如何用c#中的一个空格替换字符串中的多个空格?

例子:

1 2 3  4    5

是:

1 2 3 4 5

当前回答

string sentence = "This is a sentence with multiple    spaces";
RegexOptions options = RegexOptions.None;
Regex regex = new Regex("[ ]{2,}", options);     
sentence = regex.Replace(sentence, " ");

其他回答

string sentence = "This is a sentence with multiple    spaces";
RegexOptions options = RegexOptions.None;
Regex regex = new Regex("[ ]{2,}", options);     
sentence = regex.Replace(sentence, " ");

其实比这简单得多:

while(str.Contains("  ")) str = str.Replace("  ", " ");

我知道这很老了,但在尝试完成几乎相同的事情时偶然发现了它。在RegEx Buddy中找到了这个解决方案。该模式将用单个空格替换所有的双空格,并修剪开头和结尾空格。

pattern: (?m:^ +| +$|( ){2,})
replacement: $1

因为我们处理的是空格,所以读起来有点困难,所以这里还是用“_”代替了“空格”。

pattern: (?m:^_+|_+$|(_){2,})  <-- don't use this, just for illustration.

“(?M:" construct启用“多行”选项。我通常喜欢在模式本身中包含任何我可以包含的选项,这样它就更独立了。

// Mysample string
string str ="hi you           are          a demo";

//Split the words based on white sapce
var demo= str .Split(' ').Where(s => !string.IsNullOrWhiteSpace(s));
        
//Join the values back and add a single space in between
str = string.Join(" ", demo);
// output: string str ="hi you are a demo";
string xyz = "1   2   3   4   5";
xyz = string.Join( " ", xyz.Split( new char[] { ' ' }, StringSplitOptions.RemoveEmptyEntries ));