我使用实体框架5.0代码第一;

public class Entity
 {
   [Key, DatabaseGenerated(DatabaseGeneratedOption.Identity)]
   public string EntityId { get; set;}
   public int FirstColumn  { get; set;}
   public int SecondColumn  { get; set;}
 }

我想让FirstColumn和SecondColumn的组合是唯一的。

例子:

Id  FirstColumn  SecondColumn 
1       1              1       = OK
2       2              1       = OK
3       3              3       = OK
5       3              1       = THIS OK 
4       3              3       = GRRRRR! HERE ERROR

有办法吗?

以下是我用来实现上述布局的代码:

.header { height: 50px; } .body { position: absolute; top: 50px; right: 0; bottom: 0; left: 0; display: flex; } .sidebar { width: 140px; } .main { flex: 1; display: flex; flex-direction: column; } .content { flex: 1; display: flex; } .column { padding: 20px; border-right: 1px solid #999; } <div class="header">Main header</div> <div class="body"> <div class="sidebar">Sidebar</div> <div class="main"> <div class="page-header">Page Header. Content columns are below.</div> <div class="content"> <div class="column">Column 1</div> <div class="column">Column 1</div> <div class="column">Column 1</div> </div> </div> </div>

我省略了用于样式化的代码。你可以在笔里看到所有这些。


上述方法是有效的,但是当内容区域的内容溢出时,会导致整个页面滚动。我只想让内容区域本身滚动,所以我在内容div中添加了overflow: auto。

现在的问题是,列本身并没有超出它们的父高度,所以边界也在那里被切断了。

这支笔显示了滚动问题。

如何将内容区域设置为独立滚动,同时仍然让其子区域超出内容框的高度?

我正在制作一个顶部固定导航条的响应式布局。下面有两列,一列是边栏(3),一列是内容(9),在桌面上看起来是这样的

导航条 [3] [9]

当我调整大小移动导航栏被压缩和隐藏,然后边栏堆叠在内容的顶部,就像这样:

navbar [3] [9]

我想在顶部的主要内容,所以我需要改变移动的顺序为:

navbar [9] [3]

我发现这篇文章涵盖了同样的观点,但公认的答案已被编辑,说解决方案不适用于当前版本的Bootstrap。

如何在移动设备上重新排序这些列?或者,我如何能得到边栏列表组到我的扩展导航栏?

这是我的代码:

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <!-- Latest compiled and minified CSS --> <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" integrity="sha384-BVYiiSIFeK1dGmJRAkycuHAHRg32OmUcww7on3RYdg4Va+PmSTsz/K68vbdEjh4u" crossorigin="anonymous"> <!-- Optional theme --> <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap-theme.min.css" integrity="sha384-rHyoN1iRsVXV4nD0JutlnGaslCJuC7uwjduW9SVrLvRYooPp2bWYgmgJQIXwl/Sp" crossorigin="anonymous"> <!-- Latest compiled and minified JavaScript --> <script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js" integrity="sha384-Tc5IQib027qvyjSMfHjOMaLkfuWVxZxUPnCJA7l2mCWNIpG9mGCD8wGNIcPD7Txa" crossorigin="anonymous"></script> <div class="navbar navbar-inverse navbar-static-top"> <div class="container"> <a href="#" class="navbar-brand">Brand Title</a> <button class="navbar-toggle" data-toggle="collapse" data-target=".navHeaderCollapse"> <span class="icon-bar"></span> <span class="icon-bar"></span> <span class="icon-bar"></span> </button> <div class="collapse navbar-collapse navHeaderCollapse"> <ul class="nav navbar-nav navbar-right"><!--original navbar--> <li class="active"><a href="#">Home</a></li> <li><a href="#">FAQ</a></li> </ul> </div> </div> </div><!--End Navbar Div--> <div class="container"> <div class="row"> <div class="col-lg-3"> <div class="list-group"> <a href="#" class="list-group-item"> <h4 class="list-group-item-heading">Lorem ipsum</h4> <p class="list-group-item-text">Lorem Ipsum is simply dummy text.</p></a> </div> </div><!--end sidebar--> <div class="col-lg-9"> <div class="panel panel-default"> <div class="panel-body"> <div class="page-header"> Main Content </div> </div> </div><!--end main content area-->

如何在熊猫身上做到这一点:

我在单个文本列上有一个函数extract_text_features,返回多个输出列。具体来说,该函数返回6个值。

该函数可以工作,但是似乎没有任何合适的返回类型(pandas DataFrame/ numpy数组/ Python列表),以便输出可以正确分配df。Ix [:,10:16] = df.textcol.map(extract_text_features)

所以我认为我需要回落到迭代与df.iterrows(),按此?

更新: 使用df.iterrows()迭代至少要慢20倍,因此我放弃并将该函数分解为6个不同的.map(lambda…)调用。

更新2:这个问题是在v0.11.0版本被问到的,在可用性df之前。在v0.16中改进了Apply或添加了df.assign()。因此,很多问题和答案都不太相关。

你能解释一下T: class, new()在下一行代码中是什么意思吗?

void Add<T>(T item) where T : class, new();

我找到了这个关于正则表达式的教程,虽然我直观地理解了“greedy”,“勉强”和“possession”限定词的作用,但我的理解中似乎有一个严重的漏洞。

具体来说,在下面的例子中:

Enter your regex: .*foo // Greedy qualifier
Enter input string to search: xfooxxxxxxfoo
I found the text "xfooxxxxxxfoo" starting at index 0 and ending at index 13.

Enter your regex: .*?foo // Reluctant qualifier
Enter input string to search: xfooxxxxxxfoo
I found the text "xfoo" starting at index 0 and ending at index 4.
I found the text "xxxxxxfoo" starting at index 4 and ending at index 13.

Enter your regex: .*+foo // Possessive qualifier
Enter input string to search: xfooxxxxxxfoo
No match found.

解释提到了吃掉整个输入字符串,字母被消耗,匹配器后退,最右边出现的“foo”被反流,等等。

不幸的是,尽管有这些美好的比喻,我还是不明白谁吃什么……您是否知道其他教程(简要地)解释正则表达式引擎如何工作?

或者,如果有人能用不同的措辞解释下一段,那将是非常感激的:

The first example uses the greedy quantifier .* to find "anything", zero or more times, followed by the letters "f", "o", "o". Because the quantifier is greedy, the .* portion of the expression first eats the entire input string. At this point, the overall expression cannot succeed, because the last three letters ("f", "o", "o") have already been consumed [by whom?]. So the matcher slowly backs off [from right-to-left?] one letter at a time until the rightmost occurrence of "foo" has been regurgitated [what does this mean?], at which point the match succeeds and the search ends. The second example, however, is reluctant, so it starts by first consuming [by whom?] "nothing". Because "foo" doesn't appear at the beginning of the string, it's forced to swallow [who swallows?] the first letter (an "x"), which triggers the first match at 0 and 4. Our test harness continues the process until the input string is exhausted. It finds another match at 4 and 13. The third example fails to find a match because the quantifier is possessive. In this case, the entire input string is consumed by .*+ [how?], leaving nothing left over to satisfy the "foo" at the end of the expression. Use a possessive quantifier for situations where you want to seize all of something without ever backing off [what does back off mean?]; it will outperform the equivalent greedy quantifier in cases where the match is not immediately found.

我需要关于正则表达式匹配与非贪婪选项的帮助。

匹配模式为:

<img\s.*>

要匹配的文本是:

<html>
<img src="test">
abc
<img
  src="a" src='a' a=b>
</html>

我在http://regexpal.com上测试

该表达式匹配从<img到last >的所有文本。我需要它与第一次遇到的>匹配在初始值<img之后,所以在这里我需要得到两个匹配而不是我得到的一个。

我尝试了所有非贪婪?的组合,没有成功。

我试图使用sed来清理url行来提取域。

所以从:

http://www.suepearson.co.uk/product/174/71/3816/

我想要:

http://www.suepearson.co.uk/

(不管后面有没有斜杠,都没有关系)

我试过:

 sed 's|\(http:\/\/.*?\/\).*|\1|'

And(转义非贪婪量词)

sed 's|\(http:\/\/.*\?\/\).*|\1|'

但我似乎不能让非贪婪量词(?)工作,所以它总是匹配整个字符串。

我在一个类中发现了这一行代码,我必须修改:

::Configuration * tmpCo = m_configurationDB;//pointer to current db

我不知道类名前的双冒号是什么意思。如果没有,我会读到:声明tmpCo作为类Configuration对象的指针…但是前面的双冒号把我弄糊涂了。

我还发现:

typedef ::config::set ConfigSet;

我有一个大的HTML文件,有很多标记,看起来像这样:

<p class="MsoNormal" style="margin: 0in 0in 0pt;">
  <span style="font-size: small; font-family: Times New Roman;">stuff here</span>
</p>

我试图做一个Vim搜索和替换,以摆脱所有class=""和style=""但我有麻烦使匹配不贪婪。

我的第一次尝试是这样的

%s/style=".*?"//g

但维姆似乎不喜欢?不幸的是,移除?使匹配过于贪婪。

如何让我的火柴不贪婪?