您可以使用这里引用的.some方法。

some()方法测试数组中是否至少有一个元素 通过由提供的函数实现的测试。

// test cases const str1 = 'hi hello, how do you do?'; const str2 = 'regular string'; const str3 = 'hello there'; // do the test strings contain these terms? const conditions = ["hello", "hi", "howdy"]; // run the tests against every element in the array const test1 = conditions.some(el => str1.includes(el)); const test2 = conditions.some(el => str2.includes(el)); // strictly check that contains 1 and only one match const test3 = conditions.reduce((a,c) => a + str3.includes(c), 0) == 1; // display results console.log(`Loose matching, 2 matches "${str1}" => ${test1}`); console.log(`Loose matching, 0 matches "${str2}" => ${test2}`); console.log(`Exact matching, 1 matches "${str3}" => ${test3}`);

另外，正如下面一位用户提到的那样，匹配上面提到的“恰好一个”外观也很有趣(这是OP要求的)。这可以类似地用.reduce计算交点，然后检查它们是否等于1。

const givenArray = ['Hi, how are you'， 'how are you'， 'howdy, how you doing'] const includeValues = ["hello"， "hi"， "howdy"] const filteredStrArray = givenArray。filter(str => includeValues)str.toLowerCase().includes(value))) console.log (filteredStrArray);

扩展字符串本机原型:

if (!String.prototype.contains) {
    Object.defineProperty(String.prototype, 'contains', {
        value(patterns) {
            if (!Array.isArray(patterns)) {
                return false;
            }

            let value = 0;
            for (let i = 0; i < patterns.length; i++) {
                const pattern = patterns[i];
                value = value + this.includes(pattern);
            }
            return (value === 1);
        }
    });
}

允许你做以下事情:

console.log('Hi, hope you like this option'.toLowerCase().contains(["hello", "hi", "howdy"])); // True

您可以使用这里引用的.some方法。

some()方法测试数组中是否至少有一个元素 通过由提供的函数实现的测试。

// test cases const str1 = 'hi hello, how do you do?'; const str2 = 'regular string'; const str3 = 'hello there'; // do the test strings contain these terms? const conditions = ["hello", "hi", "howdy"]; // run the tests against every element in the array const test1 = conditions.some(el => str1.includes(el)); const test2 = conditions.some(el => str2.includes(el)); // strictly check that contains 1 and only one match const test3 = conditions.reduce((a,c) => a + str3.includes(c), 0) == 1; // display results console.log(`Loose matching, 2 matches "${str1}" => ${test1}`); console.log(`Loose matching, 0 matches "${str2}" => ${test2}`); console.log(`Exact matching, 1 matches "${str3}" => ${test3}`);

另外，正如下面一位用户提到的那样，匹配上面提到的“恰好一个”外观也很有趣(这是OP要求的)。这可以类似地用.reduce计算交点，然后检查它们是否等于1。

另一个!

let result const givenStr = 'A, X' //values separated by comma or space. const allowed = ['A', 'B'] const given = givenStr.split(/[\s,]+/).filter(v => v) console.log('given (array):', given) // given contains none or only allowed values: result = given.reduce((acc, val) => { return acc && allowed.includes(val) }, true) console.log('given contains none or only allowed values:', result) // given contains at least one allowed value: result = given.reduce((acc, val) => { return acc || allowed.includes(val) }, false) console.log('given contains at least one allowed value:', result)

即使有且只有一个条件为真，它也能工作:

var str = "bonjour le monde vive le javascript";
var arr = ['bonjour','europe', 'c++'];

function contains(target, pattern){
    var value = 0;
    pattern.forEach(function(word){
      value = value + target.includes(word);
    });
    return (value === 1)
}

console.log(contains(str, arr));