我更喜欢你使用下面的ES6风格的函数:

getQueryStringParams = query => {
    return query
        ? (/^[?#]/.test(query) ? query.slice(1) : query)
            .split('&')
            .reduce((params, param) => {
                    let [key, value] = param.split('=');
                    params[key] = value ? decodeURIComponent(value.replace(/\+/g, ' ')) : '';
                    return params;
                }, {}
            )
        : {}
};

在hashHistory的push方法中，可以指定查询参数。例如,

history.push({
  pathname: '/dresses',
  search: '?color=blue'
})

or

history.push('/dresses?color=blue')

您可以查看这个存储库以获得有关使用历史记录的其他示例

对于react-router v4.3

const addQuery = (key, value) => {
  let pathname = props.location.pathname;
  // returns path: '/app/books'
  let searchParams = new URLSearchParams(props.location.search);
  // returns the existing query string: '?type=fiction&author=fahid'
  searchParams.set(key, value);
  this.props.history.push({
    pathname: pathname,
    search: searchParams.toString()
  });
};

const removeQuery = (key) => {
  let pathname = props.location.pathname;
  // returns path: '/app/books'
  let searchParams = new URLSearchParams(props.location.search);
  // returns the existing query string: '?type=fiction&author=fahid'
  searchParams.delete(key);
  this.props.history.push({
    pathname: pathname,
    search: searchParams.toString()
  });
};

function SomeComponent({ location }) {
  return <div>
    <button onClick={ () => addQuery('book', 'react')}>search react books</button>
    <button onClick={ () => removeQuery('book')}>remove search</button>
  </div>;
}

要了解更多关于URLSearchParams:

var paramsString = "q=URLUtils.searchParams&topic=api";
var searchParams = new URLSearchParams(paramsString);

//Iterate the search parameters.
for (let p of searchParams) {
  console.log(p);
}

searchParams.has("topic") === true; // true
searchParams.get("topic") === "api"; // true
searchParams.getAll("topic"); // ["api"]
searchParams.get("foo") === null; // true
searchParams.append("topic", "webdev");
searchParams.toString(); // "q=URLUtils.searchParams&topic=api&topic=webdev"
searchParams.set("topic", "More webdev");
searchParams.toString(); // "q=URLUtils.searchParams&topic=More+webdev"
searchParams.delete("topic");
searchParams.toString(); // "q=URLUtils.searchParams"

我做了一个简单的钩子来减轻工作。

让我们想象一下你的url是这样的: /搜索吗?起源=主页= 1

function useUrl(param: string) {

    const history = useHistory()
    const { search, pathname } = useLocation()
    const url = new URLSearchParams(search)

    const urlParam = url.get(param)
    const [value, setValue] = useState(urlParam !== null ? urlParam : '')

    function _setValue(val: string){
        url.set(param, val)
        history.replace({ pathname, search: url.toString() }); 
        setValue(val)
    }

    return [value, _setValue]
}

那么实际使用情况:

function SearchPage() {

    const [origin] = useUrl("origin")
    const [page, setPage] = useUrl("page")

    return (
        <div>
            <p>Return to: {origin}</p>
            <p>Current Page: {page}</p>
        </div>
    )
}

使用React Router V6，我们可以像这样实现它

import { useNavigate, createSearchParams } from 'react-router-dom';

/* In React Component */
const navigate = useNavigate();
const params = {
  color: 'blue',
};
const options = {
  pathname: '/shop/Clothes/dresses',
  search: `?${createSearchParams(params)}`,
};
navigate(options, { replace: true });

你可以使用钩子useHistory 确保你使用的是基于函数的组件 在顶部导入这个

import {useHistory} from "react-router-dom"

在你的组件中，

const history = useHistory()
history.push({
    pathname: window.location.pathname,
    search: '?color=blue'
})