是否可以查询包含以下列的表名

LIKE '%myName%'

?


当前回答

select  
        s.[name]            'Schema',
        t.[name]            'Table',
        c.[name]            'Column',
        d.[name]            'Data Type',
        c.[max_length]      'Length',
        d.[max_length]      'Max Length',
        d.[precision]       'Precision',
        c.[is_identity]     'Is Id',
        c.[is_nullable]     'Is Nullable',
        c.[is_computed]     'Is Computed',
        d.[is_user_defined] 'Is UserDefined',
        t.[modify_date]     'Date Modified',
        t.[create_date]     'Date created'
from        sys.schemas s
inner join  sys.tables  t
on s.schema_id = t.schema_id
inner join  sys.columns c
on t.object_id = c.object_id
inner join  sys.types   d
on c.user_type_id = d.user_type_id
where c.name like '%ColumnName%'

这里将为您提供一些有关架构、表和列的额外信息,您可以选择或不选择在where子句中使用额外条件进行筛选

and c.is_nullable = 0

您可以添加其他条件,我也以这种垂直方式添加了select子句中的列,以便根据您的需要轻松地重新排序、删除、重命名或添加其他列。或者,您可以使用T.Name搜索表格。它非常可定制。

享受

其他回答

您可以在SQL Server中使用以下查询。

SELECT column_name AS 'ColumnName',
       table_name  AS 'TableName'
FROM   information_schema.columns
WHERE  column_name LIKE '%columnname%'
       AND table_schema = 'schema'
ORDER  BY tablename,
          columnname;
USE AdventureWorks

GO

SELECT t.name AS table_name, SCHEMA_NAME(schema_id) AS schema_name,
 c.name AS column_name
FROM sys.tables AS t
INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
WHERE c.name LIKE '%EmployeeID%'
ORDER BY schema_name, table_name; 

来自Pinal Sir博客

这是你问题的答案

SELECT c.name AS ColumnName, t.name AS TableName
FROM sys.columns c
    JOIN sys.tables t ON c.object_id = t.object_id
WHERE c.name LIKE '%myName%';

我不知道为什么很多人建议使用sys.columns加入sys.table。

您可以使用以下代码:

SELECT Object_name(object_id) AS TableName,
       *
FROM   sys.columns
WHERE  NAME LIKE '%MyName%' 

or

如果还需要架构名称:

SELECT *
FROM   information_schema.columns
WHERE  column_name LIKE '%MyName%' 

您可以通过column_name过滤器从INFORMATION_SCHEMA.COLUMNS中找到它

Select DISTINCT TABLE_NAME as TableName,COLUMN_NAME as ColumnName
     From INFORMATION_SCHEMA.COLUMNS Where column_name like '%myname%'