比如,我有一个脚本,用这行代码调用:

./myscript -vfd ./foo/bar/someFile -o /fizz/someOtherFile

或者这个:

./myscript -v -f -d -o /fizz/someOtherFile ./foo/bar/someFile 

什么是公认的解析方式,以便在每种情况下(或两者的某种组合)$v、$f和$d都将设置为true,而$outFile将等于/fiz/someOtherFile?


当前回答

这里有一个getopts,它用最少的代码实现解析,并允许您在一种情况下使用eval和substring定义要提取的内容。

基本上eval“local key='val'”

function myrsync() {

        local backup=("${@}") args=(); while [[ $# -gt 0 ]]; do k="$1";
                case "$k" in
                    ---sourceuser|---sourceurl|---targetuser|---targeturl|---file|---exclude|---include)
                        eval "local ${k:3}='${2}'"; shift; shift    # Past two arguments
                    ;;
                    *)  # Unknown option  
                        args+=("$1"); shift;                        # Past argument only
                    ;;                                              
                esac                                                
        done; set -- "${backup[@]}"                                 # Restore $@


        echo "${sourceurl}"
}

在这里,将变量声明为局部变量,而不是全局变量。

调用为:

myrsync ---sourceurl http://abc.def.g ---sourceuser myuser ... 

${k:3}基本上是一个从键中删除第一个---的子字符串。

其他回答

当我尝试这个问题时,上面的答案似乎有点bug——这是我发现更强大的解决方案:

boolean_arg=""
arg_with_value=""

while [[ $# -gt 0 ]]
do
key="$1"
case $key in
    -b|--boolean-arg)
    boolean_arg=true
    shift
    ;;
    -a|--arg-with-value)
    arg_with_value="$2"
    shift
    shift
    ;;
    -*)
    echo "Unknown option: $1"
    exit 1
    ;;
    *)
    arg_num=$(( $arg_num + 1 ))
    case $arg_num in
        1)
        first_normal_arg="$1"
        shift
        ;;
        2)
        second_normal_arg="$1"
        shift
        ;;
        *)
        bad_args=TRUE
    esac
    ;;
esac
done

# Handy to have this here when adding arguments to
# see if they're working. Just edit the '0' to be '1'.
if [[ 0 == 1 ]]; then
    echo "first_normal_arg: $first_normal_arg"
    echo "second_normal_arg: $second_normal_arg"
    echo "boolean_arg: $boolean_arg"
    echo "arg_with_value: $arg_with_value"
    exit 0
fi

if [[ $bad_args == TRUE || $arg_num < 2 ]]; then
    echo "Usage: $(basename "$0") <first-normal-arg> <second-normal-arg> [--boolean-arg] [--arg-with-value VALUE]"
    exit 1
fi

我使用它从末尾迭代key=>值。循环后捕获第一个可选参数。

用法为/script.sh可选的第一个参数-key value-key2 value2

#!/bin/sh

a=$(($#-1))
b=$(($#))
while [ $a -gt 0 ]; do
    eval 'key="$'$a'"; value="$'$b'"'
    echo "$key => $value"
    b=$(($b-2))
    a=$(($a-2))
done
unset a b key value

[ $(($#%2)) -ne 0 ] && echo "first_arg = $1"

当然,你可以从左到右做一些改变。

此代码段显示key=>值对和第一个参数(如果存在)。

#!/bin/sh

a=$((1+$#%2))
b=$((1+$a))

[ $(($#%2)) -ne 0 ] && echo "first_arg = $1"

while [ $a -lt $# ]; do
    eval 'key="$'$a'"; value="$'$b'"'
    echo "$key => $value"
    b=$(($b+2))
    a=$(($a+2))
done

unset a b key value

测试了100000个参数,速度很快。

您还可以从左到右迭代key=>value和第一个可选arg,而不使用eval:

#!/bin/sh

a=$(($#%2))
b=0

[ $a -eq 1 ] && echo "first_arg = $1"

for value; do
    if [ $b -gt $a -a $(($b%2)) -ne $a ]; then
        echo "$key => $value"
    fi
    key="$value"
    b=$((1+$b))
done

unset a b key value

如果您正在制作可与其他实用程序互换的脚本,下面的灵活性可能很有用。

以下任一项:

command -x=myfilename.ext --another_switch 

Or:

command -x myfilename.ext --another_switch

代码如下:

STD_IN=0

prefix=""
key=""
value=""
for keyValue in "$@"
do
  case "${prefix}${keyValue}" in
    -i=*|--input_filename=*)  key="-i";     value="${keyValue#*=}";; 
    -ss=*|--seek_from=*)      key="-ss";    value="${keyValue#*=}";;
    -t=*|--play_seconds=*)    key="-t";     value="${keyValue#*=}";;
    -|--stdin)                key="-";      value=1;;
    *)                                      value=$keyValue;;
  esac
  case $key in
    -i) MOVIE=$(resolveMovie "${value}");  prefix=""; key="";;
    -ss) SEEK_FROM="${value}";          prefix=""; key="";;
    -t)  PLAY_SECONDS="${value}";           prefix=""; key="";;
    -)   STD_IN=${value};                   prefix=""; key="";; 
    *)   prefix="${keyValue}=";;
  esac
done

根据这里的其他答案,这是我的版本:

#!/bin/bash
set -e

function parse() {
    for arg in "$@"; do # transform long options to short ones
        shift
        case "$arg" in
            "--name") set -- "$@" "-n" ;;
            "--verbose") set -- "$@" "-v" ;;
            *) set -- "$@" "$arg"
        esac
    done

    while getopts "n:v" optname  # left to ":" are flags that expect a value, right to the ":" are flags that expect nothing
    do
        case "$optname" in
            "n") name=${OPTARG} ;;
            "v") verbose=true ;;
        esac
    done
    shift "$((OPTIND-1))" # shift out all the already processed options
}


parse "$@"
echo "hello $name"
if [ ! -z $verbose ]; then echo 'nice to meet you!'; fi

用法:

$ ./parse.sh
hello
$ ./parse.sh -n YOUR_NAME
hello YOUR_NAME
$ ./parse.sh -n YOUR_NAME -v
hello YOUR_NAME
nice to meet you!
$ ./parse.sh -v -n YOUR_NAME
hello YOUR_NAME
nice to meet you!
$ ./parse.sh -v
hello 
nice to meet you!

我使用optget和optgets的组合来解析带或不带参数的短选项和长选项,甚至是非选项(不带-或-的选项):

# catch wrong options and move non-options to the end of the string
args=$(getopt -l "$opt_long" "$opt_short" "$@" 2> >(sed -e 's/^/stderr/g')) || echo -n "Error: " && echo "$args" | grep -oP "(?<=^stderr).*" && exit 1
mapfile -t args < <(xargs -n1 <<< "$(echo "$args" | sed -E "s/(--[^ ]+) /\1=/g")" )
set -- "${args[@]}"

# parse short and long options
while getopts "$opt_short-:" opt; do
  ...
done

# remove all parsed options from $@
shift $((OPTIND-1)

这样,我就可以使用$opt_verbose这样的变量访问所有选项,而非选项可以通过默认变量$1、$2等访问:

echo "help:$opt_help"
echo "file:$opt_file"
echo "verbose:$opt_verbose"
echo "long_only:$opt_long_only"
echo "short_only:$opt_s"
echo "path:$1"
echo "mail:$2"

其中一个主要特点是,我能够以完全随机的顺序传递所有选项和非选项:

#             $opt_file     $1        $2          $opt_... $opt_... $opt_...
# /demo.sh --file=file.txt /dir info@example.com -V -h --long_only=yes -s
help:1
file:file.txt
verbose:1
long_only:yes
short_only:1
path:/dir
mail:info@example.com

更多详情:https://stackoverflow.com/a/74275254/318765