如何使用JUnit来测试某些代码是否抛出异常?

我当然可以这样做:

@Test
public void testFooThrowsIndexOutOfBoundsException() {
  boolean thrown = false;

  try {
    foo.doStuff();
  } catch (IndexOutOfBoundsException e) {
    thrown = true;
  }

  assertTrue(thrown);
}

我记得,对于这类情况,有一个注释或Assert.xyz之类的东西远没有JUnit那么笨拙,更符合JUnit的精神。


当前回答

只需制作一个可以关闭和打开的Matcher,如下所示:

public class ExceptionMatcher extends BaseMatcher<Throwable> {
    private boolean active = true;
    private Class<? extends Throwable> throwable;

    public ExceptionMatcher(Class<? extends Throwable> throwable) {
        this.throwable = throwable;
    }

    public void on() {
        this.active = true;
    }

    public void off() {
        this.active = false;
    }

    @Override
    public boolean matches(Object object) {
        return active && throwable.isAssignableFrom(object.getClass());
    }

    @Override
    public void describeTo(Description description) {
        description.appendText("not the covered exception type");
    }
}

要使用它:

add public ExpectedException exception=ExpectedException.none();,那么:

ExceptionMatcher exMatch = new ExceptionMatcher(MyException.class);
exception.expect(exMatch);
someObject.somethingThatThrowsMyException();
exMatch.off();

其他回答

IMHO,在JUnit中检查异常的最佳方法是try/catch/fail/assert模式:

// this try block should be as small as possible,
// as you want to make sure you only catch exceptions from your code
try {
    sut.doThing();
    fail(); // fail if this does not throw any exception
} catch(MyException e) { // only catch the exception you expect,
                         // otherwise you may catch an exception for a dependency unexpectedly
    // a strong assertion on the message, 
    // in case the exception comes from anywhere an unexpected line of code,
    // especially important if your checking IllegalArgumentExceptions
    assertEquals("the message I get", e.getMessage()); 
}

assertTrue对某些人来说可能有点强,所以assertThat(例如getMessage(),containsString(“消息”);可能更可取。

这样如何:捕获一个非常普通的异常,确保它从catch块中取出,然后断言该异常的类是您期望的。如果a)异常类型错误(例如,如果您使用了空指针),并且b)该异常从未被抛出,则该断言将失败。

public void testFooThrowsIndexOutOfBoundsException() {
  Throwable e = null;

  try {
    foo.doStuff();
  } catch (Throwable ex) {
    e = ex;
  }

  assertTrue(e instanceof IndexOutOfBoundsException);
}

JUnit 5解决方案

import static org.junit.jupiter.api.Assertions.assertThrows;

@Test
void testFooThrowsIndexOutOfBoundsException() {    
  IndexOutOfBoundsException exception = expectThrows(IndexOutOfBoundsException.class, foo::doStuff);
     
  assertEquals("some message", exception.getMessage());
}

关于JUnit 5的更多信息http://junit.org/junit5/docs/current/user-guide/#writing-测试断言

我想评论一下这个问题的解决方案,它避免了任何与异常相关的JUnit代码。

我使用assertTrue(布尔值)和try/catch组合来查找要抛出的预期异常。下面是一个示例:

public void testConstructor() {
    boolean expectedExceptionThrown;
    try {
        // Call constructor with bad arguments
        double a = 1;
        double b = 2;
        double c = a + b; // In my example, this is an invalid option for c
        new Triangle(a, b, c);
        expectedExceptionThrown = false; // because it successfully constructed the object
    }
    catch(IllegalArgumentException e) {
        expectedExceptionThrown = true; // because I'm in this catch block
    }
    catch(Exception e) {
        expectedExceptionThrown = false; // because it threw an exception but not the one expected
    }
    assertTrue(expectedExceptionThrown);
}

JUnit内置了对此的支持,并带有“expected”属性。