如何在以下列表中搜索包含字符串“abc”的项目?

xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']

以下检查“abc”是否在列表中,但未检测到“abc-123”和“abc-456”:

if 'abc' in xs:

当前回答

mylist=['abc','def','ghi','abc']

pattern=re.compile(r'abc') 

pattern.findall(mylist)

其他回答

my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']

for item in my_list:
    if (item.find('abc')) != -1:
        print ('Found at ', item)

只是抛出这个:如果你恰好需要匹配多个字符串,例如abc和def,你可以按如下方式组合两个理解:

matchers = ['abc','def']
matching = [s for s in my_list if any(xs in s for xs in matchers)]

输出:

['abc-123', 'def-456', 'abc-456']
x = 'aaa'
L = ['aaa-12', 'bbbaaa', 'cccaa']
res = [y for y in L if x in y]

如果要获取多个子字符串的数据列表

你可以这样改

some_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
# select element where "abc" or "ghi" is included
find_1 = "abc"
find_2 = "ghi"
result = [element for element in some_list if find_1 in element or find_2 in element] 
# Output ['abc-123', 'ghi-789', 'abc-456']

使用Pythons字符串类的__contains__()方法。:

a = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
for i in a:
    if i.__contains__("abc") :
        print(i, " is containing")