我如何使一个表达式匹配绝对任何东西(包括空白)?例子:

Regex:我买了_____羊。

火柴:我买了羊。我买了一只羊。我买了五只羊。

我尝试使用(.*),但似乎没有工作。


当前回答

如果你使用JavaScript, ES2018添加了/s (dotAll)标志。带有/s标志的点。将匹配任何字符,包括换行符。

游戏机log(“line_1 \ nline_2”。match (/ + / s))

注意:目前还不是所有浏览器都支持它。

其他回答

/。如果没有换行符,*/效果很好。如果它必须匹配换行符,这里有一些解决方案:

Solution Description
/.*/s /s (dot all flag) makes . (wildcard character) match anything, including line breaks. Throw in an * (asterisk), and it will match everything. Read more.
/[\s\S]*/ \s (whitespace metacharacter) will match any whitespace character (space; tab; line break; ...), and \S (opposite of \s) will match anything that is not a whitespace character. * (asterisk) will match all occurrences of the character set (Encapsulated by []). Read more.

Regex: /I bought.*sheep./ Matches - the whole string till the end of line I bought sheep. I bought a sheep. I bought five sheep. Regex: /I bought(.*)sheep./ Matches - the whole string and also capture the sub string within () for further use I bought sheep. I bought a sheep. I bought five sheep. I boughtsheep. I bought a sheep. I bought fivesheep. Example using Javascript/Regex 'I bought sheep. I bought a sheep. I bought five sheep.'.match(/I bought(.*)sheep./)[0]; Output: "I bought sheep. I bought a sheep. I bought five sheep." 'I bought sheep. I bought a sheep. I bought five sheep.'.match(/I bought(.*)sheep./)[1]; Output: " sheep. I bought a sheep. I bought five "

我用这个:(.|\n)+对我来说就像一个魅力!

如果你使用JavaScript, ES2018添加了/s (dotAll)标志。带有/s标志的点。将匹配任何字符,包括换行符。

游戏机log(“line_1 \ nline_2”。match (/ + / s))

注意:目前还不是所有浏览器都支持它。

使用.*,并确保您使用的实现相当于单行,以便在行尾匹配。

这里有一个很好的解释-> http://www.regular-expressions.info/dot.html