A small utility function in C to do this while solving a bit manipulation problem. This goes over the string checking each set bit using a mask (1< void printStringAsBinary(char * input) { char * temp = input; int i = 7, j =0;; int inputLen = strlen(input); /* Go over the string, check first bit..bit by bit and print 1 or 0 **/ for (j = 0; j < inputLen; j++) { printf("\n"); while (i>=0) { if (*temp & (1 << i)) { printf("1"); } else { printf("0"); } i--; } temp = temp+1; i = 7; printf("\n"); } }

A small utility function in C to do this while solving a bit manipulation problem. This goes over the string checking each set bit using a mask (1< void printStringAsBinary(char * input) { char * temp = input; int i = 7, j =0;; int inputLen = strlen(input); /* Go over the string, check first bit..bit by bit and print 1 or 0 **/ for (j = 0; j < inputLen; j++) { printf("\n"); while (i>=0) { if (*temp & (1 << i)) { printf("1"); } else { printf("0"); } i--; } temp = temp+1; i = 7; printf("\n"); } }

c

// Based on https://stackoverflow.com/a/112956/1438550

#include <stdio.h>
#include <stdint.h>

const char *int_to_binary_str(int x, int N_bits){
    static char b[512];
    char *p = b;
    b[0] = '\0';

    for(int i=(N_bits-1); i>=0; i--){
      *p++ = (x & (1<<i)) ? '1' : '0';
      if(!(i%4)) *p++ = ' ';
    }
    return b;
}

int main() {
  for(int i=31; i>=0; i--){
    printf("0x%08X %s \n", (1<<i), int_to_binary_str((1<<i), 32));
  }
  return 0;
}

期望的行为:

Run:
gcc -pthread -Wformat=0 -lm -o main main.c; ./main

Output:
0x80000000 1000 0000 0000 0000 0000 0000 0000 0000  
0x40000000 0100 0000 0000 0000 0000 0000 0000 0000  
0x20000000 0010 0000 0000 0000 0000 0000 0000 0000  
0x10000000 0001 0000 0000 0000 0000 0000 0000 0000  
0x08000000 0000 1000 0000 0000 0000 0000 0000 0000  
0x04000000 0000 0100 0000 0000 0000 0000 0000 0000  
0x02000000 0000 0010 0000 0000 0000 0000 0000 0000  
0x01000000 0000 0001 0000 0000 0000 0000 0000 0000  
0x00800000 0000 0000 1000 0000 0000 0000 0000 0000  
0x00400000 0000 0000 0100 0000 0000 0000 0000 0000  
0x00200000 0000 0000 0010 0000 0000 0000 0000 0000  
0x00100000 0000 0000 0001 0000 0000 0000 0000 0000  
0x00080000 0000 0000 0000 1000 0000 0000 0000 0000  
0x00040000 0000 0000 0000 0100 0000 0000 0000 0000  
0x00020000 0000 0000 0000 0010 0000 0000 0000 0000  
0x00010000 0000 0000 0000 0001 0000 0000 0000 0000  
0x00008000 0000 0000 0000 0000 1000 0000 0000 0000  
0x00004000 0000 0000 0000 0000 0100 0000 0000 0000  
0x00002000 0000 0000 0000 0000 0010 0000 0000 0000  
0x00001000 0000 0000 0000 0000 0001 0000 0000 0000  
0x00000800 0000 0000 0000 0000 0000 1000 0000 0000  
0x00000400 0000 0000 0000 0000 0000 0100 0000 0000  
0x00000200 0000 0000 0000 0000 0000 0010 0000 0000  
0x00000100 0000 0000 0000 0000 0000 0001 0000 0000  
0x00000080 0000 0000 0000 0000 0000 0000 1000 0000  
0x00000040 0000 0000 0000 0000 0000 0000 0100 0000  
0x00000020 0000 0000 0000 0000 0000 0000 0010 0000  
0x00000010 0000 0000 0000 0000 0000 0000 0001 0000  
0x00000008 0000 0000 0000 0000 0000 0000 0000 1000  
0x00000004 0000 0000 0000 0000 0000 0000 0000 0100  
0x00000002 0000 0000 0000 0000 0000 0000 0000 0010  
0x00000001 0000 0000 0000 0000 0000 0000 0000 0001 

void PrintBinary( int Value, int Places, char* TargetString)
{
    int Mask;

    Mask = 1 << Places;

    while( Places--) {
        Mask >>= 1; /* Preshift, because we did one too many above */
        *TargetString++ = (Value & Mask)?'1':'0';
    }
    *TargetString = 0; /* Null terminator for C string */
}

调用函数“拥有”字符串…:

char BinaryString[17];
...
PrintBinary( Value, 16, BinaryString);
printf( "yadda yadda %s yadda...\n", BinaryString);

取决于您的CPU, PrintBinary中的大多数操作呈现给一个或很少几个机器指令。

C标准库中没有这样输出二进制的格式化函数。printf家族支持的所有格式操作都是针对人类可读的文本。

const char* byte_to_binary(int x)
{
    static char b[sizeof(int)*8+1] = {0};
    int y;
    long long z;

    for (z = 1LL<<sizeof(int)*8-1, y = 0; z > 0; z >>= 1, y++) {
        b[y] = (((x & z) == z) ? '1' : '0');
    }
    b[y] = 0;

    return b;
}