如果你想使用js-cookie npm包并按名称删除cookie:

import cookie from 'js-cookie'

export const removeAllCookiesByName = (cookieName: string) => {
  const hostParts = location.host.split('.')
  const domains = hostParts.reduce(
    (acc: string[], current, index) => [
      ...acc,
      hostParts.slice(index).join('.'),
    ],
    []
  )
  domains.forEach((domain) => cookie.remove(cookieName, { domain }))
}

如果你有jquery的访问。Cookie插件，你可以用这种方式删除所有的Cookie:

for (var it in $.cookie()) $.removeCookie(it);

函数方法+ ES6

const cookieCleaner = () => {
  return document.cookie.split(";").reduce(function (acc, cookie) {
    const eqPos = cookie.indexOf("=");
    const cleanCookie = `${cookie.substr(0, eqPos)}=;expires=Thu, 01 Jan 1970 00:00:00 GMT;`;
    return `${acc}${cleanCookie}`;
  }, "");
}

注意:不处理路径

一个衬套

以防你想快速粘贴进去…

document.cookie.split(";").forEach(function(c) { document.cookie = c.replace(/^ +/, "").replace(/=.*/, "=;expires=" + new Date().toUTCString() + ";path=/"); });

和bookmarklet的代码:

javascript:(function(){document.cookie.split(";").forEach(function(c) { document.cookie = c.replace(/^ +/, "").replace(/=.*/, "=;expires=" + new Date().toUTCString() + ";path=/"); }); })();

//Delete all cookies
function deleteAllCookies() {
    var cookies = document.cookie.split(";");
    for (var i = 0; i < cookies.length; i++) {
        var cookie = cookies[i];
        var eqPos = cookie.indexOf("=");
        var name = eqPos > -1 ? cookie.substr(0, eqPos) : cookie;
        document.cookie = name + '=;' +
            'expires=Thu, 01-Jan-1970 00:00:01 GMT;' +
            'path=' + '/;' +
            'domain=' + window.location.host + ';' +
            'secure=;';
    }
}

这个答案受到第二个答案和W3Schools的影响

document.cookie.split(';').forEach(function(c) {
  document.cookie = c.trim().split('=')[0] + '=;' + 'expires=Thu, 01 Jan 1970 00:00:00 UTC;';
});

似乎有效果

编辑:哇，几乎和扎克的Stack Overflow把它们放在一起的有趣方式一模一样。

编辑:NVM显然是暂时的