我有一个纯JavaScript承诺(内置实现或poly-fill):

var promise = new promise(函数(解析,拒绝){/*…* /});

从规范来看,Promise可以是:

" settle "和" resolved " “解决”和“拒绝” “等待”

我有一个用例,我希望同步审问承诺并确定:

承诺达成了吗? 如果是,承诺解决了吗?

我知道我可以使用#then()来安排在Promise改变状态后异步执行的工作。我不是在问你该怎么做。

这个问题是关于Promise状态的同步询问。我怎样才能做到这一点呢?


当前回答

This is older question but I was trying to do something similar. I need to keep n workers going. They are structured in a promise. I need to scan and see if they are resolved, rejected or still pending. If resolved, I need the value, if rejected do something to correct the issue or pending. If resolved or rejected I need to start another task to keep n going. I can't figure a way to do it with Promise.all or Promise.race as I keep working promises in an array and can find no way to delete them. So I create a worker that does the trick

我需要一个承诺生成器函数,返回一个承诺,根据需要解决或拒绝。它由一个函数调用,该函数设置框架以了解承诺在做什么。

在下面的代码中,生成器只是返回一个基于setTimeout的承诺。

在这里

//argObj should be of form
// {succeed: <true or false, nTimer: <desired time out>}
function promiseGenerator(argsObj) {
  let succeed = argsObj.succeed;          
  let nTimer = argsObj.nTimer;
  return new Promise((resolve, reject) => {
    setTimeout(() => {
      if (succeed) {
        resolve('ok');
      }
      else {
        reject(`fail`);
      }
    }, nTimer);
  })

}

function doWork(generatorargs) {
  let sp = { state: `pending`, value: ``, promise: "" };
  let p1 = promiseGenerator(generatorargs)
    .then((value) => {
      sp.state = "resolved";
      sp.value = value;
    })
    .catch((err) => {
      sp.state = "rejected";
      sp.value = err;
    })
  sp.promise = p1;
  return sp;
}

doWork返回一个包含promise及其状态和返回值的对象。

下面的代码运行一个循环,测试状态并创建新的工作线程以保持在3个正在运行的工作线程。

let promiseArray = [];

promiseArray.push(doWork({ succeed: true, nTimer: 1000 }));
promiseArray.push(doWork({ succeed: true, nTimer: 500 }));
promiseArray.push(doWork({ succeed: false, nTimer: 3000 }));

function loopTimerPromise(delay) {
  return new Promise((resolve, reject) => {
    setTimeout(() => {
      resolve('ok');
    }, delay)
  })
}

async function looper() {
  let nPromises = 3;      //just for breaking loop
  let nloop = 0;          //just for breaking loop
  let i;
  //let continueLoop = true;
  while (true) {
    await loopTimerPromise(900);  //execute loop every 900ms
    nloop++;
    //console.log(`promiseArray.length = ${promiseArray.length}`);
    for (i = promiseArray.length; i--; i > -1) {
      console.log(`index ${i} state: ${promiseArray[i].state}`);
      switch (promiseArray[i].state) {
        case "pending":
          break;
        case "resolved":
          nPromises++;
          promiseArray.splice(i, 1);
          promiseArray.push(doWork({ succeed: true, nTimer: 1000 }));
          break;
        case "rejected":
          //take recovery action
          nPromises++;
          promiseArray.splice(i, 1);
          promiseArray.push(doWork({ succeed: false, nTimer: 500 }));
          break;
        default:
          console.log(`error bad state in i=${i} state:${promiseArray[i].state} `)
          break;
      }
    }
    console.log(``);
    if (nloop > 10 || nPromises > 10) {
      //should do a Promise.all on remaining promises to clean them up but not for test
      break;
    }
  }
}

looper();

在node.js中测试

顺便说一句,不是在这个问题上,而是在其他类似的问题上,我讨厌有人说“你不明白”或“事情不是这样的”,我通常认为提问者知道他们想要什么。建议一个更好的方法是很好的。耐心地解释承诺如何起作用也会很好。

其他回答

警告:process.binding(“跑龙套”)。节点16上的getPromiseDetails未定义!

基准:

候选人:

/**
 * https://stackoverflow.com/a/47009572/5318303
 */
const isPromisePending1 = (() => { // noinspection JSUnresolvedFunction
    const util = process.binding('util')  // noinspection JSUnresolvedFunction
    return promise => !util.getPromiseDetails(promise)[0]
})()

/**
 * https://stackoverflow.com/a/35852666/5318303
 */
const isPromisePending2 = (promise) => util.inspect(promise) === 'Promise { <pending> }'

/**
 * https://stackoverflow.com/a/35820220/5318303
 */
const isPromisePending3 = (promise) => {
    const t = {}
    return Promise.race([promise, t])
            .then(v => v === t, () => false)
}

测试的承诺:

const a = Promise.resolve()
const b = Promise.reject()
const c = new Promise(() => {})
const x = (async () => 1)()

运行基准:

const n = 1000000

console.time('isPromisePending1')
for (let i = 0; i < n; i++) {
    isPromisePending1(a)
    isPromisePending1(b)
    isPromisePending1(c)
    isPromisePending1(x)
}
console.timeEnd('isPromisePending1')

console.time('isPromisePending2')
for (let i = 0; i < n; i++) {
    isPromisePending2(a)
    isPromisePending2(b)
    isPromisePending2(c)
    isPromisePending2(x)
}
console.timeEnd('isPromisePending2')

console.time('isPromisePending3')
for (let i = 0; i < n; i++) {
    await isPromisePending3(a)
    await isPromisePending3(b)
    await isPromisePending3(c)
    await isPromisePending3(x)
}
console.timeEnd('isPromisePending3')

结果:

isPromisePending1: 440.694ms
isPromisePending2: 3.354s
isPromisePending3: 4.761s

显然isPromisePending1()太快了(8~10倍)!但它在节点16上不可用!(见上述警告)。

更新:2019

Bluebird.js提供了这个:http://bluebirdjs.com/docs/api/isfulfilled.html

var Promise = require("bluebird");
let p = Promise.resolve();
console.log(p.isFulfilled());

如果您更喜欢创建自己的包装器,这里有一个关于它的不错的博客。

因为JavaScript是单线程的,所以很难找到一个足够常见的用例来证明将其放在规范中是正确的。知道承诺是否被解决的最佳位置是在.then()中。测试Promise是否被履行将创建一个轮询循环,这很可能是错误的方向。

如果你想同步推理异步代码,Async /await是一个很好的结构。

await this();
await that();
return 'success!';

另一个有用的调用是Promise.all()

var promise1 = Promise.resolve(3);
var promise2 = 42;
var promise3 = new Promise(function(resolve, reject) {
  setTimeout(resolve, 100, 'foo');
});

Promise.all([promise1, promise2, promise3]).then(function(values) {
  console.log(values);
});
// expected output: Array [3, 42, "foo"]

当我第一次得到这个答案时,这就是我正在寻找的用例。

我为此做了一个包裹。与这里的大多数其他答案不同,它不会接受未经处理的拒绝。

npm install p-state
import timers from 'timers/promises';
import {promiseStateSync} from 'p-state';

const timeoutPromise = timers.setTimeout(100);

console.log(promiseStateSync(timeoutPromise));
//=> 'pending'

await timeoutPromise;

console.log(promiseStateSync(timeoutPromise));
//=> 'fulfilled'

这一基本功能的缺失确实令人恼火。如果你正在使用node.js,那么我知道有两种变通方法,它们都不太漂亮。下面的两个代码段实现了相同的API:

> Promise.getInfo( 42 )                         // not a promise
{ status: 'fulfilled', value: 42 }
> Promise.getInfo( Promise.resolve(42) )        // fulfilled
{ status: 'fulfilled', value: 42 }
> Promise.getInfo( Promise.reject(42) )         // rejected
{ status: 'rejected', value: 42 }
> Promise.getInfo( p = new Promise(() => {}) )  // unresolved
{ status: 'pending' }
> Promise.getInfo( Promise.resolve(p) )         // resolved but pending
{ status: 'pending' }

用这两种方法似乎都无法区分最后两种承诺状态。

1. 使用V8调试API

这和util是一样的。检查使用。

const Debug = require('vm').runInDebugContext('Debug');

Promise.getInfo = function( arg ) {
    let mirror = Debug.MakeMirror( arg, true );
    if( ! mirror.isPromise() )
        return { status: 'fulfilled', value: arg };
    let status = mirror.status();
    if( status === 'pending' )
        return { status };
    if( status === 'resolved' )  // fix terminology fuck-up
        status = 'fulfilled';
    let value = mirror.promiseValue().value();
    return { status, value };
};

2. 同步运行微任务

这避免了调试API,但是会导致所有挂起的微任务和进程,从而产生一些可怕的语义。nextTick回调将同步运行。它还有一个副作用,就是防止被检查的承诺触发“未处理的承诺拒绝”错误。

Promise.getInfo = function( arg ) {
    const pending = {};
    let status, value;
    Promise.race([ arg, pending ]).then(
        x => { status = 'fulfilled'; value = x; },
        x => { status = 'rejected'; value = x; }
    );
    process._tickCallback();  // run microtasks right now
    if( value === pending )
        return { status: 'pending' };
    return { status, value };
};

不,没有同步API,但这是我的async承诺(在@Matthijs的帮助下):

函数promiseState(p) { Const t = {}; 回报的承诺。种族([p t]) .then(v => (v == t)?"pending": " completed ", () => "rejected"); } var a = Promise.resolve(); var b = Promise.reject(); var c = new Promise(() => {}); promiseState (a)。Then (state => console.log(state));/ /实现 promiseState (b)。Then (state => console.log(state));/ /拒绝 promiseState (c)。Then (state => console.log(state));/ /等待