在Java 8中,Stream.map()和Stream.flatMap()方法之间有什么区别?


当前回答

.map用于A -> B映射

Stream.of("dog", "cat")              // stream of 2 Strings
    .map(s -> s.length())            // stream of 2 Integers: [3, 3]

它将任意项A转换为任意项b


.flatMap用于A ->流< B>连接

Stream.of("dog", "cat")             // stream of 2 Strings
    .flatMapToInt(s -> s.chars())   // stream of 6 ints:      [d, o, g, c, a, t]

it——1将任何项A转换为Stream< B>,然后——2将所有流连接到一个(平面)流。Javadoc


注1:虽然后面的例子是一个原语流(IntStream),而不是一个对象流(stream),但它仍然说明了. flatmap的思想。

注意2:尽管有这个名字,String.chars()方法返回的是整数。所以实际的集合将是:[100,111,103,99,97,116] ,其中100是“d”的代码,111是“o”的代码,等等。同样,为了说明目的,它被表示为[d, o, g, c, a, t]。

其他回答

传递给流的函数。Map必须返回一个对象。这意味着输入流中的每个对象都会导致输出流中的一个对象。

传递给流的函数。flatMap为每个对象返回一个流。这意味着该函数可以为每个输入对象返回任意数量的对象(包括none)。然后将结果流连接到一个输出流。

map和flatMap都可以应用于一个<T>的流,它们都返回一个<R>的流。不同之处在于map操作为每个输入值生成一个输出值,而flatMap操作为每个输入值生成任意数量(零个或多个)值。

这反映在每个操作的参数中。

map操作接受一个函数,该函数针对输入流中的每个值被调用,并产生一个结果值,该结果值被发送到输出流。

The flatMap operation takes a function that conceptually wants to consume one value and produce an arbitrary number of values. However, in Java, it's cumbersome for a method to return an arbitrary number of values, since methods can return only zero or one value. One could imagine an API where the mapper function for flatMap takes a value and returns an array or a List of values, which are then sent to the output. Given that this is the streams library, a particularly apt way to represent an arbitrary number of return values is for the mapper function itself to return a stream! The values from the stream returned by the mapper are drained from the stream and are passed to the output stream. The "clumps" of values returned by each call to the mapper function are not distinguished at all in the output stream, thus the output is said to have been "flattened."

典型的用法是flatMap的mapper函数返回Stream.empty(),如果它想发送零值,或者类似于Stream。(a, b, c)如果它想返回几个值。当然,任何流都可以返回。

Oracle关于Optional的文章强调了map和flatmap的区别:

String version = computer.map(Computer::getSoundcard)
                  .map(Soundcard::getUSB)
                  .map(USB::getVersion)
                  .orElse("UNKNOWN");

Unfortunately, this code doesn't compile. Why? The variable computer is of type Optional<Computer>, so it is perfectly correct to call the map method. However, getSoundcard() returns an object of type Optional. This means the result of the map operation is an object of type Optional<Optional<Soundcard>>. As a result, the call to getUSB() is invalid because the outermost Optional contains as its value another Optional, which of course doesn't support the getUSB() method. With streams, the flatMap method takes a function as an argument, which returns another stream. This function is applied to each element of a stream, which would result in a stream of streams. However, flatMap has the effect of replacing each generated stream by the contents of that stream. In other words, all the separate streams that are generated by the function get amalgamated or "flattened" into one single stream. What we want here is something similar, but we want to "flatten" a two-level Optional into one. Optional also supports a flatMap method. Its purpose is to apply the transformation function on the value of an Optional (just like the map operation does) and then flatten the resulting two-level Optional into a single one. So, to make our code correct, we need to rewrite it as follows using flatMap:

String version = computer.flatMap(Computer::getSoundcard)
                   .flatMap(Soundcard::getUSB)
                   .map(USB::getVersion)
                   .orElse("UNKNOWN");

第一个flatMap确保返回Optional<Soundcard> 而不是一个Optional<Optional<Soundcard>>,和第二个flatMap 实现相同的目的,返回Optional<USB>。注意 第三个调用只需要一个map(),因为getVersion()返回一个 字符串而不是可选对象。

http://www.oracle.com/technetwork/articles/java/java8-optional-2175753.html

流操作flatMap和map接受函数作为输入。

flatMap期望该函数为流的每个元素返回一个新的流,并返回一个流,该流结合了该函数为每个元素返回的流的所有元素。换句话说,使用flatMap,对于来自源的每个元素,函数将创建多个元素。http://www.zoftino.com/java-stream-examples#flatmap-operation

Map期望函数返回一个转换后的值,并返回一个包含转换后元素的新流。换句话说,使用map,对于来自源的每个元素,函数将创建一个转换后的元素。 http://www.zoftino.com/java-stream-examples#map-operation

map() takes a Stream and transform it to another Stream. It applies a function on each element of Stream and store return value into new Stream. It does not flatten the stream. But flatMap() is the combination of a map and a flat operation i.e, it applies a function to elements as well as flatten them. 2) map() is used for transformation only, but flatMap() is used for both transformation and flattening. please read more here. https://javaint4bytes.blogspot.com/2022/11/stream-flatmap-in-java-with-examples.html