我想做一个小绘画应用程序使用画布。所以我需要找到鼠标在画布上的位置。


当前回答

基于@Spider的解决方案,我的非JQuery版本是这样的:

// Get the container element's bounding box
var sides = document.getElementById("container").getBoundingClientRect();

// Apply the mouse event listener
document.getElementById("canvas").onmousemove = (e) => {
  // Here 'self' is simply the current window's context
  var x = (e.clientX - sides.left) + self.pageXOffset;
  var y = (e.clientY - sides.top) + self.pageYOffset;
}

这适用于滚动和缩放(在这种情况下,有时它返回浮动)。

其他回答

摘自本教程,感谢上面的评论做了更正:

function getMousePos( canvas, evt ) {
    var rect = canvas.getBoundingClientRect();
    return {
        x: Math.floor( ( evt.clientX - rect.left ) / ( rect.right - rect.left ) * canvas.width ),
        y: Math.floor( ( evt.clientY - rect.top ) / ( rect.bottom - rect.top ) * canvas.height )
    };
}

在画布上使用如下:

var canvas = document.getElementById( 'myCanvas' );
canvas.addEventListener( 'mousemove', function( evt ) {
    var mousePos = getMousePos( canvas, evt );
} );
canvas.onmousedown = function(e) {
    pos_left = e.pageX - e.currentTarget.offsetLeft;
    pos_top = e.pageY - e.currentTarget.offsetTop;
    console.log(pos_left, pos_top)
}

HTMLElement.offsetLeft

HTMLElement。offsetLeft read-only属性返回当前元素的左上角在HTMLElement中向左偏移的像素数。offsetParent节点。

对于块级元素,offsetTop, offsetLeft, offsetWidth和offsetHeight描述了一个元素相对于offsetParent的边界框。

However, for inline-level elements (such as span) that can wrap from one line to the next, offsetTop and offsetLeft describe the positions of the first border box (use Element.getClientRects() to get its width and height), while offsetWidth and offsetHeight describe the dimensions of the bounding border box (use Element.getBoundingClientRect() to get its position). Therefore, a box with the left, top, width and height of offsetLeft, offsetTop, offsetWidth and offsetHeight will not be a bounding box for a span with wrapped text.

HTMLElement.offsetTop

HTMLElement。offsetTop只读属性返回当前元素相对于offsetParent节点顶部的距离。

MouseEvent.pageX

pageX只读属性返回事件相对于整个文档的X(水平)坐标(像素)。此属性考虑页面的任何水平滚动。

MouseEvent.pageY

鼠标事件。pageY只读属性返回事件相对于整个文档的Y(垂直)像素坐标。此属性考虑页面的任何垂直滚动。

如需进一步解释,请参阅Mozilla开发者网络:

https://developer.mozilla.org/en-US/docs/Web/API/MouseEvent/pageX https://developer.mozilla.org/en-US/docs/Web/API/MouseEvent/pageY https://developer.mozilla.org/en-US/docs/Web/API/HTMLElement/offsetLeft https://developer.mozilla.org/en-US/docs/Web/API/HTMLElement/offsetTop

基于@Spider的解决方案,我的非JQuery版本是这样的:

// Get the container element's bounding box
var sides = document.getElementById("container").getBoundingClientRect();

// Apply the mouse event listener
document.getElementById("canvas").onmousemove = (e) => {
  // Here 'self' is simply the current window's context
  var x = (e.clientX - sides.left) + self.pageXOffset;
  var y = (e.clientY - sides.top) + self.pageYOffset;
}

这适用于滚动和缩放(在这种情况下,有时它返回浮动)。

你可以买到它

var element = document.getElementById(canvasId);
element.onmousemove = function(e) {
    var xCoor = e.clientX;
    var yCoor = e.clientY;
}

这是我得到的。

    $(".some-class").click(function(e) {

    var posx = 0;
    var posy = 0;

    posx = e.pageX;
    posy = e.pageY;

    alert(posx);
    alert(posy);
});