这取决于你在什么上下文中使用它。 我在一个对象上使用它来检查是否有任何键有一个空字符串或null作为它的值，它工作

Object.values(object).includes('' || null)

您可以使用这里引用的.some方法。

some()方法测试数组中是否至少有一个元素 通过由提供的函数实现的测试。

// test cases const str1 = 'hi hello, how do you do?'; const str2 = 'regular string'; const str3 = 'hello there'; // do the test strings contain these terms? const conditions = ["hello", "hi", "howdy"]; // run the tests against every element in the array const test1 = conditions.some(el => str1.includes(el)); const test2 = conditions.some(el => str2.includes(el)); // strictly check that contains 1 and only one match const test3 = conditions.reduce((a,c) => a + str3.includes(c), 0) == 1; // display results console.log(`Loose matching, 2 matches "${str1}" => ${test1}`); console.log(`Loose matching, 0 matches "${str2}" => ${test2}`); console.log(`Exact matching, 1 matches "${str3}" => ${test3}`);

另外，正如下面一位用户提到的那样，匹配上面提到的“恰好一个”外观也很有趣(这是OP要求的)。这可以类似地用.reduce计算交点，然后检查它们是否等于1。

即使有且只有一个条件为真，它也能工作:

var str = "bonjour le monde vive le javascript";
var arr = ['bonjour','europe', 'c++'];

function contains(target, pattern){
    var value = 0;
    pattern.forEach(function(word){
      value = value + target.includes(word);
    });
    return (value === 1)
}

console.log(contains(str, arr));

不是最好的答案，也不是最干净的答案，但我认为它更宽容。 比如，如果你想对所有的支票使用相同的过滤器。 实际上.filter()与数组一起工作并返回一个过滤后的数组(我发现这也更容易使用)。

var str1 = 'hi, how do you do?';
var str2 = 'regular string';
var conditions = ["hello", "hi", "howdy"];

// Solve the problem
var res1 = [str1].filter(data => data.includes(conditions[0]) || data.includes(conditions[1]) || data.includes(conditions[2]));
var res2 = [str2].filter(data => data.includes(conditions[0]) || data.includes(conditions[1]) || data.includes(conditions[2]));

console.log(res1); // ["hi, how do you do?"]
console.log(res2); // []


// More useful in this case
var text = [str1, str2, "hello world"];

// Apply some filters on data
var res3 = text.filter(data => data.includes(conditions[0]) && data.includes(conditions[2]));
// You may use again the same filters for a different check
var res4 = text.filter(data => data.includes(conditions[0]) || data.includes(conditions[1]));

console.log(res3); // []
console.log(res4); // ["hi, how do you do?", "hello world"]

1线路方案:

字符串/ Array.prototype。包括('hello' || 'hi' || 'howdy');

let words = 'cucumber, mercy, introduction, shot, howdy'
words.includes('hi' || 'howdy' || 'hello') // true
words.includes('hi' || 'hello') // false

使用includes()，没有，但你可以通过test()实现REGEX:

var value = /hello|hi|howdy/.test(str);

或者，如果词语来自动态来源:

var words = ['hello', 'hi', 'howdy'];
var value = new RegExp(words.join('|')).test(str);

REGEX方法是一个更好的主意，因为它允许您将单词匹配为实际单词，而不是其他单词的子字符串。你只需要边界标记\b这个词，那么:

var str = 'hilly';
var value = str.includes('hi'); //true, even though the word 'hi' isn't found
var value = /\bhi\b/.test(str); //false - 'hi' appears but not as its own word