我有一个这样的字符串:
abc=foo&def=%5Basf%5D&xyz=5
如何将其转换为这样的JavaScript对象?
{
abc: 'foo',
def: '[asf]',
xyz: 5
}
当前回答
这似乎是最好的解决方案，因为它考虑了同名的多个参数。
function paramsToJSON(str) {
var pairs = str.split('&');
var result = {};
pairs.forEach(function(pair) {
pair = pair.split('=');
var name = pair[0]
var value = pair[1]
if( name.length )
if (result[name] !== undefined) {
if (!result[name].push) {
result[name] = [result[name]];
}
result[name].push(value || '');
} else {
result[name] = value || '';
}
});
return( result );
}
<a href="index.html?x=1&x=2&x=3&y=blah">something</a>
paramsToJSON("x=1&x=2&x=3&y=blah");
console yields => {x: Array[3], y: "blah"} where x is an array as is proper JSON
后来我决定把它转换成一个jQuery插件…
$.fn.serializeURLParams = function() {
var result = {};
if( !this.is("a") || this.attr("href").indexOf("?") == -1 )
return( result );
var pairs = this.attr("href").split("?")[1].split('&');
pairs.forEach(function(pair) {
pair = pair.split('=');
var name = decodeURI(pair[0])
var value = decodeURI(pair[1])
if( name.length )
if (result[name] !== undefined) {
if (!result[name].push) {
result[name] = [result[name]];
}
result[name].push(value || '');
} else {
result[name] = value || '';
}
});
return( result )
}
<a href="index.html?x=1&x=2&x=3&y=blah">something</a>
$("a").serializeURLParams();
console yields => {x: Array[3], y: "blah"} where x is an array as is proper JSON
现在，第一个将只接受参数，但jQuery插件将接受整个url并返回序列化的参数。
其他回答
这似乎是最好的解决方案，因为它考虑了同名的多个参数。
function paramsToJSON(str) {
var pairs = str.split('&');
var result = {};
pairs.forEach(function(pair) {
pair = pair.split('=');
var name = pair[0]
var value = pair[1]
if( name.length )
if (result[name] !== undefined) {
if (!result[name].push) {
result[name] = [result[name]];
}
result[name].push(value || '');
} else {
result[name] = value || '';
}
});
return( result );
}
<a href="index.html?x=1&x=2&x=3&y=blah">something</a>
paramsToJSON("x=1&x=2&x=3&y=blah");
console yields => {x: Array[3], y: "blah"} where x is an array as is proper JSON
后来我决定把它转换成一个jQuery插件…
$.fn.serializeURLParams = function() {
var result = {};
if( !this.is("a") || this.attr("href").indexOf("?") == -1 )
return( result );
var pairs = this.attr("href").split("?")[1].split('&');
pairs.forEach(function(pair) {
pair = pair.split('=');
var name = decodeURI(pair[0])
var value = decodeURI(pair[1])
if( name.length )
if (result[name] !== undefined) {
if (!result[name].push) {
result[name] = [result[name]];
}
result[name].push(value || '');
} else {
result[name] = value || '';
}
});
return( result )
}
<a href="index.html?x=1&x=2&x=3&y=blah">something</a>
$("a").serializeURLParams();
console yields => {x: Array[3], y: "blah"} where x is an array as is proper JSON
现在，第一个将只接受参数，但jQuery插件将接受整个url并返回序列化的参数。
//under ES6
const getUrlParamAsObject = (url = window.location.href) => {
let searchParams = url.split('?')[1];
const result = {};
//in case the queryString is empty
if (searchParams!==undefined) {
const paramParts = searchParams.split('&');
for(let part of paramParts) {
let paramValuePair = part.split('=');
//exclude the case when the param has no value
if(paramValuePair.length===2) {
result[paramValuePair[0]] = decodeURIComponent(paramValuePair[1]);
}
}
}
return result;
}
许多其他的解决方案没有考虑到边界情况。
这个可以处理
空键a=1&b=2& 空值a=1&b 空值a=1&b= 未编码的等号a=1&b=2=3=4
decodeQueryString: qs => {
// expects qs to not have a ?
// return if empty qs
if (qs === '') return {};
return qs.split('&').reduce((acc, pair) => {
// skip no param at all a=1&b=2&
if (pair.length === 0) return acc;
const parts = pair.split('=');
// fix params without value
if (parts.length === 1) parts[1] = '';
// for value handle multiple unencoded = signs
const key = decodeURIComponent(parts[0]);
const value = decodeURIComponent(parts.slice(1).join('='));
acc[key] = value;
return acc;
}, {});
},
在Mike Causer回答的基础上，我创建了这个函数，它考虑了具有相同键的多个参数(foo=bar&foo=baz)和逗号分隔的参数(foo=bar,baz,bin)。它还允许您搜索某个查询键。
function getQueryParams(queryKey) {
var queryString = window.location.search;
var query = {};
var pairs = (queryString[0] === '?' ? queryString.substr(1) : queryString).split('&');
for (var i = 0; i < pairs.length; i++) {
var pair = pairs[i].split('=');
var key = decodeURIComponent(pair[0]);
var value = decodeURIComponent(pair[1] || '');
// Se possui uma vírgula no valor, converter em um array
value = (value.indexOf(',') === -1 ? value : value.split(','));
// Se a key já existe, tratar ela como um array
if (query[key]) {
if (query[key].constructor === Array) {
// Array.concat() faz merge se o valor inserido for um array
query[key] = query[key].concat(value);
} else {
// Se não for um array, criar um array contendo o valor anterior e o novo valor
query[key] = [query[key], value];
}
} else {
query[key] = value;
}
}
if (typeof queryKey === 'undefined') {
return query;
} else {
return query[queryKey];
}
}
示例输入: foo.html吗?博兹,foo = bar&foo = baz&foo =鹿角的第二叉,buz&bar = 1, 2, 3
示例输出
{
foo: ["bar","baz","bez","boz","buz"],
bar: ["1","2","3"]
}
一个简明的解决方案:
location.search
.slice(1)
.split('&')
.map(p => p.split('='))
.reduce((obj, pair) => {
const [key, value] = pair.map(decodeURIComponent);
obj[key] = value;
return obj;
}, {});
