预期的输入:

getDatesFromRange( '2010-10-01', '2010-10-05' );

预期的输出:

Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )

当前回答

$report_starting_date=date('2014-09-16');
$report_ending_date=date('2014-09-26');
$report_starting_date1=date('Y-m-d',strtotime($report_starting_date.'-1 day'));
while (strtotime($report_starting_date1)<strtotime($report_ending_date))
{

    $report_starting_date1=date('Y-m-d',strtotime($report_starting_date1.'+1 day'));
    $dates[]=$report_starting_date1;
  } 
  print_r($dates);

 // dates    ('2014-09-16', '2014-09-26')


 //print result    Array
(
[0] => 2014-09-16
[1] => 2014-09-17
[2] => 2014-09-18
[3] => 2014-09-19
[4] => 2014-09-20
[5] => 2014-09-21
[6] => 2014-09-22
[7] => 2014-09-23
[8] => 2014-09-24
[9] => 2014-09-25
[10] => 2014-09-26
)

其他回答

<?
print_r(getDatesFromRange( '2010-10-01', '2010-10-05' ));

function getDatesFromRange($startDate, $endDate)
{
    $return = array($startDate);
    $start = $startDate;
    $i=1;
    if (strtotime($startDate) < strtotime($endDate))
    {
       while (strtotime($start) < strtotime($endDate))
        {
            $start = date('Y-m-d', strtotime($startDate.'+'.$i.' days'));
            $return[] = $start;
            $i++;
        }
    }

    return $return;
}

为了让穆斯塔法的回答更完整,这绝对是最简单和最有效的方法:

function getDatesFromRange($start_date, $end_date, $date_format = 'Y-m-d')
   {
      $dates_array = array();
      for ($x = strtotime($start_date); $x <= strtotime($end_date); $x += 86400) {
         array_push($dates_array, date($date_format, $x));
      }

      return $dates_array;
   }

   // see the dates in the array
   print_r( getDatesFromRange('2017-02-09', '2017-02-19') );

如果在调用函数时添加第三个参数,您甚至可以更改默认的输出日期格式,否则它将使用默认格式,即设置为'Y-m-d'。

我希望它能帮助你:)

下面是一个函数,它将从两个方向返回日期范围,适用于PHP >=5.2.2:

function createRange($start, $end, $format = 'Y-m-d') {
    $start  = new DateTime($start);
    $end    = new DateTime($end);
    $invert = $start > $end;

    $dates = array();
    $dates[] = $start->format($format);
    while ($start != $end) {
        $start->modify(($invert ? '-' : '+') . '1 day');
        $dates[] = $start->format($format);
    }
    return $dates;
}

使用的例子:

print_r(createRange('2010-10-01', '2010-10-05'));
/*Array
(
    [0] => 2010-10-01
    [1] => 2010-10-02
    [2] => 2010-10-03
    [3] => 2010-10-04
    [4] => 2010-10-05
)*/

print_r(createRange('2010-10-05', '2010-10-01', 'j M Y'));
/*Array
(
    [0] => 5 Oct 2010
    [1] => 4 Oct 2010
    [2] => 3 Oct 2010
    [3] => 2 Oct 2010
    [4] => 1 Oct 2010
)*/

demo

你必须添加$end->modify('+1 day')来包含间隔的最后一天,例如,如果不使用modify()方法,一月份将有31天而不是30天。 这个版本的代码将包括间隔的最后一天:

$begin = new DateTime( '2018-08-01' );
$end = new DateTime( '2018-08-31' );
$end = $end->modify( '+1 day' ); 

$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);

foreach($daterange as $date){
    echo $date->format("Ymd") . "<br>";
}

PHP文档链接

function datesbetween ($date1,$date2)
{
    $dates= array();
    for ($i = $date1
       ; $i<= $date1
       ; $i=date_add($i, date_interval_create_from_date_string('1 days')) ) 
    {            
       $dates[] = clone $i;
    }
    return $dates;
}