从Python列表中删除所有出现的值

lists = [6.9,7,8.9,3,5,4.9,1,2.9,7,9,12.9,10.9,11,7]
def remove_values_from_list():
    for list in lists:
      if(list!=7):
         print(list)
remove_values_from_list()

结果:6.9 8.9 3 5 4.9 12.9 9 12.9 10.9 11

另外,

lists = [6.9,7,8.9,3,5,4.9,1,2.9,7,9,12.9,10.9,11,7]
def remove_values_from_list(remove):
    for list in lists:
      if(list!=remove):
        print(list)
remove_values_from_list(7)

结果:6.9 8.9 3 5 4.9 12.9 9 12.9 10.9 11

你可以使用列表推导式:

def remove_values_from_list(the_list, val):
   return [value for value in the_list if value != val]

x = [1, 2, 3, 4, 2, 2, 3]
x = remove_values_from_list(x, 2)
print x
# [1, 3, 4, 3]

如果你没有内置过滤器，或者不想使用额外的空间，你需要一个线性解决方案……

def remove_all(A, v):
    k = 0
    n = len(A)
    for i in range(n):
        if A[i] !=  v:
            A[k] = A[i]
            k += 1

    A = A[:k]

功能的方法:

Python 3. x

>>> x = [1,2,3,2,2,2,3,4]
>>> list(filter((2).__ne__, x))
[1, 3, 3, 4]

or

>>> x = [1,2,3,2,2,2,3,4]
>>> list(filter(lambda a: a != 2, x))
[1, 3, 3, 4]

or

>>> [i for i in x if i != 2]

Python 2. x

>>> x = [1,2,3,2,2,2,3,4]
>>> filter(lambda a: a != 2, x)
[1, 3, 3, 4]

删除所有重复的出现，并在列表中保留一个:

test = [1, 1, 2, 3]

newlist = list(set(test))

print newlist

[1, 2, 3]

下面是我在Project Euler中使用的函数:

def removeOccurrences(e):
  return list(set(e))

有什么问题:

Motor=['1','2','2']
for i in Motor:
   if i != '2':
       print(i)
print(motor)