我一直在使用ES6 Promise。

通常,Promise是这样构造和使用的

new Promise(function(resolve, reject){
    if (someCondition){
        resolve();
    } else {
        reject();
    } 
});

但我一直在做下面这样的事情,为了灵活起见,把决心放在外面。

var outsideResolve;
var outsideReject;
new Promise(function(resolve, reject) { 
    outsideResolve = resolve; 
    outsideReject = reject; 
});

后来

onClick = function(){
    outsideResolve();
}

这很好,但是否有更简单的方法来做到这一点?如果不是,这是一个好的实践吗?


当前回答

helper方法可以减轻这种额外的开销,并给您同样的jQuery感觉。

function Deferred() {
    let resolve;
    let reject;
    const promise = new Promise((res, rej) => {
        resolve = res;
        reject = rej;
    });
    return { promise, resolve, reject };
}

用法是

const { promise, resolve, reject } = Deferred();
displayConfirmationDialog({
    confirm: resolve,
    cancel: reject
});
return promise;

它类似于jQuery

const dfd = $.Deferred();
displayConfirmationDialog({
    confirm: dfd.resolve,
    cancel: dfd.reject
});
return dfd.promise();

不过,在用例中,这种简单的本机语法就可以了

return new Promise((resolve, reject) => {
    displayConfirmationDialog({
        confirm: resolve,
        cancel: reject
    });
});

其他回答

我们的解决方案是使用闭包来存储解析/拒绝函数,并附加一个函数来扩展承诺本身。

模式如下:

function getPromise() {

    var _resolve, _reject;

    var promise = new Promise((resolve, reject) => {
        _reject = reject;
        _resolve = resolve;
    });

    promise.resolve_ex = (value) => {
       _resolve(value);
    };

    promise.reject_ex = (value) => {
       _reject(value);
    };

    return promise;
}

使用它:

var promise = getPromise();

promise.then(value => {
    console.info('The promise has been fulfilled: ' + value);
});

promise.resolve_ex('hello');  
// or the reject version 
//promise.reject_ex('goodbye');

类版本,在Typescript中:

export class Deferred<T> {
    public readonly promise: Promise<T>
    private resolveFn!: (value: T | PromiseLike<T>) => void
    private rejectFn!: (reason?: any) => void

    public constructor() {
        this.promise = new Promise<T>((resolve, reject) => {
            this.resolveFn = resolve
            this.rejectFn = reject
        })
    }

    public reject(reason?: any): void {
        this.rejectFn(reason)
    }

    public resolve(param: T): void {
        this.resolveFn(param)
    }
}

如何创建一个函数劫持拒绝并返回它?

function createRejectablePromise(handler) {
  let _reject;

  const promise = new Promise((resolve, reject) => {
    _reject = reject;

    handler(resolve, reject);
  })

  promise.reject = _reject;
  return promise;
}

// Usage
const { reject } = createRejectablePromise((resolve) => {
  setTimeout(() => {
    console.log('resolved')
    resolve();
  }, 2000)

});

reject();

感谢每个在这篇文章中发帖的人。我创建了一个模块,其中包括前面描述的Defer()对象以及在其上构建的其他一些对象。它们都利用Promise和简洁的Promise回调语法在程序中实现通信/事件处理。

延迟:可以远程解决失败的承诺(在承诺体之外) 延迟:在给定时间后自动解决的承诺 TimeOut:承诺在给定时间后自动失败。 循环:使用promise语法管理事件的可重新触发承诺 队列:基于承诺链的执行队列。

Rp = require("openpromise")

https://github.com/CABrouwers/openpromise https://www.npmjs.com/package/openpromise

以防有人来找简化这个任务的util的typescript版本:

export const deferred = <T>() => {
  let resolve!: (value: T | PromiseLike<T>) => void;
  let reject!: (reason?: any) => void;
  const promise = new Promise<T>((res, rej) => {
    resolve = res;
    reject = rej;
  });

  return {
    resolve,
    reject,
    promise,
  };
};

这可以用在。如:

const {promise, resolve} = deferred<string>();

promise.then((value) => console.log(value)); // nothing

resolve('foo'); // console.log: foo