我有一个纯JavaScript承诺(内置实现或poly-fill):

var promise = new promise(函数(解析,拒绝){/*…* /});

从规范来看,Promise可以是:

" settle "和" resolved " “解决”和“拒绝” “等待”

我有一个用例,我希望同步审问承诺并确定:

承诺达成了吗? 如果是,承诺解决了吗?

我知道我可以使用#then()来安排在Promise改变状态后异步执行的工作。我不是在问你该怎么做。

这个问题是关于Promise状态的同步询问。我怎样才能做到这一点呢?


当前回答

使用惯用的原型,等待@jib的答案的使用。

Object.defineProperty(Promise.prototype, "state", {
    get: function(){
        const o = {};
        return Promise.race([this, o]).then(
            v => v === o ? "pending" : "resolved",
            () => "rejected");
    }
});

// usage: console.log(await <Your Promise>.state);
(async () => {
    console.log(await Promise.resolve(2).state);  // "resolved"
    console.log(await Promise.reject(0).state);   // "rejected"
    console.log(await new Promise(()=>{}).state); // "pending"
})();

注意,这个异步函数像同步函数一样“几乎”立即执行(或者实际上可能立即执行)。

其他回答

使用惯用的原型,等待@jib的答案的使用。

Object.defineProperty(Promise.prototype, "state", {
    get: function(){
        const o = {};
        return Promise.race([this, o]).then(
            v => v === o ? "pending" : "resolved",
            () => "rejected");
    }
});

// usage: console.log(await <Your Promise>.state);
(async () => {
    console.log(await Promise.resolve(2).state);  // "resolved"
    console.log(await Promise.reject(0).state);   // "rejected"
    console.log(await new Promise(()=>{}).state); // "pending"
})();

注意,这个异步函数像同步函数一样“几乎”立即执行(或者实际上可能立即执行)。

你可以这样包装你的承诺

function wrapPromise(promise) {
  var value, error,
      settled = false,
      resolved = false,
      rejected = false,
      p = promise.then(function(v) {
        value = v;
        settled = true;
        resolved = true;
        return v;
      }, function(err) {
        error = err;
        settled = true;
        rejected = true;
        throw err;
      });
      p.isSettled = function() {
        return settled;
      };
      p.isResolved = function() {
        return resolved;
      };
      p.isRejected = function() {
        return rejected;
      };
      p.value = function() {
        return value;
      };
      p.error = function() {
        return error;
      };
      var pThen = p.then, pCatch = p.catch;
      p.then = function(res, rej) {
        return wrapPromise(pThen(res, rej));
      };
      p.catch = function(rej) {
        return wrapPromise(pCatch(rej));
      };
      return p;
}

注意:此方法使用未文档化的Node.js内部构件,可以在没有警告的情况下进行更改。

在Node中,你可以使用process.binding('util')来同步确定promise的状态。getPromiseDetails(/* promise */);

这将返回:

[0,]表示未决,

[1, /* value */]表示已实现,或

[2, /* value */]表示拒绝。

const pending = new Promise(resolve => setTimeout(() => resolve('yakko')));;
const fulfilled = Promise.resolve('wakko');
const rejected = Promise.reject('dot');

[pending, fulfilled, rejected].forEach(promise => {
  console.log(process.binding('util').getPromiseDetails(promise));
});

// pending:   [0, ]
// fulfilled: [1, 'wakko']
// rejected:  [2, 'dot']

将其包装到一个helper函数中:

const getStatus = promise => ['pending', 'fulfilled', 'rejected'][
  process.binding('util').getPromiseDetails(promise)[0]
];

getStatus(pending); // pending
getStatus(fulfilled); // fulfilled
getStatus(rejected); // rejected

如果你正在使用ES7实验版,你可以使用async轻松地包装你想要收听的承诺。

async function getClient() {
  let client, resolved = false;
  try {
    client = await new Promise((resolve, reject) => {
      let client = new Client();

      let timer = setTimeout(() => {
         reject(new Error(`timeout`, 1000));
         client.close();
      });

      client.on('ready', () => {
        if(!resolved) {
          clearTimeout(timer);
          resolve(client);
        }
      });

      client.on('error', (error) => {
        if(!resolved) {
          clearTimeout(timer);
          reject(error);
        }
      });

      client.on('close', (hadError) => {
        if(!resolved && !hadError) {
          clearTimeout(timer);
          reject(new Error("close"));
        }
      });
    });

    resolved = true;
  } catch(error) {
    resolved = true;
    throw error;
  }
  return client;
}

This is older question but I was trying to do something similar. I need to keep n workers going. They are structured in a promise. I need to scan and see if they are resolved, rejected or still pending. If resolved, I need the value, if rejected do something to correct the issue or pending. If resolved or rejected I need to start another task to keep n going. I can't figure a way to do it with Promise.all or Promise.race as I keep working promises in an array and can find no way to delete them. So I create a worker that does the trick

我需要一个承诺生成器函数,返回一个承诺,根据需要解决或拒绝。它由一个函数调用,该函数设置框架以了解承诺在做什么。

在下面的代码中,生成器只是返回一个基于setTimeout的承诺。

在这里

//argObj should be of form
// {succeed: <true or false, nTimer: <desired time out>}
function promiseGenerator(argsObj) {
  let succeed = argsObj.succeed;          
  let nTimer = argsObj.nTimer;
  return new Promise((resolve, reject) => {
    setTimeout(() => {
      if (succeed) {
        resolve('ok');
      }
      else {
        reject(`fail`);
      }
    }, nTimer);
  })

}

function doWork(generatorargs) {
  let sp = { state: `pending`, value: ``, promise: "" };
  let p1 = promiseGenerator(generatorargs)
    .then((value) => {
      sp.state = "resolved";
      sp.value = value;
    })
    .catch((err) => {
      sp.state = "rejected";
      sp.value = err;
    })
  sp.promise = p1;
  return sp;
}

doWork返回一个包含promise及其状态和返回值的对象。

下面的代码运行一个循环,测试状态并创建新的工作线程以保持在3个正在运行的工作线程。

let promiseArray = [];

promiseArray.push(doWork({ succeed: true, nTimer: 1000 }));
promiseArray.push(doWork({ succeed: true, nTimer: 500 }));
promiseArray.push(doWork({ succeed: false, nTimer: 3000 }));

function loopTimerPromise(delay) {
  return new Promise((resolve, reject) => {
    setTimeout(() => {
      resolve('ok');
    }, delay)
  })
}

async function looper() {
  let nPromises = 3;      //just for breaking loop
  let nloop = 0;          //just for breaking loop
  let i;
  //let continueLoop = true;
  while (true) {
    await loopTimerPromise(900);  //execute loop every 900ms
    nloop++;
    //console.log(`promiseArray.length = ${promiseArray.length}`);
    for (i = promiseArray.length; i--; i > -1) {
      console.log(`index ${i} state: ${promiseArray[i].state}`);
      switch (promiseArray[i].state) {
        case "pending":
          break;
        case "resolved":
          nPromises++;
          promiseArray.splice(i, 1);
          promiseArray.push(doWork({ succeed: true, nTimer: 1000 }));
          break;
        case "rejected":
          //take recovery action
          nPromises++;
          promiseArray.splice(i, 1);
          promiseArray.push(doWork({ succeed: false, nTimer: 500 }));
          break;
        default:
          console.log(`error bad state in i=${i} state:${promiseArray[i].state} `)
          break;
      }
    }
    console.log(``);
    if (nloop > 10 || nPromises > 10) {
      //should do a Promise.all on remaining promises to clean them up but not for test
      break;
    }
  }
}

looper();

在node.js中测试

顺便说一句,不是在这个问题上,而是在其他类似的问题上,我讨厌有人说“你不明白”或“事情不是这样的”,我通常认为提问者知道他们想要什么。建议一个更好的方法是很好的。耐心地解释承诺如何起作用也会很好。