给定字符串“ThisStringHasNoSpacesButItDoesHaveCapitals”,什么是在大写字母之前添加空格的最好方法。所以结尾字符串是"This string Has No space But It Does Have大写"

下面是我使用正则表达式的尝试

System.Text.RegularExpressions.Regex.Replace(value, "[A-Z]", " $0")

当前回答

在小写字母、大写字母或数字后添加空格的简单方法。

    string AddSpacesToSentence(string value, bool spaceLowerChar = true, bool spaceDigitChar = true, bool spaceSymbolChar = false)
    {
        var result = "";

        for (int i = 0; i < value.Length; i++)
        {
            char currentChar = value[i];
            char nextChar = value[i < value.Length - 1 ? i + 1 : value.Length - 1];

            if (spaceLowerChar && char.IsLower(currentChar) && !char.IsLower(nextChar))
            {
                result += value[i] + " ";
            }
            else if (spaceDigitChar && char.IsDigit(currentChar) && !char.IsDigit(nextChar))
            {
                result += value[i] + " ";
            }
            else if(spaceSymbolChar && char.IsSymbol(currentChar) && !char.IsSymbol(nextChar))
            {
                result += value[i];
            }
            else
            {
                result += value[i];
            }
        }

        return result;
    }

其他回答

在小写字母、大写字母或数字后添加空格的简单方法。

    string AddSpacesToSentence(string value, bool spaceLowerChar = true, bool spaceDigitChar = true, bool spaceSymbolChar = false)
    {
        var result = "";

        for (int i = 0; i < value.Length; i++)
        {
            char currentChar = value[i];
            char nextChar = value[i < value.Length - 1 ? i + 1 : value.Length - 1];

            if (spaceLowerChar && char.IsLower(currentChar) && !char.IsLower(nextChar))
            {
                result += value[i] + " ";
            }
            else if (spaceDigitChar && char.IsDigit(currentChar) && !char.IsDigit(nextChar))
            {
                result += value[i] + " ";
            }
            else if(spaceSymbolChar && char.IsSymbol(currentChar) && !char.IsSymbol(nextChar))
            {
                result += value[i];
            }
            else
            {
                result += value[i];
            }
        }

        return result;
    }
    private string GetProperName(string Header)
    {
        if (Header.ToCharArray().Where(c => Char.IsUpper(c)).Count() == 1)
        {
            return Header;
        }
        else
        {
            string ReturnHeader = Header[0].ToString();
            for(int i=1; i<Header.Length;i++)
            {
                if (char.IsLower(Header[i-1]) && char.IsUpper(Header[i]))
                {
                    ReturnHeader += " " + Header[i].ToString();
                }
                else
                {
                    ReturnHeader += Header[i].ToString();
                }
            }

            return ReturnHeader;
        }

        return Header;
    }

这个正则表达式在每个大写字母前放置一个空格字符:

using System.Text.RegularExpressions;

const string myStringWithoutSpaces = "ThisIsAStringWithoutSpaces";
var myStringWithSpaces = Regex.Replace(myStringWithoutSpaces, "([A-Z])([a-z]*)", " $1$2");

注意前面的空间,如果“$1$2”,这是可以完成的。

结果如下:

"This Is A String Without Spaces"

我开始做一个简单的扩展方法,基于二进制Worrier的代码,它将正确地处理首字母缩略词,并且是可重复的(不会破坏已经间隔的单词)。这是我的结果。

public static string UnPascalCase(this string text)
{
    if (string.IsNullOrWhiteSpace(text))
        return "";
    var newText = new StringBuilder(text.Length * 2);
    newText.Append(text[0]);
    for (int i = 1; i < text.Length; i++)
    {
        var currentUpper = char.IsUpper(text[i]);
        var prevUpper = char.IsUpper(text[i - 1]);
        var nextUpper = (text.Length > i + 1) ? char.IsUpper(text[i + 1]) || char.IsWhiteSpace(text[i + 1]): prevUpper;
        var spaceExists = char.IsWhiteSpace(text[i - 1]);
        if (currentUpper && !spaceExists && (!nextUpper || !prevUpper))
                newText.Append(' ');
        newText.Append(text[i]);
    }
    return newText.ToString();
}

下面是这个函数通过的单元测试用例。我把他建议的大部分案例都加到了这个清单上。其中三个没有通过的(两个只是罗马数字)被注释掉了:

Assert.AreEqual("For You And I", "ForYouAndI".UnPascalCase());
Assert.AreEqual("For You And The FBI", "ForYouAndTheFBI".UnPascalCase());
Assert.AreEqual("A Man A Plan A Canal Panama", "AManAPlanACanalPanama".UnPascalCase());
Assert.AreEqual("DNS Server", "DNSServer".UnPascalCase());
Assert.AreEqual("For You And I", "For You And I".UnPascalCase());
Assert.AreEqual("Mount Mᶜ Kinley National Park", "MountMᶜKinleyNationalPark".UnPascalCase());
Assert.AreEqual("El Álamo Tejano", "ElÁlamoTejano".UnPascalCase());
Assert.AreEqual("The Ævar Arnfjörð Bjarmason", "TheÆvarArnfjörðBjarmason".UnPascalCase());
Assert.AreEqual("Il Caffè Macchiato", "IlCaffèMacchiato".UnPascalCase());
//Assert.AreEqual("Mister Dženan Ljubović", "MisterDženanLjubović".UnPascalCase());
//Assert.AreEqual("Ole King Henry Ⅷ", "OleKingHenryⅧ".UnPascalCase());
//Assert.AreEqual("Carlos Ⅴº El Emperador", "CarlosⅤºElEmperador".UnPascalCase());
Assert.AreEqual("For You And The FBI", "For You And The FBI".UnPascalCase());
Assert.AreEqual("A Man A Plan A Canal Panama", "A Man A Plan A Canal Panama".UnPascalCase());
Assert.AreEqual("DNS Server", "DNS Server".UnPascalCase());
Assert.AreEqual("Mount Mᶜ Kinley National Park", "Mount Mᶜ Kinley National Park".UnPascalCase());

受到二元忧虑者答案的启发,我尝试了一下。

结果如下:

/// <summary>
/// String Extension Method
/// Adds white space to strings based on Upper Case Letters
/// </summary>
/// <example>
/// strIn => "HateJPMorgan"
/// preserveAcronyms false => "Hate JP Morgan"
/// preserveAcronyms true => "Hate JPMorgan"
/// </example>
/// <param name="strIn">to evaluate</param>
/// <param name="preserveAcronyms" >determines saving acronyms (Optional => false) </param>
public static string AddSpaces(this string strIn, bool preserveAcronyms = false)
{
    if (string.IsNullOrWhiteSpace(strIn))
        return String.Empty;

    var stringBuilder = new StringBuilder(strIn.Length * 2)
        .Append(strIn[0]);

    int i;

    for (i = 1; i < strIn.Length - 1; i++)
    {
        var c = strIn[i];

        if (Char.IsUpper(c) && (Char.IsLower(strIn[i - 1]) || (preserveAcronyms && Char.IsLower(strIn[i + 1]))))
            stringBuilder.Append(' ');

        stringBuilder.Append(c);
    }

    return stringBuilder.Append(strIn[i]).ToString();
}

测试使用秒表运行10000000次迭代和各种字符串长度和组合。

平均比二进制忧虑者的答案快50%(可能多一点)。