我在mapview中有许多注释(与rightCalloutAccessory按钮)。该按钮将执行一个从mapview到tableview的segue。我想传递给tableview一个不同的对象(持有数据)，这取决于哪个callout按钮被单击。
例如:(完全是瞎编的)
注释1 (Austin) ->传递数据obj 1(与Austin相关) 注释2(达拉斯)->传递数据obj 2(有关达拉斯) 注释3(休斯顿)->传递数据obj 3等等…(你会得到 主意)
我能够检测到哪个调出按钮被单击。
我使用prepareForSegue:来传递数据对象到目标ViewController。由于我不能使这个调用为我需要的数据对象额外的参数，有什么优雅的方法来实现相同的效果(动态数据对象)?
任何建议都将不胜感激。
当前回答
对于Swift来说，
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
var segueID = segue.identifier
if(segueID! == "yourSegueName"){
var yourVC:YourViewController = segue.destinationViewController as YourViewController
yourVC.objectOnYourVC = setObjectValueHere!
}
}
其他回答
我使用这个解决方案，这样我就可以在同一个函数中保持对segue的调用和数据通信:
private var segueCompletion : ((UIStoryboardSegue, Any?) -> Void)?
func performSegue(withIdentifier identifier: String, sender: Any?, completion: @escaping (UIStoryboardSegue, Any?) -> Void) {
self.segueCompletion = completion;
self.performSegue(withIdentifier: identifier, sender: sender);
self.segueCompletion = nil
}
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
self.segueCompletion?(segue, sender)
}
用例应该是这样的:
func showData(id : Int){
someService.loadSomeData(id: id) {
data in
self.performSegue(withIdentifier: "showData", sender: self) {
storyboard, sender in
let dataView = storyboard.destination as! DataView
dataView.data = data
}
}
}
这似乎对我有用，但是，我不能100%确定perform和prepare函数总是在同一个线程上执行。
我有一个sender类，像这样
@class MyEntry;
@interface MySenderEntry : NSObject
@property (strong, nonatomic) MyEntry *entry;
@end
@implementation MySenderEntry
@end
我使用这个sender类来传递对象prepareForSeque:sender:
-(void)didSelectItemAtIndexPath:(NSIndexPath*)indexPath
{
MySenderEntry *sender = [MySenderEntry new];
sender.entry = [_entries objectAtIndex:indexPath.row];
[self performSegueWithIdentifier:SEGUE_IDENTIFIER_SHOW_ENTRY sender:sender];
}
-(void)prepareForSegue:(UIStoryboardSegue*)segue sender:(id)sender
{
if ([[segue identifier] isEqualToString:SEGUE_IDENTIFIER_SHOW_ENTRY]) {
NSAssert([sender isKindOfClass:[MySenderEntry class]], @"MySenderEntry");
MySenderEntry *senderEntry = (MySenderEntry*)sender;
MyEntry *entry = senderEntry.entry;
NSParameterAssert(entry);
[segue destinationViewController].delegate = self;
[segue destinationViewController].entry = entry;
return;
}
if ([[segue identifier] isEqualToString:SEGUE_IDENTIFIER_HISTORY]) {
// ...
return;
}
if ([[segue identifier] isEqualToString:SEGUE_IDENTIFIER_FAVORITE]) {
// ...
return;
}
}
在Swift 4.2中，我会这样做:
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if let yourVC = segue.destination as? YourViewController {
yourVC.yourData = self.someData
}
}
我的解决方案是类似的。
// In destination class:
var AddressString:String = String()
// In segue:
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if (segue.identifier == "seguetobiddetailpagefromleadbidder")
{
let secondViewController = segue.destinationViewController as! BidDetailPage
secondViewController.AddressString = pr.address as String
}
}
对于Swift来说，
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
var segueID = segue.identifier
if(segueID! == "yourSegueName"){
var yourVC:YourViewController = segue.destinationViewController as YourViewController
yourVC.objectOnYourVC = setObjectValueHere!
}
}
