如果需要精确计算SSMS中“表财产-存储”页面上的相同数字，则需要使用与SSMS中相同的方法进行计数（适用于sql server 2005及更高版本……也适用于具有LOB字段的表，因为仅计算“used_pages”不足以显示准确的索引大小）：

;with cte as (
SELECT
t.name as TableName,
SUM (s.used_page_count) as used_pages_count,
SUM (CASE
            WHEN (i.index_id < 2) THEN (in_row_data_page_count + lob_used_page_count + row_overflow_used_page_count)
            ELSE lob_used_page_count + row_overflow_used_page_count
        END) as pages
FROM sys.dm_db_partition_stats  AS s 
JOIN sys.tables AS t ON s.object_id = t.object_id
JOIN sys.indexes AS i ON i.[object_id] = t.[object_id] AND s.index_id = i.index_id
GROUP BY t.name
)
select
    cte.TableName, 
    cast((cte.pages * 8.)/1024 as decimal(10,3)) as TableSizeInMB, 
    cast(((CASE WHEN cte.used_pages_count > cte.pages 
                THEN cte.used_pages_count - cte.pages
                ELSE 0 
          END) * 8./1024) as decimal(10,3)) as IndexSizeInMB
from cte
order by 2 desc

对于Azure，我使用了：

您应该有SSMS v17.x+

我使用；

正如用户Sparrow所提到的：

打开数据库>并选择表，然后按F7键你应该看到行数作为：

此处的SSMS连接到Azure数据库

也许表格有更多的分区文件，必须显示文件顺序

SELECT
  T1.Name                                       AS TableName,
  T5.Name                                       AS SchemaName,
  T3.partition_number                           AS PartionNumber,   
  T3.Rows                                       AS RowsCount,
  SUM(T4.total_pages) * 8                       AS TotalSpaceKB,
  SUM(T4.used_pages) * 8                        AS UsedSpaceKB,
  (SUM(T4.total_pages) - SUM(T4.used_pages)) * 8 AS UnusedSpaceKB
FROM
  sys.objects T1  INNER JOIN 
  sys.indexes T2 ON T1.object_id = T2.object_id  INNER JOIN 
  sys.partitions T3 ON T2.object_id = T3.object_id AND T2.index_id = T3.index_id  INNER JOIN
  sys.allocation_units T4 ON T3.partition_id = T4.container_id LEFT JOIN
  sys.schemas T5 ON T1.schema_id = T5.schema_id
WHERE
  T1.type='U'
GROUP BY
  T1.Name, T5.Name, T3.Rows,T3.partition_number
ORDER BY
  T1.Name,T3.partition_number;

SELECT 
    t.NAME AS TableName,
    s.Name AS SchemaName,
    p.rows,
    SUM(a.total_pages) * 8 AS TotalSpaceKB, 
    CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
    SUM(a.used_pages) * 8 AS UsedSpaceKB, 
    CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB, 
    (SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
    CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM 
    sys.tables t
INNER JOIN      
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN 
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN 
    sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN 
    sys.schemas s ON t.schema_id = s.schema_id
WHERE 
    t.NAME NOT LIKE 'dt%' 
    AND t.is_ms_shipped = 0
    AND i.OBJECT_ID > 255 
GROUP BY 
    t.Name, s.Name, p.Rows
ORDER BY 
    TotalSpaceMB DESC, t.Name

经过一番搜索，我找不到一种简单的方法来获取所有表格的信息。有一个名为sp_spaceused的方便存储过程，它将返回数据库使用的所有空间。如果提供了表名，则返回该表使用的空间。但是，存储过程返回的结果不可排序，因为列是字符值。

以下脚本将生成我要查找的信息。

create table #TableSize (
    Name varchar(255),
    [rows] int,
    reserved varchar(255),
    data varchar(255),
    index_size varchar(255),
    unused varchar(255))
create table #ConvertedSizes (
    Name varchar(255),
    [rows] int,
    reservedKb int,
    dataKb int,
    reservedIndexSize int,
    reservedUnused int)

EXEC sp_MSforeachtable @command1="insert into #TableSize
EXEC sp_spaceused '?'"
insert into #ConvertedSizes (Name, [rows], reservedKb, dataKb, reservedIndexSize, reservedUnused)
select name, [rows], 
SUBSTRING(reserved, 0, LEN(reserved)-2), 
SUBSTRING(data, 0, LEN(data)-2), 
SUBSTRING(index_size, 0, LEN(index_size)-2), 
SUBSTRING(unused, 0, LEN(unused)-2)
from #TableSize

select * from #ConvertedSizes
order by reservedKb desc

drop table #TableSize
drop table #ConvertedSizes

 exec  sp_spaceused N'dbo.MyTable'

对于所有表，请使用。。（根据保罗的评论补充）

exec sp_MSForEachTable 'exec sp_spaceused [?]'