比如,我有一个脚本,用这行代码调用:

./myscript -vfd ./foo/bar/someFile -o /fizz/someOtherFile

或者这个:

./myscript -v -f -d -o /fizz/someOtherFile ./foo/bar/someFile 

什么是公认的解析方式,以便在每种情况下(或两者的某种组合)$v、$f和$d都将设置为true,而$outFile将等于/fiz/someOtherFile?


当前回答

我最终实现了公认答案的dash(或/bin/sh)版本,基本上不使用数组:

while [[ $# -gt 0 ]]; do
    case "$1" in
    -v|--verbose) verbose=1; shift;;
    -o|--output) if [[ $# -gt 1 && "$2" != -* ]]; then
            file=$2; shift 2
        else
            echo "-o requires file-path" 1>&2; exit 1
        fi ;;
    --)
        while [[ $# -gt 0 ]]; do BACKUP="$BACKUP;$1"; shift; done
        break;;
    *)
        BACKUP="$BACKUP;$1"
        shift
        ;;
    esac
done
# Restore unused arguments.
while [ -n "$BACKUP" ] ; do
    [ ! -z "${BACKUP%%;*}" ] && set -- "$@" "${BACKUP%%;*}"
    [ "$BACKUP" = "${BACKUP/;/}" ] && break
    BACKUP="${BACKUP#*;}"
done

其他回答

使用bash模块中的模块“参数”

例子:

#!/bin/bash
. import.sh log arguments

NAME="world"

parse_arguments "-n|--name)NAME;S" -- "$@" || {
  error "Cannot parse command line."
  exit 1
}

info "Hello, $NAME!"

混合位置和基于标志的参数

--param=arg(等于分隔符)

在位置参数之间自由混合标志:

./script.sh dumbo 127.0.0.1 --environment=production -q -d
./script.sh dumbo --environment=production 127.0.0.1 --quiet -d

可以用相当简洁的方法完成:

# process flags
pointer=1
while [[ $pointer -le $# ]]; do
   param=${!pointer}
   if [[ $param != "-"* ]]; then ((pointer++)) # not a parameter flag so advance pointer
   else
      case $param in
         # paramter-flags with arguments
         -e=*|--environment=*) environment="${param#*=}";;
                  --another=*) another="${param#*=}";;

         # binary flags
         -q|--quiet) quiet=true;;
                 -d) debug=true;;
      esac

      # splice out pointer frame from positional list
      [[ $pointer -gt 1 ]] \
         && set -- ${@:1:((pointer - 1))} ${@:((pointer + 1)):$#} \
         || set -- ${@:((pointer + 1)):$#};
   fi
done

# positional remain
node_name=$1
ip_address=$2

--参数arg(空格分隔)

通常情况下,不混合--flag=value和--flag值样式会更清晰。

./script.sh dumbo 127.0.0.1 --environment production -q -d

这读起来有点冒险,但仍然有效

./script.sh dumbo --environment production 127.0.0.1 --quiet -d

来源

# process flags
pointer=1
while [[ $pointer -le $# ]]; do
   if [[ ${!pointer} != "-"* ]]; then ((pointer++)) # not a parameter flag so advance pointer
   else
      param=${!pointer}
      ((pointer_plus = pointer + 1))
      slice_len=1

      case $param in
         # paramter-flags with arguments
         -e|--environment) environment=${!pointer_plus}; ((slice_len++));;
                --another) another=${!pointer_plus}; ((slice_len++));;

         # binary flags
         -q|--quiet) quiet=true;;
                 -d) debug=true;;
      esac

      # splice out pointer frame from positional list
      [[ $pointer -gt 1 ]] \
         && set -- ${@:1:((pointer - 1))} ${@:((pointer + $slice_len)):$#} \
         || set -- ${@:((pointer + $slice_len)):$#};
   fi
done

# positional remain
node_name=$1
ip_address=$2

我最终实现了公认答案的dash(或/bin/sh)版本,基本上不使用数组:

while [[ $# -gt 0 ]]; do
    case "$1" in
    -v|--verbose) verbose=1; shift;;
    -o|--output) if [[ $# -gt 1 && "$2" != -* ]]; then
            file=$2; shift 2
        else
            echo "-o requires file-path" 1>&2; exit 1
        fi ;;
    --)
        while [[ $# -gt 0 ]]; do BACKUP="$BACKUP;$1"; shift; done
        break;;
    *)
        BACKUP="$BACKUP;$1"
        shift
        ;;
    esac
done
# Restore unused arguments.
while [ -n "$BACKUP" ] ; do
    [ ! -z "${BACKUP%%;*}" ] && set -- "$@" "${BACKUP%%;*}"
    [ "$BACKUP" = "${BACKUP/;/}" ] && break
    BACKUP="${BACKUP#*;}"
done
# As long as there is at least one more argument, keep looping
while [[ $# -gt 0 ]]; do
    key="$1"
    case "$key" in
        # This is a flag type option. Will catch either -f or --foo
        -f|--foo)
        FOO=1
        ;;
        # Also a flag type option. Will catch either -b or --bar
        -b|--bar)
        BAR=1
        ;;
        # This is an arg value type option. Will catch -o value or --output-file value
        -o|--output-file)
        shift # past the key and to the value
        OUTPUTFILE="$1"
        ;;
        # This is an arg=value type option. Will catch -o=value or --output-file=value
        -o=*|--output-file=*)
        # No need to shift here since the value is part of the same string
        OUTPUTFILE="${key#*=}"
        ;;
        *)
        # Do whatever you want with extra options
        echo "Unknown option '$key'"
        ;;
    esac
    # Shift after checking all the cases to get the next option
    shift
done

这使您既可以使用空格分隔的选项/值,也可以使用相等的定义值。

因此,您可以使用以下命令运行脚本:

./myscript --foo -b -o /fizz/file.txt

以及:

./myscript -f --bar -o=/fizz/file.txt

并且两者应该具有相同的最终结果。

赞成的意见:

允许-arg=value和-arg-value适用于bash中可以使用的任何arg名称意思是-a或-arg或--arg或-ar-g或其他纯粹的狂欢。无需学习/使用getopt或getopts

欺骗:

无法组合参数意思是没有-abc。您必须执行-a-b-c

假设我们创建一个名为test_args.sh的shell脚本,如下所示

#!/bin/sh
until [ $# -eq 0 ]
do
  name=${1:1}; shift;
  if [[ -z "$1" || $1 == -* ]] ; then eval "export $name=true"; else eval "export $name=$1"; shift; fi  
done
echo "year=$year month=$month day=$day flag=$flag"

运行以下命令后:

sh test_args.sh  -year 2017 -flag  -month 12 -day 22 

输出将是:

year=2017 month=12 day=22 flag=true