给定字符串“ThisStringHasNoSpacesButItDoesHaveCapitals”,什么是在大写字母之前添加空格的最好方法。所以结尾字符串是"This string Has No space But It Does Have大写"

下面是我使用正则表达式的尝试

System.Text.RegularExpressions.Regex.Replace(value, "[A-Z]", " $0")

当前回答

这个正则表达式在每个大写字母前放置一个空格字符:

using System.Text.RegularExpressions;

const string myStringWithoutSpaces = "ThisIsAStringWithoutSpaces";
var myStringWithSpaces = Regex.Replace(myStringWithoutSpaces, "([A-Z])([a-z]*)", " $1$2");

注意前面的空间,如果“$1$2”,这是可以完成的。

结果如下:

"This Is A String Without Spaces"

其他回答

具有fold的实现,也称为Aggregate:

    public static string SpaceCapitals(this string arg) =>
       new string(arg.Aggregate(new List<Char>(),
                      (accum, x) => 
                      {
                          if (Char.IsUpper(x) &&
                              accum.Any() &&
                              // prevent double spacing
                              accum.Last() != ' ' &&
                              // prevent spacing acronyms (ASCII, SCSI)
                              !Char.IsUpper(accum.Last()))
                          {
                              accum.Add(' ');
                          }

                          accum.Add(x);

                          return accum;
                      }).ToArray());

除了请求之外,这个实现还正确地保存了开头、内部、结尾空格和首字母缩写,例如,

" SpacedWord " => " Spaced Word ",  

"Inner Space" => "Inner Space",  

"SomeACRONYM" => "Some ACRONYM".

在小写字母、大写字母或数字后添加空格的简单方法。

    string AddSpacesToSentence(string value, bool spaceLowerChar = true, bool spaceDigitChar = true, bool spaceSymbolChar = false)
    {
        var result = "";

        for (int i = 0; i < value.Length; i++)
        {
            char currentChar = value[i];
            char nextChar = value[i < value.Length - 1 ? i + 1 : value.Length - 1];

            if (spaceLowerChar && char.IsLower(currentChar) && !char.IsLower(nextChar))
            {
                result += value[i] + " ";
            }
            else if (spaceDigitChar && char.IsDigit(currentChar) && !char.IsDigit(nextChar))
            {
                result += value[i] + " ";
            }
            else if(spaceSymbolChar && char.IsSymbol(currentChar) && !char.IsSymbol(nextChar))
            {
                result += value[i];
            }
            else
            {
                result += value[i];
            }
        }

        return result;
    }

欢迎来到Unicode

所有这些解决方案对于现代文本来说本质上都是错误的。你需要使用能理解大小写的东西。由于Bob要求使用其他语言,我将为Perl提供两种语言。

我提供了四种解决方案,从最坏到最好。只有最好的人才是对的。其他人都有问题。下面是一个测试运行,向您展示什么可行,什么不可行,以及在哪里。我用了下划线,这样你们就能看到空格放在了哪里,我把所有错的地方都标记了出来。

Testing TheLoneRanger
               Worst:    The_Lone_Ranger
               Ok:       The_Lone_Ranger
               Better:   The_Lone_Ranger
               Best:     The_Lone_Ranger
Testing MountMᶜKinleyNationalPark
     [WRONG]   Worst:    Mount_MᶜKinley_National_Park
     [WRONG]   Ok:       Mount_MᶜKinley_National_Park
     [WRONG]   Better:   Mount_MᶜKinley_National_Park
               Best:     Mount_Mᶜ_Kinley_National_Park
Testing ElÁlamoTejano
     [WRONG]   Worst:    ElÁlamo_Tejano
               Ok:       El_Álamo_Tejano
               Better:   El_Álamo_Tejano
               Best:     El_Álamo_Tejano
Testing TheÆvarArnfjörðBjarmason
     [WRONG]   Worst:    TheÆvar_ArnfjörðBjarmason
               Ok:       The_Ævar_Arnfjörð_Bjarmason
               Better:   The_Ævar_Arnfjörð_Bjarmason
               Best:     The_Ævar_Arnfjörð_Bjarmason
Testing IlCaffèMacchiato
     [WRONG]   Worst:    Il_CaffèMacchiato
               Ok:       Il_Caffè_Macchiato
               Better:   Il_Caffè_Macchiato
               Best:     Il_Caffè_Macchiato
Testing MisterDženanLjubović
     [WRONG]   Worst:    MisterDženanLjubović
     [WRONG]   Ok:       MisterDženanLjubović
               Better:   Mister_Dženan_Ljubović
               Best:     Mister_Dženan_Ljubović
Testing OleKingHenryⅧ
     [WRONG]   Worst:    Ole_King_HenryⅧ
     [WRONG]   Ok:       Ole_King_HenryⅧ
     [WRONG]   Better:   Ole_King_HenryⅧ
               Best:     Ole_King_Henry_Ⅷ
Testing CarlosⅤºElEmperador
     [WRONG]   Worst:    CarlosⅤºEl_Emperador
     [WRONG]   Ok:       CarlosⅤº_El_Emperador
     [WRONG]   Better:   CarlosⅤº_El_Emperador
               Best:     Carlos_Ⅴº_El_Emperador

顺便说一下,这里几乎所有人都选择了第一种方式,即标记为“最差”的方式。少数人选择了标记为“OK”的第二种方式。但是在我之前没有人告诉过你如何做“更好”或“最好”的方法。

下面是带有四个方法的测试程序:

#!/usr/bin/env perl
use utf8;
use strict;
use warnings;

# First I'll prove these are fine variable names:
my (
    $TheLoneRanger              ,
    $MountMᶜKinleyNationalPark  ,
    $ElÁlamoTejano              ,
    $TheÆvarArnfjörðBjarmason   ,
    $IlCaffèMacchiato           ,
    $MisterDženanLjubović         ,
    $OleKingHenryⅧ              ,
    $CarlosⅤºElEmperador        ,
);

# Now I'll load up some string with those values in them:
my @strings = qw{
    TheLoneRanger
    MountMᶜKinleyNationalPark
    ElÁlamoTejano
    TheÆvarArnfjörðBjarmason
    IlCaffèMacchiato
    MisterDženanLjubović
    OleKingHenryⅧ
    CarlosⅤºElEmperador
};

my($new, $best, $ok);
my $mask = "  %10s   %-8s  %s\n";

for my $old (@strings) {
    print "Testing $old\n";
    ($best = $old) =~ s/(?<=\p{Lowercase})(?=[\p{Uppercase}\p{Lt}])/_/g;

    ($new = $old) =~ s/(?<=[a-z])(?=[A-Z])/_/g;
    $ok = ($new ne $best) && "[WRONG]";
    printf $mask, $ok, "Worst:", $new;

    ($new = $old) =~ s/(?<=\p{Ll})(?=\p{Lu})/_/g;
    $ok = ($new ne $best) && "[WRONG]";
    printf $mask, $ok, "Ok:", $new;

    ($new = $old) =~ s/(?<=\p{Ll})(?=[\p{Lu}\p{Lt}])/_/g;
    $ok = ($new ne $best) && "[WRONG]";
    printf $mask, $ok, "Better:", $new;

    ($new = $old) =~ s/(?<=\p{Lowercase})(?=[\p{Uppercase}\p{Lt}])/_/g;
    $ok = ($new ne $best) && "[WRONG]";
    printf $mask, $ok, "Best:", $new;
}

当你能在这个数据集上得到与“最佳”相同的分数时,你就知道你做对了。在那之前,你还没有。这里没有人比“还行”做得更好,大多数人都做得“最差”。我期待看到有人发布正确的ℂ代码。

我注意到,StackOverflow的高亮代码是悲惨的笨拙再次。他们所做的一切都和这里提到的其他糟糕的方法一样(大部分但不是全部)。难道不是早就该让ASCII停止使用了吗?这已经没有意义了,假装这是你的全部是大错特错的。这会导致糟糕的代码。

对于任何正在寻找回答这个问题的c++函数的人,您可以使用下面的方法。这是模仿@Binary Worrier给出的答案。这种方法只是自动保留首字母缩略词。

using namespace std;

void AddSpacesToSentence(string& testString)
        stringstream ss;
        ss << testString.at(0);
        for (auto it = testString.begin() + 1; it != testString.end(); ++it )
        {
            int index = it - testString.begin();
            char c = (*it);
            if (isupper(c))
            {
                char prev = testString.at(index - 1);
                if (isupper(prev))
                {
                    if (index < testString.length() - 1)
                    {
                        char next = testString.at(index + 1);
                        if (!isupper(next) && next != ' ')
                        {
                            ss << ' ';
                        }
                    }
                }
                else if (islower(prev)) 
                {
                   ss << ' ';
                }
            }

            ss << c;
        }

        cout << ss.str() << endl;

我为这个函数使用的测试字符串,结果是:

"helloWorld" -> "helloWorld" "HelloWorld" -> "HelloWorld" "HelloABCWorld" -> "HelloABCWorld" "HelloWorldABC" -> "HelloWorldABC" "ABCHelloWorld" -> "ABCHelloWorld" " abc hello world " -> " abc hello world " " abchelloworld " -> " abchelloworld " " a " -> " a "

在Ruby中,通过Regexp:

"FooBarBaz".gsub(/(?!^)(?=[A-Z])/, ' ') # => "Foo Bar Baz"