有没有办法在Swift中获得设备型号名称(iPhone 4S, iPhone 5, iPhone 5S等)?
我知道有一个名为UIDevice.currentDevice()的属性。模型，但它只返回设备类型(iPod touch, iPhone, iPad, iPhone模拟器等)。
我也知道在Objective-C中使用以下方法可以轻松完成:
#import <sys/utsname.h>
struct utsname systemInfo;
uname(&systemInfo);
NSString* deviceModel = [NSString stringWithCString:systemInfo.machine
encoding:NSUTF8StringEncoding];
但是我正在Swift中开发我的iPhone应用程序，所以有人可以帮助我用等效的方法在Swift中解决这个问题吗?
当前回答
如果你不想每次苹果向设备家族添加新型号时都更新你的代码，可以使用下面的方法只返回型号代码。
func platform() -> String {
var systemInfo = utsname()
uname(&systemInfo)
let modelCode = withUnsafeMutablePointer(&systemInfo.machine) {
ptr in String.fromCString(UnsafePointer<CChar>(ptr))
}
return String.fromCString(modelCode!)!
}
其他回答
我在UIDevice上做了另一个示例扩展，包括基于@HAS的答案的模拟器模型标识符。它在上面的Swift3.2(包括Swift 4)中工作得很好。x, Swift 5):
let modelName = UIDevice.current.modelName
新增型号:iPod touch(第七代)，iPhone SE(第二代)，iPhone 12 mini, iPhone 12 Pro, iPhone 12 Pro Max, iPad Pro(12.9英寸)(第四代)
import UIKit
public extension UIDevice {
/// pares the deveice name as the standard name
var modelName: String {
#if targetEnvironment(simulator)
let identifier = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"]!
#else
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8, value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
#endif
switch identifier {
case "iPod5,1": return "iPod Touch 5"
case "iPod7,1": return "iPod Touch 6"
case "iPod9,1": return "iPod touch (7th generation)"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone9,4": return "iPhone 7 Plus"
case "iPhone8,4": return "iPhone SE"
case "iPhone10,1", "iPhone10,4": return "iPhone 8"
case "iPhone10,2", "iPhone10,5": return "iPhone 8 Plus"
case "iPhone10,3", "iPhone10,6": return "iPhone X"
case "iPhone11,2": return "iPhone XS"
case "iPhone11,4", "iPhone11,6": return "iPhone XS Max"
case "iPhone11,8": return "iPhone XR"
case "iPhone12,1": return "iPhone 11"
case "iPhone12,3": return "iPhone 11 Pro"
case "iPhone12,5": return "iPhone 11 Pro Max"
case "iPhone12,8": return "iPhone SE (2nd generation)"
case "iPhone13,1": return "iPhone 12 mini"
case "iPhone13,2": return "iPhone 12"
case "iPhone13,3": return "iPhone 12 Pro"
case "iPhone13,4": return "iPhone 12 Pro Max"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad 3"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad 4"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad6,11", "iPad6,12": return "iPad 5"
case "iPad7,5", "iPad7,6": return "iPad 6"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad Mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad Mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad Mini 3"
case "iPad5,1", "iPad5,2": return "iPad Mini 4"
case "iPad6,3", "iPad6,4": return "iPad Pro 9.7 Inch"
case "iPad6,7", "iPad6,8": return "iPad Pro 12.9 Inch"
case "iPad7,1", "iPad7,2": return "iPad Pro (12.9-inch) (2nd generation)"
case "iPad7,3", "iPad7,4": return "iPad Pro (10.5-inch)"
case "iPad8,1", "iPad8,2", "iPad8,3", "iPad8,4":return "iPad Pro (11-inch)"
case "iPad8,5", "iPad8,6", "iPad8,7", "iPad8,8":return "iPad Pro (12.9-inch) (3rd generation)"
case "iPad8,11", "iPad8,12": return "iPad Pro (12.9-inch) (4th generation)"
case "AppleTV5,3": return "Apple TV"
case "AppleTV6,2": return "Apple TV 4K"
case "AudioAccessory1,1": return "HomePod"
default: return identifier
}
}
}
这是一个用于检测apple设备的新库
import DeviceDetector
let detector = DeviceDetector.shared
let deviceName = detector.currentDeviceName
let deviceSet = detector.currentDevice
let information = """
Model: \(deviceName)
iPhone?: \(detector.isiPhone)
iPad?: \(detector.isiPad)
Notch?: \(detector.hasSafeArea)
4inch?: \(DeviceSet.iPhone4inchSet.contains(deviceSet))
4.7inch?: \(DeviceSet.iPhone4_7inchSet.contains(deviceSet))
iPhoneSE?: \(DeviceSet.iPhoneSESet.contains(deviceSet))
iPhonePlus?: \(DeviceSet.iPhonePlusSet.contains(deviceSet))
iPadPro?: \(DeviceSet.iPadProSet.contains(deviceSet))
"""
结果
我已经实现了一个超轻量级的库，可以根据给出的一些答案来检测使用的设备:https://github.com/schickling/Device.swift
它可以通过迦太基安装，并像这样使用:
import Device
let deviceType = UIDevice.currentDevice().deviceType
switch deviceType {
case .IPhone6: print("Do stuff for iPhone6")
case .IPadMini: print("Do stuff for iPad mini")
default: print("Check other available cases of DeviceType")
}
使用Swift 3 (Xcode 8.3)
func deviceName() -> String {
var systemInfo = utsname()
uname(&systemInfo)
let str = withUnsafePointer(to: &systemInfo.machine.0) { ptr in
return String(cString: ptr)
}
return str
}
注意:根据官方开发论坛的回答，以这种方式使用元组是安全的。大Int8元组的内存对齐方式将与大Int8数组相同。即:连续且无填充。
这里有一个辅助库。
斯威夫特5
吊舱“股息”，“~> 2.0”
Swift 4.0 - Swift 4.2
吊舱“股息”，“~> 1.3”
如果你只是想确定模型并做出相应的东西。
你可以这样用:
let isIphoneX = Device().isOneOf([.iPhoneX, .simulator(.iPhoneX)])
在函数中:
func isItIPhoneX() -> Bool {
let device = Device()
let check = device.isOneOf([.iPhoneX, .iPhoneXr , .iPhoneXs , .iPhoneXsMax ,
.simulator(.iPhoneX), .simulator(.iPhoneXr) , .simulator(.iPhoneXs) , .simulator(.iPhoneXsMax) ])
return check
}
