是否有方法将JSON内容反序列化为c#动态类型?为了使用DataContractJsonSerializer,最好跳过创建一堆类。


当前回答

你想要的DynamicJSONObject对象包含在ASP. web . helpers .dll中。NET Web Pages包,它是WebMatrix的一部分。

其他回答

我在我的代码中使用这样的代码,它工作得很好

using System.Web.Script.Serialization;
JavaScriptSerializer oJS = new JavaScriptSerializer();
RootObject oRootObject = new RootObject();
oRootObject = oJS.Deserialize<RootObject>(Your JSon String);

获取一个ExpandoObject:

using Newtonsoft.Json;
using Newtonsoft.Json.Converters;

Container container = JsonConvert.Deserialize<Container>(jsonAsString, new ExpandoObjectConverter());

用Newtonsoft创建动态对象。Json真的很棒。

//json is your string containing the JSON value
dynamic data = JsonConvert.DeserializeObject<dynamic>(json);

现在您可以像访问普通对象一样访问数据对象。这是我们当前的JSON对象示例:

{ "ID":123,"Name":"Jack","Numbers":[1, 2, 3] }

这是你在反序列化后访问它的方式:

data.ID //Retrieve the int
data.Name //Retrieve the string
data.Numbers[0] //Retrieve the first element in the array

如何解析简单的JSON内容与动态& JavaScriptSerializer

请添加System.Web.Extensions的引用,并使用System.Web.Script.Serialization添加此命名空间;在前:

public static void EasyJson()
{
    var jsonText = @"{
        ""some_number"": 108.541,
        ""date_time"": ""2011-04-13T15:34:09Z"",
        ""serial_number"": ""SN1234""
    }";

    var jss = new JavaScriptSerializer();
    var dict = jss.Deserialize<dynamic>(jsonText);

    Console.WriteLine(dict["some_number"]);
    Console.ReadLine();
}

如何解析嵌套和复杂的json与动态和JavaScriptSerializer

请添加System.Web.Extensions的引用,并使用System.Web.Script.Serialization添加此命名空间;在前:

public static void ComplexJson()
{
    var jsonText = @"{
        ""some_number"": 108.541,
        ""date_time"": ""2011-04-13T15:34:09Z"",
        ""serial_number"": ""SN1234"",
        ""more_data"": {
            ""field1"": 1.0,
            ""field2"": ""hello""
        }
    }";

    var jss = new JavaScriptSerializer();
    var dict = jss.Deserialize<dynamic>(jsonText);

    Console.WriteLine(dict["some_number"]);
    Console.WriteLine(dict["more_data"]["field2"]);
    Console.ReadLine();
}

我做了一个使用Expando对象的DynamicJsonConverter的新版本。我使用了expando对象,因为我想使用Json.NET将动态序列化回JSON。

using System;
using System.Collections;
using System.Collections.Generic;
using System.Collections.ObjectModel;
using System.Dynamic;
using System.Web.Script.Serialization;

public static class DynamicJson
{
    public static dynamic Parse(string json)
    {
        JavaScriptSerializer jss = new JavaScriptSerializer();
        jss.RegisterConverters(new JavaScriptConverter[] { new DynamicJsonConverter() });

        dynamic glossaryEntry = jss.Deserialize(json, typeof(object)) as dynamic;
        return glossaryEntry;
    }

    class DynamicJsonConverter : JavaScriptConverter
    {
        public override object Deserialize(IDictionary<string, object> dictionary, Type type, JavaScriptSerializer serializer)
        {
            if (dictionary == null)
                throw new ArgumentNullException("dictionary");

            var result = ToExpando(dictionary);

            return type == typeof(object) ? result : null;
        }

        private static ExpandoObject ToExpando(IDictionary<string, object> dictionary)
        {
            var result = new ExpandoObject();
            var dic = result as IDictionary<String, object>;

            foreach (var item in dictionary)
            {
                var valueAsDic = item.Value as IDictionary<string, object>;
                if (valueAsDic != null)
                {
                    dic.Add(item.Key, ToExpando(valueAsDic));
                    continue;
                }
                var arrayList = item.Value as ArrayList;
                if (arrayList != null && arrayList.Count > 0)
                {
                    dic.Add(item.Key, ToExpando(arrayList));
                    continue;
                }

                dic.Add(item.Key, item.Value);
            }
            return result;
        }

        private static ArrayList ToExpando(ArrayList obj)
        {
            ArrayList result = new ArrayList();

            foreach (var item in obj)
            {
                var valueAsDic = item as IDictionary<string, object>;
                if (valueAsDic != null)
                {
                    result.Add(ToExpando(valueAsDic));
                    continue;
                }

                var arrayList = item as ArrayList;
                if (arrayList != null && arrayList.Count > 0)
                {
                    result.Add(ToExpando(arrayList));
                    continue;
                }

                result.Add(item);
            }
            return result;
        }

        public override IDictionary<string, object> Serialize(object obj, JavaScriptSerializer serializer)
        {
            throw new NotImplementedException();
        }

        public override IEnumerable<Type> SupportedTypes
        {
            get { return new ReadOnlyCollection<Type>(new List<Type>(new[] { typeof(object) })); }
        }
    }
}