我正在Chrome中开发一个扩展,我想知道:当一个元素出现时,最好的方法是什么?使用纯javascript,间隔检查,直到一个元素存在,或jQuery有一些简单的方法来做到这一点?


当前回答

下面的observe函数将允许您通过选择器监听元素。

在下面的例子中,2秒过后,.greeting将被插入到.container中。因为我们正在监听这个元素的插入,所以我们可以有一个在插入时触发的回调。

const observe = (selector, callback, targetNode = document.body) => new MutationObserver(mutations => [...mutations] .flatMap((mutation) => [...mutation.addedNodes]) .filter((node) => node.matches && node.matches(selector)) .forEach(callback)) .observe(targetNode, { childList: true, subtree: true }); const createGreeting = () => { const el = document.createElement('DIV'); el.textContent = 'Hello World'; el.classList.add('greeting'); return el; }; const container = document.querySelector('.container'); observe('.greeting', el => console.log('I have arrived!', el), container); new Promise(res => setTimeout(() => res(createGreeting()), 2000)) .then(el => container.appendChild(el)); html, body { width: 100%; height: 100%; margin: 0; padding: 0; } body { display: flex; } .container { display: flex; flex: 1; align-items: center; justify-content: center; } .greeting { font-weight: bold; font-size: 2em; } <div class="container"></div>


更新

下面是一个实验性的async/await示例。

const sleep = (ms) => new Promise((res) => setTimeout(res, ms)); const observe = (selector, targetNode = document.body) => new Promise(res => { new MutationObserver(mutations => res([...mutations] .flatMap((mutation) => [...mutation.addedNodes]) .find((node) => node.matches && node.matches(selector)))) .observe(targetNode, { childList: true, subtree: true }); }); const createGreeting = () => { const el = document.createElement('DIV'); el.textContent = 'Hello World'; el.classList.add('greeting'); return el; }; const container = document.querySelector('.container'); observe('.greeting', container) .then(el => console.log('I have arrived!', el)); (async () => { await sleep(2000); container.appendChild(createGreeting()); })(); html, body { width: 100%; height: 100%; margin: 0; padding: 0; } body { display: flex; } .container { display: flex; flex: 1; align-items: center; justify-content: center; } .greeting { font-weight: bold; font-size: 2em; } <div class="container"></div>

其他回答

你可以这样做

$('#yourelement').ready(function() {

});

请注意,这只在从服务器请求元素时元素出现在DOM中时才有效。如果元素是通过JavaScript动态添加的,那么它将不起作用,您可能需要查看其他答案。

你也可以使用getElementById代替querySelector

这个函数和 https://stackoverflow.com/a/61511955/10798137

  async function waitForElementById(id, timeout = null, location = document.body) {
    return new Promise((resolve) => {
        let element = document.getElementById(id);
        if (element) {
            return resolve(element);
        }

        const observer = new MutationObserver(async () => {
            let element = document.getElementById(id);
            if (element) {
                resolve(element);
                observer.disconnect();
            } else {
                if (timeout) {
                    async function timeOver() {
                        return new Promise((resolve) => {
                            setTimeout(() => {
                                observer.disconnect();
                                resolve(false);
                            }, timeout);
                        });
                    }
                    resolve(await timeOver());
                }
            }
        });

        observer.observe(location, {
            childList: true,
            subtree: true,
        });
    });

使用它


    waitForElement("tag_id", 500).then((elm) => {
      console.log(elm)
    })

Or


    var elm = async waitForElement("tag_id", 500)

这里有一个用Javascript编写的promise返回解决方案(没有混乱的回调)。默认情况下,它每200ms检查一次。

function waitFor(selector) {
    return new Promise(function (res, rej) {
        waitForElementToDisplay(selector, 200);
        function waitForElementToDisplay(selector, time) {
            if (document.querySelector(selector) != null) {
                res(document.querySelector(selector));
            }
            else {
                setTimeout(function () {
                    waitForElementToDisplay(selector, time);
                }, time);
            }
        }
    });
}

我采取@Yong Wong的解决方案,但它有一个可选的超时,你可以指定根节点从哪里你想等待元素。

完整的异步/等待。

const $ = (selector, opts) => {
  let timeout = undefined;
  let root = undefined;

  if (opts) {
    ({ root, timeout } = opts);
  }

  if (root === undefined) root = document.body;
  
  const nodeFound = root.querySelector(selector);
  if (nodeFound) return new Promise(resolve => resolve(nodeFound));

  return new Promise((resolve, reject) => {
    let callback = () => {
      observer.disconnect();
    };

    const _resolve = (node) => {
      callback();
      resolve(node);
    };

    const _reject = (err) => {
      callback();
      reject(err);
    };

    if (timeout && timeout > 0) {
      const handle = setTimeout(() => {
        _reject(new Error("Element not found: timeout exceeded."));
      }, timeout);
      callback = () => {
        observer.disconnect();
        clearTimeout(handle);
      };
    }

    const observer = new MutationObserver(mutations => {
      for (const mutation of mutations) {
        for (const addedNode of mutation.addedNodes) {
          if (addedNode.matches(selector)) {
            _resolve(addedNode);
            return;
          }
        }
      }
    });

    observer.observe(root, {
      childList: true,
      subtree: true,
    });
  });
}

示例调用:

// wait for 10 seconds for 'div.bla-bla-bla' to appear as a child of 'div.some-container'
await $("div.bla-bla-bla", {
  timeout: 10000,
  root: document.querySelector("div.some-container") 
});

你可以试试这个:

const wait_until_element_appear = setInterval(() => {
    if ($(element).length !== 0) {
        // some code
        clearInterval(wait_until_element_appear);
    }
}, 0);

这个办法对我很有效