我想用JavaScript格式化价格。我想要一个函数,它将浮点作为参数,并返回如下格式的字符串:

"$ 2,500.00"

我该怎么做?


当前回答

这里是我见过的最好的JavaScript货币格式化程序:

Number.prototype.formatMoney = function(decPlaces, thouSeparator, decSeparator) {
    var n = this,
        decPlaces = isNaN(decPlaces = Math.abs(decPlaces)) ? 2 : decPlaces,
        decSeparator = decSeparator == undefined ? "." : decSeparator,
        thouSeparator = thouSeparator == undefined ? "," : thouSeparator,
        sign = n < 0 ? "-" : "",
        i = parseInt(n = Math.abs(+n || 0).toFixed(decPlaces)) + "",
        j = (j = i.length) > 3 ? j % 3 : 0;
    return sign + (j ? i.substr(0, j) + thouSeparator : "") + i.substr(j).replace(/(\d{3})(?=\d)/g, "$1" + thouSeparator) + (decPlaces ? decSeparator + Math.abs(n - i).toFixed(decPlaces).slice(2) : "");
};

它被重新格式化并从这里借用:如何将数字格式化为货币字符串

您必须提供您自己的货币代号(您使用了$以上)。

这样调用它(尽管注意,参数默认为2、逗号和句点,因此如果这是您的首选,则不需要提供任何参数):

var myMoney = 3543.75873;
var formattedMoney = '$' + myMoney.formatMoney(2, ',', '.'); // "$3,543.76"

其他回答

快速快捷的解决方案(适用于任何地方!)

(12345.67).toFixed(2).replace(/\d(?=(\d{3})+\.)/g, '$&,');  // 12,345.67

此解决方案背后的思想是用第一个匹配和逗号替换匹配的部分,即“$&,”。匹配是使用前瞻方法完成的。您可以将表达式读为“匹配一个数字,如果它后面跟着三个数字集(一个或多个)和一个点的序列”。

测验:

1        --> "1.00"
12       --> "12.00"
123      --> "123.00"
1234     --> "1,234.00"
12345    --> "12,345.00"
123456   --> "123,456.00"
1234567  --> "1,234,567.00"
12345.67 --> "12,345.67"

演示:http://jsfiddle.net/hAfMM/9571/


扩展短解决方案

您还可以扩展Number对象的原型,以添加对任意数量的小数[0..n]和数字组大小[0..x]的额外支持:

/**
 * Number.prototype.format(n, x)
 * 
 * @param integer n: length of decimal
 * @param integer x: length of sections
 */
Number.prototype.format = function(n, x) {
    var re = '\\d(?=(\\d{' + (x || 3) + '})+' + (n > 0 ? '\\.' : '$') + ')';
    return this.toFixed(Math.max(0, ~~n)).replace(new RegExp(re, 'g'), '$&,');
};

1234..format();           // "1,234"
12345..format(2);         // "12,345.00"
123456.7.format(3, 2);    // "12,34,56.700"
123456.789.format(2, 4);  // "12,3456.79"

演示/测试:http://jsfiddle.net/hAfMM/435/


超扩展短解决方案

在此超级扩展版本中,您可以设置不同的分隔符类型:

/**
 * Number.prototype.format(n, x, s, c)
 * 
 * @param integer n: length of decimal
 * @param integer x: length of whole part
 * @param mixed   s: sections delimiter
 * @param mixed   c: decimal delimiter
 */
Number.prototype.format = function(n, x, s, c) {
    var re = '\\d(?=(\\d{' + (x || 3) + '})+' + (n > 0 ? '\\D' : '$') + ')',
        num = this.toFixed(Math.max(0, ~~n));

    return (c ? num.replace('.', c) : num).replace(new RegExp(re, 'g'), '$&' + (s || ','));
};

12345678.9.format(2, 3, '.', ',');  // "12.345.678,90"
123456.789.format(4, 4, ' ', ':');  // "12 3456:7890"
12345678.9.format(0, 3, '-');       // "12-345-679"

演示/测试:http://jsfiddle.net/hAfMM/612/

因为每个问题都需要单线解决方案:

Number.prototype.formatCurrency = function() { return this.toFixed(2).toString().split(/[-.]/).reverse().reduceRight(function (t, c, i) { return (i == 2) ? '-' + t : (i == 1) ? t + c.replace(/(\d)(?=(\d{3})+$)/g, '$1,') : t + '.' + c; }, '$'); }

这很容易针对不同的地区进行更改。只需将“$1”更改为“$1.”和“.”转换为“”、“”和。以数字表示。可以通过更改末尾的“$”来更改货币符号。

或者,如果您有ES6,您可以使用默认值声明函数:

Number.prototype.formatCurrency = function(thou = ',', dec = '.', sym = '$') { return this.toFixed(2).toString().split(/[-.]/).reverse().reduceRight(function (t, c, i) { return (i == 2) ? '-' + t : (i == 1) ? t + c.replace(/(\d)(?=(\d{3})+$)/g, '$1' + thou) : t + dec + c; }, sym); }

console.log((4215.57).formatCurrency())
$4,215.57
console.log((4216635.57).formatCurrency('.', ','))
$4.216.635,57
console.log((4216635.57).formatCurrency('.', ',', "\u20AC"))
€4.216.635,57

哦,它也适用于负数:

console.log((-6635.574).formatCurrency('.', ',', "\u20AC"))
-€6.635,57
console.log((-1066.507).formatCurrency())
-$1,066.51

当然,你不必有货币符号:

console.log((1234.586).formatCurrency(',','.',''))
1,234.59
console.log((-7890123.456).formatCurrency(',','.',''))
-7,890,123.46
console.log((1237890.456).formatCurrency('.',',',''))
1.237.890,46

乔纳森·M的代码对我来说太复杂了,所以我重写了它,在Firefox v30上获得了30%的速度提升,在Chrome v35上获得了60%的速度提升(http://jsperf.com/number-formating2):

Number.prototype.formatNumber = function(decPlaces, thouSeparator, decSeparator) {
    decPlaces = isNaN(decPlaces = Math.abs(decPlaces)) ? 2 : decPlaces;
    decSeparator = decSeparator == undefined ? "." : decSeparator;
    thouSeparator = thouSeparator == undefined ? "," : thouSeparator;

    var n = this.toFixed(decPlaces);
    if (decPlaces) {
        var i = n.substr(0, n.length - (decPlaces + 1));
        var j = decSeparator + n.substr(-decPlaces);
    } else {
        i = n;
        j = '';
    }

    function reverse(str) {
        var sr = '';
        for (var l = str.length - 1; l >= 0; l--) {
            sr += str.charAt(l);
        }
        return sr;
    }

    if (parseInt(i)) {
        i = reverse(reverse(i).replace(/(\d{3})(?=\d)/g, "$1" + thouSeparator));
    }
    return i + j;
};

用法:

var sum = 123456789.5698;
var formatted = '$' + sum.formatNumber(2, ',', '.'); // "$123,456,789.57"

下面是Patrick Desjardins(别名Daok)代码,添加了一些注释和一些小改动:

/*
decimal_sep: character used as decimal separator, it defaults to '.' when omitted
thousands_sep: char used as thousands separator, it defaults to ',' when omitted
*/
Number.prototype.toMoney = function(decimals, decimal_sep, thousands_sep)
{
   var n = this,
   c = isNaN(decimals) ? 2 : Math.abs(decimals), // If decimal is zero we must take it. It means the user does not want to show any decimal
   d = decimal_sep || '.', // If no decimal separator is passed, we use the dot as default decimal separator (we MUST use a decimal separator)

   /*
   According to [https://stackoverflow.com/questions/411352/how-best-to-determine-if-an-argument-is-not-sent-to-the-javascript-function]
   the fastest way to check for not defined parameter is to use typeof value === 'undefined'
   rather than doing value === undefined.
   */
   t = (typeof thousands_sep === 'undefined') ? ',' : thousands_sep, // If you don't want to use a thousands separator you can pass empty string as thousands_sep value

   sign = (n < 0) ? '-' : '',

   // Extracting the absolute value of the integer part of the number and converting to string
   i = parseInt(n = Math.abs(n).toFixed(c)) + '',

   j = ((j = i.length) > 3) ? j % 3 : 0;
   return sign + (j ? i.substr(0, j) + t : '') + i.substr(j).replace(/(\d{3})(?=\d)/g, "$1" + t) + (c ? d + Math.abs(n - i).toFixed(c).slice(2) : '');
}

这里有一些测试:

// Some tests (do not forget parenthesis when using negative numbers and number with no decimals)
alert(123456789.67392.toMoney() + '\n' + 123456789.67392.toMoney(3) + '\n' + 123456789.67392.toMoney(0) + '\n' + (123456).toMoney() + '\n' + (123456).toMoney(0) + '\n' + 89.67392.toMoney() + '\n' + (89).toMoney());

// Some tests (do not forget parenthesis when using negative numbers and number with no decimals)
alert((-123456789.67392).toMoney() + '\n' + (-123456789.67392).toMoney(-3));

次要变化包括:

移动了一点Math.abs(小数),只有当不是NaN时才能执行。decimal_sep不能再是空字符串(必须使用某种十进制分隔符)我们使用typeof thousand_sep===“undefined”,如How best to determine if a argument is not send to JavaScript function中所建议的不需要(+n||0),因为这是Number对象

JSFiddle公司

使用regexp的更快方法:

Number.prototype.toMonetaryString = function() {
  var n = this.toFixed(2), m;
  //var = this.toFixed(2).replace(/\./, ','); For comma separator
  // with a space for thousands separator
  while ((m = n.replace(/(\d)(\d\d\d)\b/g, '$1 $2')) != n)
      n = m;
  return m;
}

String.prototype.fromMonetaryToNumber = function(s) {
  return this.replace(/[^\d-]+/g, '')/100;
}