为了扩展Lucero的回答，下面介绍如何在不丢失原始堆栈跟踪的情况下实现原始代码的意图。

public class Program {
    public static void Main(string[] args) {
        try {
            // something
        } catch (Exception ex) {
            if (!HandleException(ex)) throw;
        }
    }

    /// <returns>
    ///   true if the exception has been handled;
    ///   false if exception should be passed along
    /// </returns>
    private static bool HandleException(Exception ex) {
        if (ex is ThreadAbortException) {
            // ignore then,
            return true;
        }
        if (ex is ArgumentOutOfRangeException) { 
            // Log then,
            return false;
        }
        if (ex is InvalidOperationException) {
            // Show message then,
            return false;
        }
        // and so on.
    }
}

微软文档代表:

Once an exception is thrown, part of the information it carries is the stack trace. The stack trace is a list of the method call hierarchy that starts with the method that throws the exception and ends with the method that catches the exception. If an exception is re-thrown by specifying the exception in the throw statement, the stack trace is restarted at the current method and the list of method calls between the original method that threw the exception and the current method is lost. To keep the original stack trace information with the exception, use the throw statement without specifying the exception.

来源:https://learn.microsoft.com/en-us/dotnet/fundamentals/code-analysis/quality-rules/ca2200

int a = 0;
try {
    int x = 4;
    int y ;
    try {
        y = x / a;
    } catch (Exception e) {
        Console.WriteLine("inner ex");
        //throw;   // Line 1
        //throw e;   // Line 2
        //throw new Exception("devide by 0");  // Line 3
    }
} catch (Exception ex) {
    Console.WriteLine(ex);
    throw ex;
}

如果所有第1、2和3行都注释了- 输出-内ex 如果所有第2行和第3行都注释了- 输出-内ex 系统。DevideByZeroException:{"试图除零。"}--------- 如果所有第1行和第2行都注释了- 输出-内ex 系统。例外:除0 ---- 如果所有第1行和第3行都注释了- 输出-内ex 系统。DevideByZeroException:{"试图除零。"}---------

和StackTrace将重置的情况下抛出ex;

当你抛出ex时，抛出的异常就变成了“原始”异常。因此所有之前的堆栈跟踪都不会在那里。

如果你抛出了异常，异常就会沿着这一行进行，你会得到完整的堆栈跟踪。

不，这将导致异常具有不同的堆栈跟踪。只有在catch处理程序中使用不带任何异常对象的throw才会保持堆栈跟踪不变。

你可能想从HandleException返回一个布尔值，不管是否应该重新抛出异常。

为了扩展Lucero的回答，下面介绍如何在不丢失原始堆栈跟踪的情况下实现原始代码的意图。

public class Program {
    public static void Main(string[] args) {
        try {
            // something
        } catch (Exception ex) {
            if (!HandleException(ex)) throw;
        }
    }

    /// <returns>
    ///   true if the exception has been handled;
    ///   false if exception should be passed along
    /// </returns>
    private static bool HandleException(Exception ex) {
        if (ex is ThreadAbortException) {
            // ignore then,
            return true;
        }
        if (ex is ArgumentOutOfRangeException) { 
            // Log then,
            return false;
        }
        if (ex is InvalidOperationException) {
            // Show message then,
            return false;
        }
        // and so on.
    }
}