是否有一个聪明的(即优化)方法重命名一个关键在javascript对象?
一种非优化的方式是:
o[ new_key ] = o[ old_key ];
delete o[ old_key ];
是否有一个聪明的(即优化)方法重命名一个关键在javascript对象?
一种非优化的方式是:
o[ new_key ] = o[ old_key ];
delete o[ old_key ];
当前回答
function iterate(instance) {
for (let child of instance.tree_down) iterate(child);
instance.children = instance.tree_down;
delete instance.tree_down;
}
iterate(link_hierarchy);
console.log(link_hierarchy);
其他回答
我的方法,改编好的@Mulhoon typescript帖子,用于更改多个键:
const renameKeys = <
TOldKey extends keyof T,
TNewkey extends string,
T extends Record<string, unknown>
>(
keys: {[ key: string]: TNewkey extends TOldKey ? never : TNewkey },
obj: T
) => Object
.keys(obj)
.reduce((acc, key) => ({
...acc,
...{ [keys[key] || key]: obj[key] }
}), {});
renameKeys({id: 'value', name: 'label'}, {id: 'toto_id', name: 'toto', age: 35});
您可以使用实用程序来处理这个问题。
npm i paix
import { paix } from 'paix';
const source_object = { FirstName: "Jhon", LastName: "Doe", Ignored: true };
const replacement = { FirstName: 'first_name', LastName: 'last_name' };
const modified_object = paix(source_object, replacement);
console.log(modified_object);
// { Ignored: true, first_name: 'Jhon', last_name: 'Doe' };
如果你想保留迭代顺序(插入的顺序),这里有一个建议:
const renameObjectKey = (object, oldName, newName) => {
const updatedObject = {}
for(let key in object) {
if (key === oldName) {
newObject[newName] = object[key]
} else {
newObject[key] = object[key]
}
}
object = updatedObject
}
一般来说,如果你想获得一个新的对象(不改变原来的对象),根据keyMap重命名键-你可以使用以下基于lodash mapKeys的实现:
const {mapKeys} = require('lodash');
const renameKeys = (obj, keyMap) => _.mapKeys(obj, (value, key) => keyMap[key] || key);
使用的例子:
renameKeys({a: 1, b: 2, c: 3}, {c: 'p', a: 'm'})
> {m: 1, b: 2, p: 3}
下面是创建具有重命名键的新对象的示例。
let x = { id: "checkout", name: "git checkout", description: "checkout repository" };
let renamed = Object.entries(x).reduce((u, [n, v]) => {
u[`__${n}`] = v;
return u;
}, {});