let page,limit,skip,lastPage, query;
 page = req.params.page *1 || 1;  //This is the page,fetch from the server
 limit = req.params.limit * 1 || 1; //  This is the limit ,it also fetch from the server
 skip = (page - 1) * limit;   // Number of skip document
 lastPage = page * limit;   //last index 
 counts = await userModel.countDocuments() //Number of document in the collection

query = query.skip(skip).limit(limit) //current page

const paginate = {}

//For previous page
if(skip > 0) {
   paginate.prev = {
       page: page - 1,
       limit: limit
} 
//For next page
 if(lastPage < counts) {
  paginate.next = {
     page: page + 1,
     limit: limit
}
results = await query //Here is the final results of the query.

你可以像这样串起来:

var query = Model.find().sort('mykey', 1).skip(2).limit(5)

使用exec执行查询

query.exec(callback);

您可以像这样编写查询。

mySchema.find().skip((page-1)*per_page).limit(per_page).exec(function(err, articles) {
        if (err) {
            return res.status(400).send({
                message: err
            });
        } else {
            res.json(articles);
        }
    });

Page:来自客户端作为请求参数的页码。 Per_page:每页显示的结果数目

如果你正在使用MEAN堆栈，下面的博客文章提供了很多信息，在前端使用angular-UI引导和在后端使用猫鼬跳过和限制方法创建分页。

参见:https://techpituwa.wordpress.com/2015/06/06/mean-js-pagination-with-angular-ui-bootstrap/

在用Rodolphe提供的信息仔细研究了Mongoose API后，我想出了这个解决方案:

MyModel.find(query, fields, { skip: 10, limit: 5 }, function(err, results) { ... });

您也可以使用下面的代码行

per_page = parseInt(req.query.per_page) || 10
page_no = parseInt(req.query.page_no) || 1
var pagination = {
  limit: per_page ,
  skip:per_page * (page_no - 1)
}
users = await User.find({<CONDITION>}).limit(pagination.limit).skip(pagination.skip).exec()

这段代码将在最新版本的mongo中工作

let page,limit,skip,lastPage, query;
 page = req.params.page *1 || 1;  //This is the page,fetch from the server
 limit = req.params.limit * 1 || 1; //  This is the limit ,it also fetch from the server
 skip = (page - 1) * limit;   // Number of skip document
 lastPage = page * limit;   //last index 
 counts = await userModel.countDocuments() //Number of document in the collection

query = query.skip(skip).limit(limit) //current page

const paginate = {}

//For previous page
if(skip > 0) {
   paginate.prev = {
       page: page - 1,
       limit: limit
} 
//For next page
 if(lastPage < counts) {
  paginate.next = {
     page: page + 1,
     limit: limit
}
results = await query //Here is the final results of the query.