我如何通过iPhone键盘上的“下一步”按钮浏览所有的文本字段?
最后一个文本字段应该关闭键盘。
我已经设置了IB按钮(下一步/完成),但现在我卡住了。
我实现了textFieldShouldReturn动作,但现在下一步和完成按钮关闭键盘。
我如何通过iPhone键盘上的“下一步”按钮浏览所有的文本字段?
最后一个文本字段应该关闭键盘。
我已经设置了IB按钮(下一步/完成),但现在我卡住了。
我实现了textFieldShouldReturn动作,但现在下一步和完成按钮关闭键盘。
当前回答
Swift 4 for mxcl答案:
txtFirstname.addTarget(txtLastname, action:
#selector(becomeFirstResponder), for: UIControlEvents.editingDidEndOnExit)
其他回答
退出一个文本字段后,调用[otherTextField becomeFirstResponder],下一个字段获得焦点。
这实际上是一个棘手的问题,因为通常你还想滚动屏幕或以其他方式调整文本字段的位置,以便在编辑时容易看到。只要确保做大量的测试,以不同的方式进入和退出文本字段,并提前离开(总是给用户一个选项,取消键盘,而不是进入下一个字段,通常在导航栏中有“完成”)
我很惊讶,这里有这么多答案没有理解一个简单的概念:在应用程序中的控件中导航不是视图本身应该做的事情。控制器的工作是决定将哪个控件作为下一个第一响应器。
此外,大多数答案只适用于前进导航,但用户也可能想后退。
这就是我想到的。表单应该由视图控制器管理,视图控制器是响应器链的一部分。所以你可以完全自由地实现以下方法:
#pragma mark - Key Commands
- (NSArray *)keyCommands
{
static NSArray *commands;
static dispatch_once_t once;
dispatch_once(&once, ^{
UIKeyCommand *const forward = [UIKeyCommand keyCommandWithInput:@"\t" modifierFlags:0 action:@selector(tabForward:)];
UIKeyCommand *const backward = [UIKeyCommand keyCommandWithInput:@"\t" modifierFlags:UIKeyModifierShift action:@selector(tabBackward:)];
commands = @[forward, backward];
});
return commands;
}
- (void)tabForward:(UIKeyCommand *)command
{
NSArray *const controls = self.controls;
UIResponder *firstResponder = nil;
for (UIResponder *const responder in controls) {
if (firstResponder != nil && responder.canBecomeFirstResponder) {
[responder becomeFirstResponder]; return;
}
else if (responder.isFirstResponder) {
firstResponder = responder;
}
}
[controls.firstObject becomeFirstResponder];
}
- (void)tabBackward:(UIKeyCommand *)command
{
NSArray *const controls = self.controls;
UIResponder *firstResponder = nil;
for (UIResponder *const responder in controls.reverseObjectEnumerator) {
if (firstResponder != nil && responder.canBecomeFirstResponder) {
[responder becomeFirstResponder]; return;
}
else if (responder.isFirstResponder) {
firstResponder = responder;
}
}
[controls.lastObject becomeFirstResponder];
}
额外的逻辑滚动屏幕外的响应可见之前可能适用。
这种方法的另一个优点是,您不需要子类化您可能想要显示的所有类型的控件(如UITextFields),而是可以在控制器级别管理逻辑,老实说,在控制器级别管理逻辑是正确的。
Swift 3解决方案,使用UITextField的有序数组
func nextTextField() {
let textFields = // Your textfields array
for i in 0 ..< textFields.count{
if let textfield = textFields[i], textfield.isFirstResponder{
textfield.resignFirstResponder()
if i+1 < textFields.count, let nextextfield = textFields[i+1]{
nextextfield.becomeFirstResponder()
return
}
}
}
}
我已经实现了在视图层次结构中通过Responders导航的动态解决方案。其思想是,在整个层次结构中搜索下一个可能的响应器,根据需要向前或向后搜索。
UIView搜索扩展:
UIView+Cat.h
- (UIResponder *)getNextFirstResponder;
- (UIResponder *)getPreviousFirstResponder;
UIView+Cat.m
- (UIResponder *)getPreviousFirstResponder {
if (!self.superview) {
return nil;
}
BOOL hasreachedself = NO;
for (NSInteger i = self.superview.subviews.count-1; i >= 0; i--) {
UIView *v = [self.superview.subviews objectAtIndex:i];
if (v == self) {
hasreachedself = YES;
continue;
}
if (!hasreachedself) continue;
if ([v canBecomeFirstResponder] && !v.hidden) {
return v;
}
UIResponder *subResponder = [self getNextFirstResponderInView:v];
if (subResponder) {
return subResponder;
}
}
//search hierachicaly in superviews
return [self.superview getPreviousFirstResponder];
}
- (UIResponder *)getNextFirstResponder {
if (!self.superview) {
return nil;
}
BOOL hasreachedself = NO;
for (UIView *v in self.superview.subviews) {
if (v == self) {
hasreachedself = YES;
continue;
}
if (!hasreachedself) continue;
if ([v canBecomeFirstResponder] && !v.hidden) {
return v;
}
UIResponder *subResponder = [self getNextFirstResponderInView:v];
if (subResponder) {
return subResponder;
}
}
//search hierachicaly in superviews
return [self.superview getNextFirstResponder];
}
- (UIResponder *)getNextFirstResponderInView:(UIView *)view {
if ([view canBecomeFirstResponder] && !view.hidden) {
return view;
}
for (UIView *v in view.subviews) {
UIResponder *subResponder = [self getNextFirstResponderInView:v];
if (subResponder) {
return subResponder;
}
}
return nil;
}
用法:添加UIToolbar到UITextField / UITextView(在类别或子类中):
- (void)addToolbarInputAccessoryView {
UIToolbar *toolbar = [[UIToolbar alloc] initWithFrame:CGRectZero];
UIBarButtonItem *prev = [[UIBarButtonItem alloc] initWithImage:[UIImage systemImageNamed:@"chevron.up"] style:UIBarButtonItemStylePlain target:self action:@selector(moveToPreviousFirstResponder)];
UIBarButtonItem *next = [[UIBarButtonItem alloc] initWithImage:[UIImage systemImageNamed:@"chevron.down"] style:UIBarButtonItemStylePlain target:self action:@selector(moveToNextFirstResponder)];
UIBarButtonItem *space = [[UIBarButtonItem alloc] initWithBarButtonSystemItem:UIBarButtonSystemItemFlexibleSpace target:nil action:nil];
UIBarButtonItem *done = [[UIBarButtonItem alloc] initWithBarButtonSystemItem:UIBarButtonSystemItemDone target:self action:@selector(hideKeyboard)];
toolbar.items = @[prev, next, space, done];
if ([[UITextField appearance] keyboardAppearance] == UIKeyboardAppearanceDark) {
toolbar.barStyle = UIBarStyleBlack;
toolbar.translucent = YES;
[toolbar setBarTintColor:[UIColor blackColor]];
[toolbar setTintColor:[UIColor whiteColor]];
}
[toolbar sizeToFit];
self.inputAccessoryView = toolbar;
}
- (void)hideKeyboard {
[self resignFirstResponder];
}
- (void)moveToNextFirstResponder {
UIResponder *next = [self getNextFirstResponder];
if (next) {
[next becomeFirstResponder];
}
else {
[self resignFirstResponder];
}
}
- (void)moveToPreviousFirstResponder {
UIResponder *prev = [self getPreviousFirstResponder];
if (prev) {
[prev becomeFirstResponder];
}
else {
[self resignFirstResponder];
}
}
没有usings标签,也没有为nextField/nextTextField添加属性,你可以尝试模拟TAB,其中"testInput"是你当前的活动字段:
if ([textInput isFirstResponder])
[textInput.superview.subviews enumerateObjectsAtIndexes:
[NSIndexSet indexSetWithIndexesInRange:
NSMakeRange([textInput.superview.subviews indexOfObject:textInput]+1,
[textInput.superview.subviews count]-[textInput.superview.subviews indexOfObject:textInput]-1)]
options:0 usingBlock:^(UIView *obj, NSUInteger idx, BOOL *stop) {
*stop = !obj.hidden && [obj becomeFirstResponder];
}];
if ([textInput isFirstResponder])
[textInput.superview.subviews enumerateObjectsAtIndexes:
[NSIndexSet indexSetWithIndexesInRange:
NSMakeRange(0,
[textInput.superview.subviews indexOfObject:textInput])]
options:0 usingBlock:^(UIView *obj, NSUInteger idx, BOOL *stop) {
*stop = !obj.hidden && [obj becomeFirstResponder];
}];