有没有办法在Swift中获得设备型号名称(iPhone 4S, iPhone 5, iPhone 5S等)?
我知道有一个名为UIDevice.currentDevice()的属性。模型，但它只返回设备类型(iPod touch, iPhone, iPad, iPhone模拟器等)。
我也知道在Objective-C中使用以下方法可以轻松完成:
#import <sys/utsname.h>
struct utsname systemInfo;
uname(&systemInfo);
NSString* deviceModel = [NSString stringWithCString:systemInfo.machine
encoding:NSUTF8StringEncoding];
但是我正在Swift中开发我的iPhone应用程序，所以有人可以帮助我用等效的方法在Swift中解决这个问题吗?
当前回答
当你使用Swift 3时，接受的答案有一些问题! 这个答案(灵感来自NAZIK)适用于Swift 3和新款iPhone:
import UIKit
public extension UIDevice {
var modelName: String {
#if (arch(i386) || arch(x86_64)) && os(iOS)
let DEVICE_IS_SIMULATOR = true
#else
let DEVICE_IS_SIMULATOR = false
#endif
var machineString = String()
if DEVICE_IS_SIMULATOR == true
{
if let dir = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] {
machineString = dir
}
}
else {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
machineString = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8 , value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
}
switch machineString {
case "iPod4,1": return "iPod Touch 4G"
case "iPod5,1": return "iPod Touch 5G"
case "iPod7,1": return "iPod Touch 6G"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone8,4": return "iPhone SE"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone 9,4": return "iPhone 7 Plus"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad 3"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad 4"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad Mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad Mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad Mini 3"
case "iPad5,1", "iPad5,2": return "iPad Mini 4"
case "iPad6,3", "iPad6,4": return "iPad Pro (9.7 inch)"
case "iPad6,7", "iPad6,8": return "iPad Pro (12.9 inch)"
case "AppleTV5,3": return "Apple TV"
default: return machineString
}
}
}
其他回答
我已经实现了一个超轻量级的库，可以根据给出的一些答案来检测使用的设备:https://github.com/schickling/Device.swift
它可以通过迦太基安装，并像这样使用:
import Device
let deviceType = UIDevice.currentDevice().deviceType
switch deviceType {
case .IPhone6: print("Do stuff for iPhone6")
case .IPadMini: print("Do stuff for iPad mini")
default: print("Check other available cases of DeviceType")
}
struct DeviceType {
static let IS_IPHONE_4_OR_LESS = UIDevice.current.userInterfaceIdiom == .phone && Constants.SCREEN_MAX_LENGTH < 568
static let IS_IPHONE_5 = UIDevice.current.userInterfaceIdiom == .phone && Constants.SCREEN_MAX_LENGTH == 568
static let IS_IPHONE_6 = UIDevice.current.userInterfaceIdiom == .phone && Constants.SCREEN_MAX_LENGTH == 667
static let IS_IPHONE_6P = UIDevice.current.userInterfaceIdiom == .phone && Constants.SCREEN_MAX_LENGTH == 736
static let IS_IPAD = UIDevice.current.userInterfaceIdiom == .pad && Constants.SCREEN_MAX_LENGTH == 1024
}
在Swift 3中是这样的
UIDevice.current.model
对于swift4.0及以上使用以下代码:
let udid = UIDevice.current.identifierForVendor?.uuidString
let name = UIDevice.current.name
let version = UIDevice.current.systemVersion
let modelName = UIDevice.current.model
let osName = UIDevice.current.systemName
let localized = UIDevice.current.localizedModel
print(udid ?? "")
print(name)
print(version)
print(modelName)
print(osName)
print(localized)
我最近在开发这个swift包:
https://github.com/EmilioOjeda/Device
我认为它的主要优点是代码生成的。所以每当一个新的Xcode版本发布时，我所要做的就是运行一个脚本并更新swift包。
代码生成是如何工作的?
它从Xcode的数据库(每个平台)读取并解析设备的数据，以识别正在运行的设备，并为其提供信息。
这是用法……
import Device
// or => 'import iPhoneOSDevice' <= iPhoneOS-only device data
// or => 'import tvOSDevice' <= tvOS-only device data
// A representation of the running device - it could be either actual or simulated.
let device = Device.current
// It is 'true' when running on a physical device.
_ = device.isDevice
// It is 'true' when running on a simulator instance.
_ = device.isSimulator
// It is 'true' when the device does not match either simulators or physical devices.
_ = device.isUnknown
// The identifier for the device.
// i.e.: 'iPhone15,3'
let id = device.id
// The known/commercial name of the device.
// i.e.: 'iPhone 14 Pro Max'
let model = device.model
