使用这个

WITH tblTemp as
(
SELECT ROW_NUMBER() Over(PARTITION BY Name,Department ORDER BY Name)
   As RowNumber,* FROM <table_name>
)
DELETE FROM tblTemp where RowNumber >1

我更喜欢子查询\having count(*) > 1解决方案内部连接，因为我发现它更容易阅读，它很容易变成一个SELECT语句来验证什么将被删除，然后再运行它。

--DELETE FROM table1 
--WHERE id IN ( 
     SELECT MIN(id) FROM table1 
     GROUP BY col1, col2, col3 
     -- could add a WHERE clause here to further filter
     HAVING count(*) > 1
--)

我更喜欢CTE从sql server表中删除重复的行

强烈推荐阅读本文::http://codaffection.com/sql-server-article/delete-duplicate-rows-in-sql-server/

保持原创性

WITH CTE AS
(
SELECT *,ROW_NUMBER() OVER (PARTITION BY col1,col2,col3 ORDER BY col1,col2,col3) AS RN
FROM MyTable
)

DELETE FROM CTE WHERE RN<>1

不保留原创

WITH CTE AS
(SELECT *,R=RANK() OVER (ORDER BY col1,col2,col3)
FROM MyTable)
 
DELETE CTE
WHERE R IN (SELECT R FROM CTE GROUP BY R HAVING COUNT(*)>1)

下面的查询用于删除重复的行。本例中的表以ID作为标识列，具有重复数据的列是Column1、Column2和Column3。

DELETE FROM TableName
WHERE  ID NOT IN (SELECT MAX(ID)
                  FROM   TableName
                  GROUP  BY Column1,
                            Column2,
                            Column3
                  /*Even if ID is not null-able SQL Server treats MAX(ID) as potentially
                    nullable. Because of semantics of NOT IN (NULL) including the clause
                    below can simplify the plan*/
                  HAVING MAX(ID) IS NOT NULL) 

下面的脚本显示GROUP BY、HAVING、ORDER BY在一个查询中的用法，并返回带有重复列及其计数的结果。

SELECT YourColumnName,
       COUNT(*) TotalCount
FROM   YourTableName
GROUP  BY YourColumnName
HAVING COUNT(*) > 1
ORDER  BY COUNT(*) DESC 

如果重复行的所有列都是相同的，那么下面的查询可以用来删除重复的记录。

SELECT DISTINCT * INTO #TemNewTable FROM #OriginalTable
TRUNCATE TABLE #OriginalTable
INSERT INTO #OriginalTable SELECT * FROM #TemNewTable
DROP TABLE #TemNewTable

DELETE
FROM
    table_name T1
WHERE
    rowid > (
        SELECT
            min(rowid)
        FROM
            table_name T2
        WHERE
            T1.column_name = T2.column_name
    );