在Groovy中

inputStream.getText()

下面的代码对我有用。

URL url = MyClass.class.getResource("/" + configFileName);
BufferedInputStream bi = (BufferedInputStream) url.getContent();
byte[] buffer = new byte[bi.available() ];
int bytesRead = bi.read(buffer);
String out = new String(buffer);

请注意，根据Java文档，available（）方法可能不适用于InputStream，但始终适用于BufferedInputStream。如果您不想使用available（）方法，我们可以始终使用以下代码

URL url = MyClass.class.getResource("/" + configFileName);
BufferedInputStream bi = (BufferedInputStream) url.getContent();
File f = new File(url.getPath());
byte[] buffer = new byte[ (int) f.length()];
int bytesRead = bi.read(buffer);
String out = new String(buffer);

我不确定是否会有任何编码问题。如果代码有任何问题，请发表评论。

这个很好，因为：

它可以安全地处理Charset。您可以控制读取缓冲区的大小。您可以设置生成器的长度，而不必是精确的值。不受库依赖关系的影响。适用于Java 7或更高版本。

怎么做？

public static String convertStreamToString(InputStream is) throws IOException {
   StringBuilder sb = new StringBuilder(2048); // Define a size if you have an idea of it.
   char[] read = new char[128]; // Your buffer size.
   try (InputStreamReader ir = new InputStreamReader(is, StandardCharsets.UTF_8)) {
     for (int i; -1 != (i = ir.read(read)); sb.append(read, 0, i));
   }
   return sb.toString();
}

对于JDK 9

public static String inputStreamString(InputStream inputStream) throws IOException {
    try (inputStream) {
        return new String(inputStream.readAllBytes(), StandardCharsets.UTF_8);
    }
}

异-8859-1

如果您知道输入流的编码是ISO-8859-1或ASCII，这里有一种非常高效的方法来实现这一点。它（1）避免了StringWriter的内部StringBuffer中存在的不必要的同步，（2）避免了InputStreamReader的开销，（3）最小化了必须复制StringBuilder的内部字符数组的次数。

public static String iso_8859_1(InputStream is) throws IOException {
    StringBuilder chars = new StringBuilder(Math.max(is.available(), 4096));
    byte[] buffer = new byte[4096];
    int n;
    while ((n = is.read(buffer)) != -1) {
        for (int i = 0; i < n; i++) {
            chars.append((char)(buffer[i] & 0xFF));
        }
    }
    return chars.toString();
}

UTF-8型

对于使用UTF-8编码的流，可以使用相同的通用策略：

public static String utf8(InputStream is) throws IOException {
    StringBuilder chars = new StringBuilder(Math.max(is.available(), 4096));
    byte[] buffer = new byte[4096];
    int n;
    int state = 0;
    while ((n = is.read(buffer)) != -1) {
        for (int i = 0; i < n; i++) {
            if ((state = nextStateUtf8(state, buffer[i])) >= 0) {
                chars.appendCodePoint(state);
            } else if (state == -1) { //error
                state = 0;
                chars.append('\uFFFD'); //replacement char
            }
        }
    }
    return chars.toString();
}

其中nextStateUtf8（）函数定义如下：

/**
 * Returns the next UTF-8 state given the next byte of input and the current state.
 * If the input byte is the last byte in a valid UTF-8 byte sequence,
 * the returned state will be the corresponding unicode character (in the range of 0 through 0x10FFFF).
 * Otherwise, a negative integer is returned. A state of -1 is returned whenever an
 * invalid UTF-8 byte sequence is detected.
 */
static int nextStateUtf8(int currentState, byte nextByte) {
    switch (currentState & 0xF0000000) {
        case 0:
            if ((nextByte & 0x80) == 0) { //0 trailing bytes (ASCII)
                return nextByte;
            } else if ((nextByte & 0xE0) == 0xC0) { //1 trailing byte
                if (nextByte == (byte) 0xC0 || nextByte == (byte) 0xC1) { //0xCO & 0xC1 are overlong
                    return -1;
                } else {
                    return nextByte & 0xC000001F;
                }
            } else if ((nextByte & 0xF0) == 0xE0) { //2 trailing bytes
                if (nextByte == (byte) 0xE0) { //possibly overlong
                    return nextByte & 0xA000000F;
                } else if (nextByte == (byte) 0xED) { //possibly surrogate
                    return nextByte & 0xB000000F;
                } else {
                    return nextByte & 0x9000000F;
                }
            } else if ((nextByte & 0xFC) == 0xF0) { //3 trailing bytes
                if (nextByte == (byte) 0xF0) { //possibly overlong
                    return nextByte & 0x80000007;
                } else {
                    return nextByte & 0xE0000007;
                }
            } else if (nextByte == (byte) 0xF4) { //3 trailing bytes, possibly undefined
                return nextByte & 0xD0000007;
            } else {
                return -1;
            }
        case 0xE0000000: //3rd-to-last continuation byte
            return (nextByte & 0xC0) == 0x80 ? currentState << 6 | nextByte & 0x9000003F : -1;
        case 0x80000000: //3rd-to-last continuation byte, check overlong
            return (nextByte & 0xE0) == 0xA0 || (nextByte & 0xF0) == 0x90 ? currentState << 6 | nextByte & 0x9000003F : -1;
        case 0xD0000000: //3rd-to-last continuation byte, check undefined
            return (nextByte & 0xF0) == 0x80 ? currentState << 6 | nextByte & 0x9000003F : -1;
        case 0x90000000: //2nd-to-last continuation byte
            return (nextByte & 0xC0) == 0x80 ? currentState << 6 | nextByte & 0xC000003F : -1;
        case 0xA0000000: //2nd-to-last continuation byte, check overlong
            return (nextByte & 0xE0) == 0xA0 ? currentState << 6 | nextByte & 0xC000003F : -1;
        case 0xB0000000: //2nd-to-last continuation byte, check surrogate
            return (nextByte & 0xE0) == 0x80 ? currentState << 6 | nextByte & 0xC000003F : -1;
        case 0xC0000000: //last continuation byte
            return (nextByte & 0xC0) == 0x80 ? currentState << 6 | nextByte & 0x3F : -1;
        default:
            return -1;
    }
}

自动检测编码

如果您的输入流是使用ASCII、ISO-8859-1或UTF-8编码的，但您不确定是哪一种，我们可以使用与上一种方法类似的方法，但使用额外的编码检测组件在返回字符串之前自动检测编码。

public static String autoDetect(InputStream is) throws IOException {
    StringBuilder chars = new StringBuilder(Math.max(is.available(), 4096));
    byte[] buffer = new byte[4096];
    int n;
    int state = 0;
    boolean ascii = true;
    while ((n = is.read(buffer)) != -1) {
        for (int i = 0; i < n; i++) {
            if ((state = nextStateUtf8(state, buffer[i])) > 0x7F)
                ascii = false;
            chars.append((char)(buffer[i] & 0xFF));
        }
    }

    if (ascii || state < 0) { //probably not UTF-8
        return chars.toString();
    }
    //probably UTF-8
    int pos = 0;
    char[] charBuf = new char[2];
    for (int i = 0, len = chars.length(); i < len; i++) {
        if ((state = nextStateUtf8(state, (byte)chars.charAt(i))) >= 0) {
            boolean hi = Character.toChars(state, charBuf, 0) == 2;
            chars.setCharAt(pos++, charBuf[0]);
            if (hi) {
                chars.setCharAt(pos++, charBuf[1]);
            }
        }
    }
    return chars.substring(0, pos);
}

如果您的输入流的编码既不是ISO-8859-1，也不是ASCII，也不是UTF-8，那么我就遵从已经存在的其他答案。

这里有一种仅使用标准Java库的方法（请注意，流没有关闭，您的里程可能会有所不同）。

static String convertStreamToString(java.io.InputStream is) {
    java.util.Scanner s = new java.util.Scanner(is).useDelimiter("\\A");
    return s.hasNext() ? s.next() : "";
}

我从“愚蠢的扫描仪技巧”一文中学会了这个技巧。它工作的原因是因为Scanner迭代流中的令牌，在这种情况下，我们使用“输入边界的开始”（\A）来分离令牌，从而为流的整个内容只提供一个令牌。

注意，如果您需要明确输入流的编码，可以向Scanner构造函数提供第二个参数，指示要使用的字符集（例如“UTF-8”）。

雅各布也收到了帽子提示，他曾向我指出了上述文章。

Use:

import java.io.BufferedInputStream;
import java.io.ByteArrayOutputStream;
import java.io.InputStream;
import java.io.IOException;

public static String readInputStreamAsString(InputStream in)
    throws IOException {

    BufferedInputStream bis = new BufferedInputStream(in);
    ByteArrayOutputStream buf = new ByteArrayOutputStream();
    int result = bis.read();
    while(result != -1) {
      byte b = (byte)result;
      buf.write(b);
      result = bis.read();
    }
    return buf.toString();
}