目前的文档只讨论了获取路由参数,而不是实际的路由段。

例如,如果我想找到当前路由的父,这是怎么可能的?


当前回答

import { Router, NavigationEnd } from "@angular/router";

constructor(private router: Router) {
  // Detect current route
  router.events.subscribe(val => {
    if (val instanceof NavigationEnd) {
      console.log(val.url);
    }
  });
}

其他回答

router.events。订阅(e => { if (e instanceof NavigationEnd) { 这一点。currentUrl = e.url; } });

给那些还在寻找这个的人。在Angular 2上。有几种方法。

constructor(private router: Router, private activatedRoute: ActivatedRoute){

   // string path from root to current route. i.e /Root/CurrentRoute
   router.url 

    // just the fragment of the current route. i.e. CurrentRoute
   activatedRoute.url.value[0].path

    // same as above with urlSegment[]
   activatedRoute.url.subscribe((url: urlSegment[])=> console.log(url[0].path))

   // same as above
   activatedRoute.snapshot.url[0].path

   // the url fragment from the parent route i.e. Root
   // since the parent is an ActivatedRoute object, you can get the same using 
   activatedRoute.parent.url.value[0].path
}

引用:

https://angular.io/docs/ts/latest/api/router/index/ActivatedRoute-interface.html https://angular.io/docs/ts/latest/api/router/index/Router-class.html https://angular.io/docs/ts/latest/guide/router.html

在Angular 14中,如果你这样做

this.router.url

它总是会返回'/'

您可以使用Location服务(https://angular.io/api/common/Location)及其方法“path”来获得URL,而不是使用Router(在导航生命周期中可能还没有最终路由)。这是一个比“window.location”更好的选择。pathname,”它不会感知Angular,并且会在路径中包含基本的href。

import { Location } from '@angular/common';

constructor(private location: Location) { }

ngOnInit(): void {
    console.log(this.location.path());  // returns path

}

获取路由段:

import { ActivatedRoute, UrlSegment } from '@angular/router';

constructor( route: ActivatedRoute) {}

getRoutes() { const segments: UrlSegment[] = this.route.snapshot.url; }

对我来说,在AuthGuardService实现CanActivate访问当前路由时,接受的答案不工作,因为路由还没有完全处理。我在这里回答了同样的问题(https://stackoverflow.com/a/68541653/1479486),但如果你只是想从这里复制粘贴,这是我的解决方案:

const finalUrl = this.router.getCurrentNavigation()?.finalUrl;   
const isLoginPage = finalUrl?.root.children['primary'].segments[0]?.path === 'login';