我怎样才能将我的JS对象转换为FormData?
我这样做的原因是，我有一个用~100个表单字段值构造的对象。
var item = {
description: 'Some Item',
price : '0.00',
srate : '0.00',
color : 'red',
...
...
}
现在我被要求将上传文件功能添加到我的表单，当然，通过JSON是不可能的，所以我计划移动到FormData。那么有什么方法可以将我的JS对象转换为FormData呢?
当前回答
将处理嵌套数组和对象的解决方案。有人可能会觉得有用
function add_form_data(form_data,key,item,arr){
if(typeof(item)==='object' && item && item.constructor===Array){
for(var i=0;i<item.length;i++){
var item2=item[i];
var key2=key+'[' + i +']';
if(arr){
key2=key+'[' + key2 +']';
}
add_form_data(form_data,key2,item2,true);
}
}else if(typeof(item)==='object' && item){
for ( var key2 in item ) {
var item2=item[key2];
if(arr){
key2=key+'[' + key2 +']';
}
add_form_data(form_data,key2,item2,arr);
}
}else{
form_data.append(key,item);
}
}
使用
var form_data = new FormData();
add_form_data(form_data,null,json_data);// provide json_data here
var string_url_data=new URLSearchParams(form_data).toString();// if query string is needed
其他回答
递归地
const toFormData = (f => f(f))(h => f => f(x => h(h)(f)(x)))(f => fd => pk => d => { if (d instanceof Object) { Object.keys(d).forEach(k => { const v = d[k] if (pk) k = `${pk}[${k}]` if (v instanceof Object && !(v instanceof Date) && !(v instanceof File)) { return f(fd)(k)(v) } else { fd.append(k, v) } }) } return fd })(new FormData())() let data = { name: 'John', age: 30, colors: ['red', 'green', 'blue'], children: [ { name: 'Max', age: 3 }, { name: 'Madonna', age: 10 } ] } console.log('data', data) document.getElementById("data").insertAdjacentHTML('beforeend', JSON.stringify(data)) let formData = toFormData(data) for (let key of formData.keys()) { console.log(key, formData.getAll(key).join(',')) document.getElementById("item").insertAdjacentHTML('beforeend', `<li>${key} = ${formData.getAll(key).join(',')}</li>`) } <p id="data"></p> <ul id="item"></ul>
尝试 obj2fd=> https://www.npmjs.com/package/obj2fd
import obj2fd from 'obj2fd'
let data = {a:1, b:2, c:{ca:1}};
let dataWithFormData = obj2fd(data);
//result => [a=>1, b=>2, c=>[ca=>1]]
使用jquery，你可以通过$.param(obj)简单地做到这一点。
例子: Const obj = { 描述:'Some Item'， 价格:0.00, srate:“0.00”, 颜色:红色的 ｝ Const form_obj = $.param(obj); . ajax({美元 url:“example.com”, 方法:“文章”, 数据:form_obj }) < script src = " https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js " > < /脚本>
使用ES6和更函数式的编程方法@adeneo的答案可能是这样的:
function getFormData(object) {
const formData = new FormData();
Object.keys(object).forEach(key => formData.append(key, object[key]));
return formData;
}
或者使用.reduce()和箭头函数:
const getFormData = object => Object.keys(object).reduce((formData, key) => {
formData.append(key, object[key]);
return formData;
}, new FormData());
我参考了古德拉丹的回答。我用Typescript格式编辑了一下。
class UtilityService {
private appendFormData(formData, data, rootName) {
let root = rootName || '';
if (data instanceof File) {
formData.append(root, data);
} else if (Array.isArray(data)) {
for (var i = 0; i < data.length; i++) {
this.appendFormData(formData, data[i], root + '[' + i + ']');
}
} else if (typeof data === 'object' && data) {
for (var key in data) {
if (data.hasOwnProperty(key)) {
if (root === '') {
this.appendFormData(formData, data[key], key);
} else {
this.appendFormData(formData, data[key], root + '.' + key);
}
}
}
} else {
if (data !== null && typeof data !== 'undefined') {
formData.append(root, data);
}
}
}
getFormDataFromObj(data) {
var formData = new FormData();
this.appendFormData(formData, data, '');
return formData;
}
}
export let UtilityMan = new UtilityService();
