我很惊讶，没有答案会提到RxJava2的解决方案。它真的很简单，提供了一个简单的方法来设置计时器在Android。

首先你需要设置Gradle依赖，如果你还没有这样做:

implementation "io.reactivex.rxjava2:rxjava:2.x.y"

(将x和y替换为当前版本号)

因为我们只有一个简单的，非重复的TASK，我们可以使用Completable对象:

Completable.timer(2, TimeUnit.SECONDS, Schedulers.computation())
        .observeOn(AndroidSchedulers.mainThread())
        .subscribe(() -> {
            // Timer finished, do something...
        });

对于重复TASK，你可以用类似的方式使用Observable:

Observable.interval(2, TimeUnit.SECONDS, Schedulers.computation())
        .observeOn(AndroidSchedulers.mainThread())
        .subscribe(tick -> {
            // called every 2 seconds, do something...
        }, throwable -> {
            // handle error
        });

Schedulers.computation()确保我们的计时器在后台线程上运行，. observveon (AndroidSchedulers.mainThread())意味着我们在计时器结束后运行的代码将在主线程上完成。

为了避免不必要的内存泄漏，您应该确保在Activity/Fragment被销毁时取消订阅。

他是更简单的解决方案，工作在我的应用程序。

  public class MyActivity extends Acitivity {

    TextView myTextView;
    boolean someCondition=true;

     @Override
        protected void onCreate(Bundle savedInstanceState) {
            super.onCreate(savedInstanceState);
            setContentView(R.layout.my_activity);

            myTextView = (TextView) findViewById(R.id.refreshing_field);

            //starting our task which update textview every 1000 ms
            new RefreshTask().execute();



        }

    //class which updates our textview every second

    class RefreshTask extends AsyncTask {

            @Override
            protected void onProgressUpdate(Object... values) {
                super.onProgressUpdate(values);
                String text = String.valueOf(System.currentTimeMillis());
                myTextView.setText(text);

            }

            @Override
            protected Object doInBackground(Object... params) {
                while(someCondition) {
                    try {
                        //sleep for 1s in background...
                        Thread.sleep(1000);
                        //and update textview in ui thread
                        publishProgress();
                    } catch (InterruptedException e) {
                        e.printStackTrace(); 

                };
                return null;
            }
        }
    }

void method(boolean u,int max)
{
    uu=u;
    maxi=max;
    if (uu==true)
    { 
        CountDownTimer uy = new CountDownTimer(maxi, 1000) 
  {
            public void onFinish()
            {
                text.setText("Finish"); 
            }

            @Override
            public void onTick(long l) {
                String currentTimeString=DateFormat.getTimeInstance().format(new Date());
                text.setText(currentTimeString);
            }
        }.start();
    }

    else{text.setText("Stop ");
}

enter code here
Thread th=new Thread(new Runnable() {
        @Override
        public void run() {
            try { for(int i=0;i<5;i++) {
                b1.setText(""+i);
                Thread.sleep(5000);
                runOnUiThread(new Runnable() {
                    @Override
                    public void run() {
                        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
       pp();
       
                        }
                    }
                });
            }} catch (InterruptedException e) {
                e.printStackTrace();
            }
        }
    });
    th.start();

这是一个定时器的简单代码:

Timer timer = new Timer();
TimerTask t = new TimerTask() {       
    @Override
    public void run() {

        System.out.println("1");
    }
};
timer.scheduleAtFixedRate(t,1000,1000);

我认为你可以用Rx方法来做:

 timerSubscribe = Observable.interval(1, TimeUnit.SECONDS)
            .subscribeOn(Schedulers.io())
            .observeOn(AndroidSchedulers.mainThread())
            .subscribe(new Action1<Long>() {
                @Override
                public void call(Long aLong) {
                      //TODO do your stuff
                }
            });

然后取消这个:

timerSubscribe.unsubscribe();

接收定时器 http://reactivex.io/documentation/operators/timer.html