比如,我有一个脚本,用这行代码调用:
./myscript -vfd ./foo/bar/someFile -o /fizz/someOtherFile
或者这个:
./myscript -v -f -d -o /fizz/someOtherFile ./foo/bar/someFile
什么是公认的解析方式,以便在每种情况下(或两者的某种组合)$v、$f和$d都将设置为true,而$outFile将等于/fiz/someOtherFile?
比如,我有一个脚本,用这行代码调用:
./myscript -vfd ./foo/bar/someFile -o /fizz/someOtherFile
或者这个:
./myscript -v -f -d -o /fizz/someOtherFile ./foo/bar/someFile
什么是公认的解析方式,以便在每种情况下(或两者的某种组合)$v、$f和$d都将设置为true,而$outFile将等于/fiz/someOtherFile?
当前回答
我最终实现了公认答案的dash(或/bin/sh)版本,基本上不使用数组:
while [[ $# -gt 0 ]]; do
case "$1" in
-v|--verbose) verbose=1; shift;;
-o|--output) if [[ $# -gt 1 && "$2" != -* ]]; then
file=$2; shift 2
else
echo "-o requires file-path" 1>&2; exit 1
fi ;;
--)
while [[ $# -gt 0 ]]; do BACKUP="$BACKUP;$1"; shift; done
break;;
*)
BACKUP="$BACKUP;$1"
shift
;;
esac
done
# Restore unused arguments.
while [ -n "$BACKUP" ] ; do
[ ! -z "${BACKUP%%;*}" ] && set -- "$@" "${BACKUP%%;*}"
[ "$BACKUP" = "${BACKUP/;/}" ] && break
BACKUP="${BACKUP#*;}"
done
其他回答
使用bash模块中的模块“参数”
例子:
#!/bin/bash
. import.sh log arguments
NAME="world"
parse_arguments "-n|--name)NAME;S" -- "$@" || {
error "Cannot parse command line."
exit 1
}
info "Hello, $NAME!"
混合位置和基于标志的参数
--param=arg(等于分隔符)
在位置参数之间自由混合标志:
./script.sh dumbo 127.0.0.1 --environment=production -q -d
./script.sh dumbo --environment=production 127.0.0.1 --quiet -d
可以用相当简洁的方法完成:
# process flags
pointer=1
while [[ $pointer -le $# ]]; do
param=${!pointer}
if [[ $param != "-"* ]]; then ((pointer++)) # not a parameter flag so advance pointer
else
case $param in
# paramter-flags with arguments
-e=*|--environment=*) environment="${param#*=}";;
--another=*) another="${param#*=}";;
# binary flags
-q|--quiet) quiet=true;;
-d) debug=true;;
esac
# splice out pointer frame from positional list
[[ $pointer -gt 1 ]] \
&& set -- ${@:1:((pointer - 1))} ${@:((pointer + 1)):$#} \
|| set -- ${@:((pointer + 1)):$#};
fi
done
# positional remain
node_name=$1
ip_address=$2
--参数arg(空格分隔)
通常情况下,不混合--flag=value和--flag值样式会更清晰。
./script.sh dumbo 127.0.0.1 --environment production -q -d
这读起来有点冒险,但仍然有效
./script.sh dumbo --environment production 127.0.0.1 --quiet -d
来源
# process flags
pointer=1
while [[ $pointer -le $# ]]; do
if [[ ${!pointer} != "-"* ]]; then ((pointer++)) # not a parameter flag so advance pointer
else
param=${!pointer}
((pointer_plus = pointer + 1))
slice_len=1
case $param in
# paramter-flags with arguments
-e|--environment) environment=${!pointer_plus}; ((slice_len++));;
--another) another=${!pointer_plus}; ((slice_len++));;
# binary flags
-q|--quiet) quiet=true;;
-d) debug=true;;
esac
# splice out pointer frame from positional list
[[ $pointer -gt 1 ]] \
&& set -- ${@:1:((pointer - 1))} ${@:((pointer + $slice_len)):$#} \
|| set -- ${@:((pointer + $slice_len)):$#};
fi
done
# positional remain
node_name=$1
ip_address=$2
我最终实现了公认答案的dash(或/bin/sh)版本,基本上不使用数组:
while [[ $# -gt 0 ]]; do
case "$1" in
-v|--verbose) verbose=1; shift;;
-o|--output) if [[ $# -gt 1 && "$2" != -* ]]; then
file=$2; shift 2
else
echo "-o requires file-path" 1>&2; exit 1
fi ;;
--)
while [[ $# -gt 0 ]]; do BACKUP="$BACKUP;$1"; shift; done
break;;
*)
BACKUP="$BACKUP;$1"
shift
;;
esac
done
# Restore unused arguments.
while [ -n "$BACKUP" ] ; do
[ ! -z "${BACKUP%%;*}" ] && set -- "$@" "${BACKUP%%;*}"
[ "$BACKUP" = "${BACKUP/;/}" ] && break
BACKUP="${BACKUP#*;}"
done
# As long as there is at least one more argument, keep looping
while [[ $# -gt 0 ]]; do
key="$1"
case "$key" in
# This is a flag type option. Will catch either -f or --foo
-f|--foo)
FOO=1
;;
# Also a flag type option. Will catch either -b or --bar
-b|--bar)
BAR=1
;;
# This is an arg value type option. Will catch -o value or --output-file value
-o|--output-file)
shift # past the key and to the value
OUTPUTFILE="$1"
;;
# This is an arg=value type option. Will catch -o=value or --output-file=value
-o=*|--output-file=*)
# No need to shift here since the value is part of the same string
OUTPUTFILE="${key#*=}"
;;
*)
# Do whatever you want with extra options
echo "Unknown option '$key'"
;;
esac
# Shift after checking all the cases to get the next option
shift
done
这使您既可以使用空格分隔的选项/值,也可以使用相等的定义值。
因此,您可以使用以下命令运行脚本:
./myscript --foo -b -o /fizz/file.txt
以及:
./myscript -f --bar -o=/fizz/file.txt
并且两者应该具有相同的最终结果。
赞成的意见:
允许-arg=value和-arg-value适用于bash中可以使用的任何arg名称意思是-a或-arg或--arg或-ar-g或其他纯粹的狂欢。无需学习/使用getopt或getopts
欺骗:
无法组合参数意思是没有-abc。您必须执行-a-b-c
假设我们创建一个名为test_args.sh的shell脚本,如下所示
#!/bin/sh
until [ $# -eq 0 ]
do
name=${1:1}; shift;
if [[ -z "$1" || $1 == -* ]] ; then eval "export $name=true"; else eval "export $name=$1"; shift; fi
done
echo "year=$year month=$month day=$day flag=$flag"
运行以下命令后:
sh test_args.sh -year 2017 -flag -month 12 -day 22
输出将是:
year=2017 month=12 day=22 flag=true