我得到ARC编译器的以下警告:
"performSelector may cause a leak because its selector is unknown".
这是我正在做的:
[_controller performSelector:NSSelectorFromString(@"someMethod")];
为什么我得到这个警告?我理解编译器不能检查选择器是否存在,但为什么会导致泄漏?我怎样才能改变我的代码,让我不再得到这个警告呢?
我得到ARC编译器的以下警告:
"performSelector may cause a leak because its selector is unknown".
这是我正在做的:
[_controller performSelector:NSSelectorFromString(@"someMethod")];
为什么我得到这个警告?我理解编译器不能检查选择器是否存在,但为什么会导致泄漏?我怎样才能改变我的代码,让我不再得到这个警告呢?
当前回答
奇怪但事实是:如果可以接受(即result为void并且你不介意让runloop循环一次),添加一个延迟,即使这是零:
[_controller performSelector:NSSelectorFromString(@"someMethod")
withObject:nil
afterDelay:0];
这删除了警告,大概是因为它向编译器保证没有对象可以返回,并且在某种程度上管理不当。
其他回答
我没有使用块方法,这给我带来了一些问题:
IMP imp = [_controller methodForSelector:selector];
void (*func)(id, SEL) = (void *)imp;
我将使用NSInvocation,像这样:
-(void) sendSelectorToDelegate:(SEL) selector withSender:(UIButton *)button
if ([delegate respondsToSelector:selector])
{
NSMethodSignature * methodSignature = [[delegate class]
instanceMethodSignatureForSelector:selector];
NSInvocation * delegateInvocation = [NSInvocation
invocationWithMethodSignature:methodSignature];
[delegateInvocation setSelector:selector];
[delegateInvocation setTarget:delegate];
// remember the first two parameter are cmd and self
[delegateInvocation setArgument:&button atIndex:2];
[delegateInvocation invoke];
}
在Xcode 4.2的LLVM 3.0编译器中,你可以像下面这样抑制警告:
#pragma clang diagnostic push
#pragma clang diagnostic ignored "-Warc-performSelector-leaks"
[self.ticketTarget performSelector: self.ticketAction withObject: self];
#pragma clang diagnostic pop
如果你在几个地方得到错误,并且想要使用C宏系统来隐藏指令,你可以定义一个宏来更容易地抑制警告:
#define SuppressPerformSelectorLeakWarning(Stuff) \
do { \
_Pragma("clang diagnostic push") \
_Pragma("clang diagnostic ignored \"-Warc-performSelector-leaks\"") \
Stuff; \
_Pragma("clang diagnostic pop") \
} while (0)
你可以像这样使用宏:
SuppressPerformSelectorLeakWarning(
[_target performSelector:_action withObject:self]
);
如果你需要执行消息的结果,你可以这样做:
id result;
SuppressPerformSelectorLeakWarning(
result = [_target performSelector:_action withObject:self]
);
不要压制警告!
有不少于12个可选的解决方案来修补编译器。 虽然在第一次实现时你很聪明,但地球上很少有工程师能追随你的脚步,而这段代码最终会崩溃。
安全的路线:
所有这些解决方案都是可行的,只是在一定程度上与您的初衷有所不同。假设param可以为nil:
安全路线,相同的概念行为:
// GREAT
[_controller performSelectorOnMainThread:selector withObject:anArgument waitUntilDone:YES];
[_controller performSelectorOnMainThread:selector withObject:anArgument waitUntilDone:YES modes:@[(__bridge NSString *)kCFRunLoopDefaultMode]];
[_controller performSelector:selector onThread:[NSThread mainThread] withObject:anArgument waitUntilDone:YES];
[_controller performSelector:selector onThread:[NSThread mainThread] withObject:anArgument waitUntilDone:YES modes:@[(__bridge NSString *)kCFRunLoopDefaultMode]];
安全路线,行为稍有不同:
(见此回复) 使用任何线程代替[NSThread主线程]。
// GOOD
[_controller performSelector:selector withObject:anArgument afterDelay:0];
[_controller performSelector:selector withObject:anArgument afterDelay:0 inModes:@[(__bridge NSString *)kCFRunLoopDefaultMode]];
[_controller performSelectorOnMainThread:selector withObject:anArgument waitUntilDone:NO];
[_controller performSelectorOnMainThread:selector withObject:anArgument waitUntilDone:NO];
[_controller performSelectorOnMainThread:selector withObject:anArgument waitUntilDone:NO modes:@[(__bridge NSString *)kCFRunLoopDefaultMode]];
[_controller performSelectorInBackground:selector withObject:anArgument];
[_controller performSelector:selector onThread:[NSThread mainThread] withObject:anArgument waitUntilDone:NO];
[_controller performSelector:selector onThread:[NSThread mainThread] withObject:anArgument waitUntilDone:NO modes:@[(__bridge NSString *)kCFRunLoopDefaultMode]];
危险的路线
需要某种编译器静音,这是必然的破坏。请注意,目前,它确实在Swift中中断了。
// AT YOUR OWN RISK
[_controller performSelector:selector];
[_controller performSelector:selector withObject:anArgument];
[_controller performSelector:selector withObject:anArgument withObject:nil];
Matt Galloway的回答解释了原因:
考虑以下几点: id anotherObject1 = [someObject performSelector:@selector(copy)]; id anotherObject2 = [someObject performSelector:@selector(giveMeAnotherNonRetainedObject)]; 现在,ARC如何知道第一个返回一个保留计数为1的对象,而第二个 返回一个自动释放的对象?
如果您忽略了返回值,那么抑制警告似乎通常是安全的。如果你真的需要从performSelector获取一个保留对象,我不确定最好的做法是什么——除了“不要这样做”。
@c-road在这里提供了正确的问题描述链接。下面您可以看到我的示例,当performSelector导致内存泄漏时。
@interface Dummy : NSObject <NSCopying>
@end
@implementation Dummy
- (id)copyWithZone:(NSZone *)zone {
return [[Dummy alloc] init];
}
- (id)clone {
return [[Dummy alloc] init];
}
@end
void CopyDummy(Dummy *dummy) {
__unused Dummy *dummyClone = [dummy copy];
}
void CloneDummy(Dummy *dummy) {
__unused Dummy *dummyClone = [dummy clone];
}
void CopyDummyWithLeak(Dummy *dummy, SEL copySelector) {
__unused Dummy *dummyClone = [dummy performSelector:copySelector];
}
void CloneDummyWithoutLeak(Dummy *dummy, SEL cloneSelector) {
__unused Dummy *dummyClone = [dummy performSelector:cloneSelector];
}
int main(int argc, const char * argv[]) {
@autoreleasepool {
Dummy *dummy = [[Dummy alloc] init];
for (;;) { @autoreleasepool {
//CopyDummy(dummy);
//CloneDummy(dummy);
//CloneDummyWithoutLeak(dummy, @selector(clone));
CopyDummyWithLeak(dummy, @selector(copy));
[NSThread sleepForTimeInterval:1];
}}
}
return 0;
}
在我的例子中,唯一导致内存泄漏的方法是CopyDummyWithLeak。原因是ARC不知道,copySelector返回retain object。
如果你运行内存泄漏工具,你可以看到下面的图片: ...在其他任何情况下都没有内存泄漏: