如何在Python中连接两个列表?
例子:
listone = [1, 2, 3]
listtwo = [4, 5, 6]
预期结果:
>>> joinedlist
[1, 2, 3, 4, 5, 6]
如何在Python中连接两个列表?
例子:
listone = [1, 2, 3]
listtwo = [4, 5, 6]
预期结果:
>>> joinedlist
[1, 2, 3, 4, 5, 6]
当前回答
您可以简单地使用+或+=运算符,如下所示:
a = [1, 2, 3]
b = [4, 5, 6]
c = a + b
Or:
c = []
a = [1, 2, 3]
b = [4, 5, 6]
c += (a + b)
此外,如果希望合并列表中的值是唯一的,可以执行以下操作:
c = list(set(a + b))
其他回答
使用+运算符组合列表:
listone = [1, 2, 3]
listtwo = [4, 5, 6]
joinedlist = listone + listtwo
输出:
>>> joinedlist
[1, 2, 3, 4, 5, 6]
如果要以排序形式合并这两个列表,可以使用heapq库中的merge函数。
from heapq import merge
a = [1, 2, 4]
b = [2, 4, 6, 7]
print list(merge(a, b))
这很简单,我认为它甚至在教程中显示了:
>>> listone = [1,2,3]
>>> listtwo = [4,5,6]
>>>
>>> listone + listtwo
[1, 2, 3, 4, 5, 6]
如果不能使用加号运算符(+),则可以使用运算符导入:
import operator
listone = [1,2,3]
listtwo = [4,5,6]
result = operator.add(listone, listtwo)
print(result)
>>> [1, 2, 3, 4, 5, 6]
或者,您也可以使用__add__dunder函数:
listone = [1,2,3]
listtwo = [4,5,6]
result = list.__add__(listone, listtwo)
print(result)
>>> [1, 2, 3, 4, 5, 6]
值得注意的是,itertools.chain函数接受可变数量的参数:
>>> l1 = ['a']; l2 = ['b', 'c']; l3 = ['d', 'e', 'f']
>>> [i for i in itertools.chain(l1, l2)]
['a', 'b', 'c']
>>> [i for i in itertools.chain(l1, l2, l3)]
['a', 'b', 'c', 'd', 'e', 'f']
如果输入是可迭代的(元组、列表、生成器等),则可以使用from_iteable类方法:
>>> il = [['a'], ['b', 'c'], ['d', 'e', 'f']]
>>> [i for i in itertools.chain.from_iterable(il)]
['a', 'b', 'c', 'd', 'e', 'f']