我有一个React组件,在组件的渲染方法中,我有这样的东西:
render() {
return (
<div>
<div>
// removed for brevity
</div>
{ switch(...) {} }
<div>
// removed for brevity
</div>
</div>
);
}
Now the point is that I have two div elements, one at the top and one at the bottom, that are fixed. In the middle I want to have a switch statement, and according to a value in my state I want to render a different component. So basically, I want the two div elements to be fixed always, and just in the middle to render a different component each time. I'm using this to implement a multi-step payment procedure). Though, as is the code currently it doesn't work, as it gives me an error saying that switch is unexpected. Any ideas how to achieve what I want?
import React from 'react';
import ListView from './ListView';
import TableView from './TableView';
function DataView({
currView,
data,
onSelect,
onChangeStatus,
viewTodo,
editTodo,
deleteTodo,
}) {
return (
<div>
{(function () {
switch (currView) {
case 'table':
return (
<TableView
todos={data}
onSelect={onSelect}
onChangeStatus={onChangeStatus}
viewTodo={viewTodo}
editTodo={editTodo}
deleteTodo={deleteTodo}
/>
);
case 'list':
return (
<ListView
todos={data}
onSelect={onSelect}
onChangeStatus={onChangeStatus}
viewTodo={viewTodo}
editTodo={editTodo}
deleteTodo={deleteTodo}
/>
);
default:
break;
}
})()}
</div>
);
}
export default DataView;
你不能在渲染中有开关。放置访问一个元素的对象文字的伪切换方法并不理想,因为它会导致所有视图都要处理,并且可能导致在该状态下不存在的道具的依赖错误。
这里有一个很好的干净的方法来做到这一点,不需要每个视图提前渲染:
render () {
const viewState = this.getViewState();
return (
<div>
{viewState === ViewState.NO_RESULTS && this.renderNoResults()}
{viewState === ViewState.LIST_RESULTS && this.renderResults()}
{viewState === ViewState.SUCCESS_DONE && this.renderCompleted()}
</div>
)
如果视图状态的条件不只基于一个简单的属性——比如每行有多个条件,那么枚举和getViewState函数封装条件是分离条件逻辑和清理呈现的好方法。