我一直在阅读c++常见问题,对朋友声明很好奇。我个人从未使用过它,但我对探索这门语言很感兴趣。
使用friend的一个好例子是什么?
读了一些常见问题,我喜欢<< >>操作符重载和添加作为这些类的朋友的想法。然而,我不确定这如何不会破坏封装。什么时候这些异常可以保持在OOP的严格范围内?
我一直在阅读c++常见问题,对朋友声明很好奇。我个人从未使用过它,但我对探索这门语言很感兴趣。
使用friend的一个好例子是什么?
读了一些常见问题,我喜欢<< >>操作符重载和添加作为这些类的朋友的想法。然而,我不确定这如何不会破坏封装。什么时候这些异常可以保持在OOP的严格范围内?
当前回答
In C++ "friend" keyword is useful in Operator overloading and Making Bridge. 1.) Friend keyword in operator overloading :Example for operator overloading is: Let say we have a class "Point" that has two float variable"x"(for x-coordinate) and "y"(for y-coordinate). Now we have to overload "<<"(extraction operator) such that if we call "cout << pointobj" then it will print x and y coordinate (where pointobj is an object of class Point). To do this we have two option: 1.Overload "operator <<()" function in "ostream" class. 2.Overload "operator<<()" function in "Point" class. Now First option is not good because if we need to overload again this operator for some different class then we have to again make change in "ostream" class. That's why second is best option. Now compiler can call "operator <<()" function:
1.Using ostream object cout.As: cout.operator<<(Pointobj) (form ostream class).
2.Call without an object.As: operator<<(cout, Pointobj) (from Point class).
Beacause we have implemented overloading in Point class. So to call this function without an object we have to add"friend" keyword because we can call a friend function without an object. Now function declaration will be As: "friend ostream &operator<<(ostream &cout, Point &pointobj);" 2.) Friend keyword in making bridge : Suppose we have to make a function in which we have to access private member of two or more classes ( generally termed as "bridge" ) . How to do this: To access private member of a class it should be member of that class. Now to access private member of other class every class should declare that function as a friend function. For example : Suppose there are two class A and B. A function "funcBridge()" want to access private member of both classes. Then both class should declare "funcBridge()" as: friend return_type funcBridge(A &a_obj, B & b_obj);I think this would help to understand friend keyword.
其他回答
在为类实现树算法时,教授给我们的框架代码将树类作为节点类的朋友。
它实际上没有任何好处,除了让你在不使用设置函数的情况下访问成员变量。
正如朋友声明的参考资料所说:
友元声明出现在类主体中,并授予函数或另一个类对出现友元声明的类的私有和受保护成员的访问权。
所以提醒一下,有些回答中有技术错误,说朋友只能访问受保护的成员。
这可能不是一个实际的用例情况,但可能有助于说明类间朋友关系的使用。
会所
class ClubHouse {
public:
friend class VIPMember; // VIP Members Have Full Access To Class
private:
unsigned nonMembers_;
unsigned paidMembers_;
unsigned vipMembers;
std::vector<Member> members_;
public:
ClubHouse() : nonMembers_(0), paidMembers_(0), vipMembers(0) {}
addMember( const Member& member ) { // ...code }
void updateMembership( unsigned memberID, Member::MembershipType type ) { // ...code }
Amenity getAmenity( unsigned memberID ) { // ...code }
protected:
void joinVIPEvent( unsigned memberID ) { // ...code }
}; // ClubHouse
会员班的
class Member {
public:
enum MemberShipType {
NON_MEMBER_PAID_EVENT, // Single Event Paid (At Door)
PAID_MEMBERSHIP, // Monthly - Yearly Subscription
VIP_MEMBERSHIP, // Highest Possible Membership
}; // MemberShipType
protected:
MemberShipType type_;
unsigned id_;
Amenity amenity_;
public:
Member( unsigned id, MemberShipType type ) : id_(id), type_(type) {}
virtual ~Member(){}
unsigned getId() const { return id_; }
MemberShipType getType() const { return type_; }
virtual void getAmenityFromClubHouse() = 0
};
class NonMember : public Member {
public:
explicit NonMember( unsigned id ) : Member( id, MemberShipType::NON_MEMBER_PAID_EVENT ) {}
void getAmenityFromClubHouse() override {
Amenity = ClubHouse::getAmenity( this->id_ );
}
};
class PaidMember : public Member {
public:
explicit PaidMember( unsigned id ) : Member( id, MemberShipType::PAID_MEMBERSHIP ) {}
void getAmenityFromClubHouse() override {
Amenity = ClubHouse::getAmenity( this->id_ );
}
};
class VIPMember : public Member {
public:
friend class ClubHouse;
public:
explicit VIPMember( unsigned id ) : Member( id, MemberShipType::VIP_MEMBERSHIP ) {}
void getAmenityFromClubHouse() override {
Amenity = ClubHouse::getAmenity( this->id_ );
}
void attendVIPEvent() {
ClubHouse::joinVIPEvent( this->id );
}
};
设施
class Amenity{};
如果你看看这些类之间的关系;会所拥有各种不同类型的会员资格和会员资格。成员都派生自超类或基类,因为它们都共享公共的ID和枚举类型,外部类可以通过基类中的访问函数访问它们的ID和类型。
然而,通过这种成员及其派生类的层次结构以及它们与ClubHouse类的关系,派生类中唯一具有“特殊特权”的是VIPMember类。基类和其他2个派生类不能访问ClubHouse的joinVIPEvent()方法,但VIP Member类拥有该特权,就好像它拥有对该事件的完全访问一样。
所以对于vip会员和ClubHouse,这是一个双向通道,而其他会员职业是有限的。
In C++ "friend" keyword is useful in Operator overloading and Making Bridge. 1.) Friend keyword in operator overloading :Example for operator overloading is: Let say we have a class "Point" that has two float variable"x"(for x-coordinate) and "y"(for y-coordinate). Now we have to overload "<<"(extraction operator) such that if we call "cout << pointobj" then it will print x and y coordinate (where pointobj is an object of class Point). To do this we have two option: 1.Overload "operator <<()" function in "ostream" class. 2.Overload "operator<<()" function in "Point" class. Now First option is not good because if we need to overload again this operator for some different class then we have to again make change in "ostream" class. That's why second is best option. Now compiler can call "operator <<()" function:
1.Using ostream object cout.As: cout.operator<<(Pointobj) (form ostream class).
2.Call without an object.As: operator<<(cout, Pointobj) (from Point class).
Beacause we have implemented overloading in Point class. So to call this function without an object we have to add"friend" keyword because we can call a friend function without an object. Now function declaration will be As: "friend ostream &operator<<(ostream &cout, Point &pointobj);" 2.) Friend keyword in making bridge : Suppose we have to make a function in which we have to access private member of two or more classes ( generally termed as "bridge" ) . How to do this: To access private member of a class it should be member of that class. Now to access private member of other class every class should declare that function as a friend function. For example : Suppose there are two class A and B. A function "funcBridge()" want to access private member of both classes. Then both class should declare "funcBridge()" as: friend return_type funcBridge(A &a_obj, B & b_obj);I think this would help to understand friend keyword.
首先(依我看)不要听那些说朋友没用的人。它是有用的。在许多情况下,您将拥有具有不打算公开可用的数据或功能的对象。对于许多作者可能只是表面上熟悉不同领域的大型代码库尤其如此。
友元说明符也有替代方案,但通常都很麻烦(cppp级别的具体类/掩码类型定义),或者不是万无一错(注释或函数名约定)。
在答案上;
友元说明符允许指定类访问发出友元语句的类内受保护的数据或功能。例如,在下面的代码中,任何人都可以询问孩子的名字,但只有母亲和孩子可以更改名字。
您可以通过考虑一个更复杂的类(如Window)来进一步考虑这个简单的示例。一个窗口很可能会有许多不应该被公开访问的函数/数据元素,但是被相关的类(如WindowManager)所需要。
class Child
{
//Mother class members can access the private parts of class Child.
friend class Mother;
public:
string name( void );
protected:
void setName( string newName );
};