我想知道是否有一个已知的,内置/优雅的方法来找到一个JS数组的第一个元素匹配给定的条件。c#的等效程序是List.Find。

到目前为止,我一直在使用这样的双功能组合:

// Returns the first element of an array that satisfies given predicate
Array.prototype.findFirst = function (predicateCallback) {
    if (typeof predicateCallback !== 'function') {
        return undefined;
    }

    for (var i = 0; i < arr.length; i++) {
        if (i in this && predicateCallback(this[i])) return this[i];
    }

    return undefined;
};

// Check if element is not undefined && not null
isNotNullNorUndefined = function (o) {
    return (typeof (o) !== 'undefined' && o !== null);
};

然后我可以用:

var result = someArray.findFirst(isNotNullNorUndefined);

但既然ECMAScript中有这么多函数风格的数组方法,也许已经有这样的东西了?我想很多人都必须实现这样的东西……


当前回答

从ECMAScript 6开始,你可以使用Array.prototype.find。这可以在Firefox(25.0)、Chrome(45.0)、Edge(12)和Safari(7.1)中实现,但不能在Internet Explorer或其他一堆旧的或不常见的平台上实现。

例如,下面的x为106:

Const x =[100,101,102,103,104,105,106,107,108,109]。Find (function (el) { 返回el > 105; }); console.log (x);

If you want to use this right now but need support for IE or other unsupporting browsers, you can use a shim. I recommend the es6-shim. MDN also offers a shim if for some reason you don't want to put the whole es6-shim into your project. For maximum compatibility you want the es6-shim, because unlike the MDN version it detects buggy native implementations of find and overwrites them (see the comment that begins "Work around bugs in Array#find and Array#findIndex" and the lines immediately following it).

其他回答

Javascript中没有内置函数来执行此搜索。

如果你正在使用jQuery,你可以做一个jQuery. inarray(元素,数组)。

Array.prototype.find()就是这样做的,更多信息:https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/find

使用过滤器并从结果数组中获得第一个索引如何?

var result = someArray.filter(isNotNullNorUndefined)[0];
foundElement = myArray[myArray.findIndex(element => //condition here)];

从ES 2015开始,Array.prototype.find()就提供了这个确切的功能。

对于不支持此功能的浏览器,Mozilla开发者网络提供了一个填充(粘贴在下面):

if (!Array.prototype.find) {
  Array.prototype.find = function(predicate) {
    if (this === null) {
      throw new TypeError('Array.prototype.find called on null or undefined');
    }
    if (typeof predicate !== 'function') {
      throw new TypeError('predicate must be a function');
    }
    var list = Object(this);
    var length = list.length >>> 0;
    var thisArg = arguments[1];
    var value;

    for (var i = 0; i < length; i++) {
      value = list[i];
      if (predicate.call(thisArg, value, i, list)) {
        return value;
      }
    }
    return undefined;
  };
}