 = UIAlertAction(title: "OK", style: .default, handler: { action in
})
alert2.addAction(defaultAction2)
sceneDelegate.window?.makeKeyAndVisible()
sceneDelegate.window?.rootViewController?.present(alert2, animated: true, completion: nil)
})
}
你可以使用这个简单的扩展与n个按钮和相关的动作swift4以上
extension UIViewController {
func popupAlert(title: String?, message: String?, actionTitles:[String?], actions:[((UIAlertAction) -> Void)?]) {
let alert = UIAlertController(title: title, message: message, preferredStyle: .alert)
for (index, title) in actionTitles.enumerated() {
let action = UIAlertAction(title: title, style: .default, handler: actions[index])
alert.addAction(action)
}
self.present(alert, animated: true, completion: nil)
}
}
你可以这样使用它，
self.popupAlert(title: "Message", message: "your message", actionTitles: ["first","second","third"], actions:[
{action1 in
//action for first btn click
},
{action2 in
//action for second btn click
},
{action3 in
//action for third btn click
}, nil])
