我正在使用UITextfied,而点击textfied键盘出现,但当我按下返回键,键盘没有消失。我使用了以下代码:

func textFieldShouldReturn(textField: UITextField!) -> Bool // called when 'return' key pressed. return NO to ignore.
{
    return true;
}

方法resignfirstresponder没有进入函数。


当前回答

我讨厌给每个UIViewController添加相同的函数。 通过扩展UIViewController来支持UITextFieldDelegate,你可以提供一个默认行为“返回按下”。

extension UIViewController: UITextFieldDelegate{
    public func textFieldShouldReturn(_ textField: UITextField) -> Bool {
        textField.resignFirstResponder()
        return true;
    }
}

当你创建新的UIViewController和UITextField时,你所要做的就是在你的UIViewController中写一行代码。

override func viewDidLoad() {
    super.viewDidLoad()
    textField.delegate = self
}

你甚至可以通过在Main.storyboard中钩子委托来省略这一行代码。(使用“ctrl”从UITextField拖动到UIViewController)

其他回答

Add UITextFieldDelegate to the class declaration: class ViewController: UIViewController, UITextFieldDelegate Connect the textfield or write it programmatically @IBOutlet weak var userText: UITextField! set your view controller as the text fields delegate in view did load: override func viewDidLoad() { super.viewDidLoad() self.userText.delegate = self } Add the following function func textFieldShouldReturn(userText: UITextField!) -> Bool { userText.resignFirstResponder() return true; } with all this your keyboard will begin to dismiss by touching outside the textfield aswell as by pressing return key.

不需要委派

你可以从UITextField为“Primary action triggers”创建一个动作出口,并在传入的sender参数上辞职第一响应者:

@IBAction func done(_ sender: UITextField) {
    sender.resignFirstResponder()
}

超级简单。

(感谢斯科特·史密斯60秒的视频,让我知道了这一点:https://youtu.be/v6GrnVQy7iA)

所有在一个隐藏键盘和移动键盘打开视图:Swift 5

override func viewDidLoad() {
    super.viewDidLoad()
    let tap = UITapGestureRecognizer(target: self, action: #selector(taped))
    view.addGestureRecognizer(tap)
    NotificationCenter.default.addObserver(self, selector: #selector(KeyboardWillShow), name: UIResponder.keyboardWillShowNotification, object: nil)
    NotificationCenter.default.addObserver(self, selector: #selector(KeyboardWillHide), name: UIResponder.keyboardWillHideNotification, object: nil)
}


   override func viewWillDisappear(_ animated: Bool) {
    super.viewWillDisappear(true)
    NotificationCenter.default.removeObserver(self, name: UIResponder.keyboardWillShowNotification, object: nil)
    NotificationCenter.default.removeObserver(self, name: UIResponder.keyboardWillHideNotification, object: nil)
}
 @objc func taped(){
    
    self.view.endEditing(true)
    
}

@objc func KeyboardWillShow(sender: NSNotification){
    
    let keyboardSize : CGSize = ((sender.userInfo?[UIResponder.keyboardFrameEndUserInfoKey] as? NSValue)?.cgRectValue.size)!
    if self.view.frame.origin.y == 0{
        self.view.frame.origin.y -= keyboardSize.height
    }
    
    
}

@objc func KeyboardWillHide(sender : NSNotification){
    
    let keyboardSize : CGSize = ((sender.userInfo?[UIResponder.keyboardFrameBeginUserInfoKey] as? NSValue)?.cgRectValue.size)!
    if self.view.frame.origin.y != 0{
        self.view.frame.origin.y += keyboardSize.height
    }
    
}


func textFieldShouldReturn(_ textField: UITextField) -> Bool { 
    textField.resignFirstResponder()
    return true
}

你可以把它放在任何地方,但不能放在UIButton中

 func TextFieldEndEditing(text fiend name: UITextField!) -> Bool
{
    return (false)
}

然后你可以把这段代码放在一个按钮中(也是一个例子):

self.view.endEditing(true)

这对我很有效

override func viewDidLoad() {
    super.viewDidLoad()

    let tap = UITapGestureRecognizer(target: self, action: #selector(handleScreenTap(sender:)))
    self.view.addGestureRecognizer(tap)}

然后用这个函数

func handleScreenTap(sender: UITapGestureRecognizer) {
    self.view.endEditing(true)
}