有没有办法在Swift中获得设备型号名称(iPhone 4S, iPhone 5, iPhone 5S等)?

我知道有一个名为UIDevice.currentDevice()的属性。模型,但它只返回设备类型(iPod touch, iPhone, iPad, iPhone模拟器等)。

我也知道在Objective-C中使用以下方法可以轻松完成:

#import <sys/utsname.h>

struct utsname systemInfo;
uname(&systemInfo);

NSString* deviceModel = [NSString stringWithCString:systemInfo.machine
                          encoding:NSUTF8StringEncoding];

但是我正在Swift中开发我的iPhone应用程序,所以有人可以帮助我用等效的方法在Swift中解决这个问题吗?


当前回答

当你使用Swift 3时,接受的答案有一些问题! 这个答案(灵感来自NAZIK)适用于Swift 3和新款iPhone:

import UIKit


public extension UIDevice {
var modelName: String {
    #if (arch(i386) || arch(x86_64)) && os(iOS)
        let DEVICE_IS_SIMULATOR = true
    #else
        let DEVICE_IS_SIMULATOR = false
    #endif

    var machineString = String()

    if DEVICE_IS_SIMULATOR == true
    {
        if let dir = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] {
            machineString = dir
        }
    }
    else {
        var systemInfo = utsname()
        uname(&systemInfo)
        let machineMirror = Mirror(reflecting: systemInfo.machine)
        machineString = machineMirror.children.reduce("") { identifier, element in
            guard let value = element.value as? Int8 , value != 0 else { return identifier }
            return identifier + String(UnicodeScalar(UInt8(value)))
        }
    }
    switch machineString {
    case "iPod4,1":                                 return "iPod Touch 4G"
    case "iPod5,1":                                 return "iPod Touch 5G"
    case "iPod7,1":                                 return "iPod Touch 6G"
    case "iPhone3,1", "iPhone3,2", "iPhone3,3":     return "iPhone 4"
    case "iPhone4,1":                               return "iPhone 4s"
    case "iPhone5,1", "iPhone5,2":                  return "iPhone 5"
    case "iPhone5,3", "iPhone5,4":                  return "iPhone 5c"
    case "iPhone6,1", "iPhone6,2":                  return "iPhone 5s"
    case "iPhone7,2":                               return "iPhone 6"
    case "iPhone7,1":                               return "iPhone 6 Plus"
    case "iPhone8,1":                               return "iPhone 6s"
    case "iPhone8,2":                               return "iPhone 6s Plus"
    case "iPhone8,4":                               return "iPhone SE"
    case "iPhone9,1", "iPhone9,3":                  return "iPhone 7"
    case "iPhone9,2", "iPhone 9,4":                 return "iPhone 7 Plus"
    case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
    case "iPad3,1", "iPad3,2", "iPad3,3":           return "iPad 3"
    case "iPad3,4", "iPad3,5", "iPad3,6":           return "iPad 4"
    case "iPad4,1", "iPad4,2", "iPad4,3":           return "iPad Air"
    case "iPad5,3", "iPad5,4":                      return "iPad Air 2"
    case "iPad2,5", "iPad2,6", "iPad2,7":           return "iPad Mini"
    case "iPad4,4", "iPad4,5", "iPad4,6":           return "iPad Mini 2"
    case "iPad4,7", "iPad4,8", "iPad4,9":           return "iPad Mini 3"
    case "iPad5,1", "iPad5,2":                      return "iPad Mini 4"
    case "iPad6,3", "iPad6,4":                      return "iPad Pro (9.7 inch)"
    case "iPad6,7", "iPad6,8":                      return "iPad Pro (12.9 inch)"
    case "AppleTV5,3":                              return "Apple TV"
    default:                                        return machineString
    }
}
}

其他回答

获取模型名称(营销名称)的最简单方法

小心使用私有API -[UIDevice _deviceinfokey:],你不会被Apple拒绝。

// works on both simulators and real devices, iOS 8 to iOS 12
NSString *deviceModelName(void) {
    // For Simulator
    NSString *modelName = NSProcessInfo.processInfo.environment[@"SIMULATOR_DEVICE_NAME"];
    if (modelName.length > 0) {
        return modelName;
    }

    // For real devices and simulators, except simulators running on iOS 8.x
    UIDevice *device = [UIDevice currentDevice];
    NSString *selName = [NSString stringWithFormat:@"_%@ForKey:", @"deviceInfo"];
    SEL selector = NSSelectorFromString(selName);
    if ([device respondsToSelector:selector]) {
#pragma clang diagnostic push
#pragma clang diagnostic ignored "-Warc-performSelector-leaks"
        modelName = [device performSelector:selector withObject:@"marketing-name"];
#pragma clang diagnostic pop
    }
    return modelName;
}

我是怎么得到"marketing-name"这个密钥的?

运行在模拟器上的NSProcessInfo.processInfo.environment包含一个名为“SIMULATOR_CAPABILITIES”的键,其值是一个plist文件。然后你打开plist文件,你会得到模型名称的关键字“marketing-name”。

我发现很多答案都用了字符串。我决定改变@HAS答案使用一个enum:

public enum Devices: String {
    case IPodTouch5
    case IPodTouch6
    case IPhone4
    case IPhone4S
    case IPhone5
    case IPhone5C
    case IPhone5S
    case IPhone6
    case IPhone6Plus
    case IPhone6S
    case IPhone6SPlus
    case IPhone7
    case IPhone7Plus
    case IPhoneSE
    case IPad2
    case IPad3
    case IPad4
    case IPadAir
    case IPadAir2
    case IPadMini
    case IPadMini2
    case IPadMini3
    case IPadMini4
    case IPadPro
    case AppleTV
    case Simulator
    case Other
}

public extension UIDevice {

    public var modelName: Devices {
        var systemInfo = utsname()
        uname(&systemInfo)
        let machineMirror = Mirror(reflecting: systemInfo.machine)
        let identifier = machineMirror.children.reduce("") { identifier, element in
            guard let value = element.value as? Int8 , value != 0 else { return identifier }
            return identifier + String(UnicodeScalar(UInt8(value)))
        }

        switch identifier {
        case "iPod5,1":                                 return Devices.IPodTouch5
        case "iPod7,1":                                 return Devices.IPodTouch6
        case "iPhone3,1", "iPhone3,2", "iPhone3,3":     return Devices.IPhone4
        case "iPhone4,1":                               return Devices.IPhone4S
        case "iPhone5,1", "iPhone5,2":                  return Devices.IPhone5
        case "iPhone5,3", "iPhone5,4":                  return Devices.IPhone5C
        case "iPhone6,1", "iPhone6,2":                  return Devices.IPhone5S
        case "iPhone7,2":                               return Devices.IPhone6
        case "iPhone7,1":                               return Devices.IPhone6Plus
        case "iPhone8,1":                               return Devices.IPhone6S
        case "iPhone8,2":                               return Devices.IPhone6SPlus
        case "iPhone9,1", "iPhone9,3":                  return Devices.IPhone7
        case "iPhone9,2", "iPhone9,4":                  return Devices.IPhone7Plus
        case "iPhone8,4":                               return Devices.IPhoneSE
        case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return Devices.IPad2
        case "iPad3,1", "iPad3,2", "iPad3,3":           return Devices.IPad3
        case "iPad3,4", "iPad3,5", "iPad3,6":           return Devices.IPad4
        case "iPad4,1", "iPad4,2", "iPad4,3":           return Devices.IPadAir
        case "iPad5,3", "iPad5,4":                      return Devices.IPadAir2
        case "iPad2,5", "iPad2,6", "iPad2,7":           return Devices.IPadMini
        case "iPad4,4", "iPad4,5", "iPad4,6":           return Devices.IPadMini2
        case "iPad4,7", "iPad4,8", "iPad4,9":           return Devices.IPadMini3
        case "iPad5,1", "iPad5,2":                      return Devices.IPadMini4
        case "iPad6,3", "iPad6,4", "iPad6,7", "iPad6,8":return Devices.IPadPro
        case "AppleTV5,3":                              return Devices.AppleTV
        case "i386", "x86_64":                          return Devices.Simulator
        default:                                        return Devices.Other
        }
    }

}

使用Swift 3 (Xcode 8.3)

    func deviceName() -> String {
        var systemInfo = utsname()
        uname(&systemInfo)
        let str = withUnsafePointer(to: &systemInfo.machine.0) { ptr in
            return String(cString: ptr)
        }
        return str
    }

注意:根据官方开发论坛的回答,以这种方式使用元组是安全的。大Int8元组的内存对齐方式将与大Int8数组相同。即:连续且无填充。

还有另一个简单的替代方案(模型标识符参考可在https://www.theiphonewiki.com/wiki/Models):找到)

Swift 3/4/5的更新答案,包括字符串修剪和模拟器支持:

func modelIdentifier() -> String {
    if let simulatorModelIdentifier = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] { return simulatorModelIdentifier }
    var sysinfo = utsname()
    uname(&sysinfo) // ignore return value
    return String(bytes: Data(bytes: &sysinfo.machine, count: Int(_SYS_NAMELEN)), encoding: .ascii)!.trimmingCharacters(in: .controlCharacters)
}

在Swift 3中是这样的

 UIDevice.current.model